Simulink model 'to workspace' output - matlab

Question

I am trying to control motor torque and am using a workspace variable in Simulink and want to output similar variable to workspace.
I have size(T_u)=[3, 91] whereas the output I am getting from the simulation has size [91, 90]
I am unable to understand why this is so.
Code that I am using:
load('Motor_Param.mat')
t = 1:0.1:10;
T_o = [0.05*(10-t);0.04*(10-t);0.03*(10-t)];
T_d = zeros(size(T_o));
T_e = (T_d - T_o);
C_PD = pid(100,0,10,100);
T_u = zeros(size(T_e));
for k=1:size(T_e,1)
T_u(k,:) = lsim(C_PD,T_e(k,:),t);
%T_u(1,:)= -45.0450000000000 -44.5444552724092 -44.0439110892737 -43.5433674500493 -43.0428243541925 -42.5422818011600 -42.0417397904094 -41.5411983213986 -41.0406573935862 -40.5401170064312 -40.0395771593933 -39.5390378519326 -39.0384990835098 -38.5379608535861 -38.0374231616233 -37.5368860070837 -37.0363493894301 -36.5358133081260 -36.0352777626353 -35.5347427524223 -35.0342082769522 -34.5336743356904 -34.0331409281029 -33.5326080536564 -33.0320757118181 -32.5315439020554 -32.0310126238368 -31.5304818766308 -31.0299516599067 -30.5294219731343 -30.0288928157839 -29.5283641873264 -29.0278360872332 -28.5273085149760 -28.0267814700274 -27.5262549518604 -27.0257289599483 -26.5252034937652 -26.0246785527857 -25.5241541364848 -25.0236302443380 -24.5231068758215 -24.0225840304120 -23.5220617075865 -23.0215399068228 -22.5210186275990 -22.0204978693939 -21.5199776316868 -21.0194579139572 -20.5189387156857 -20.0184200363529 -19.5179018754402 -19.0173842324294 -18.5168671068029 -18.0163504980435 -17.5158344056347 -17.0153188290603 -16.5148037678048 -16.0142892213531 -15.5137751891906 -15.0132616708034 -14.5127486656779 -14.0122361733011 -13.5117241931606 -13.0112127247442 -12.5107017675407 -12.0101913210389 -11.5096813847285 -11.0091719580996 -10.5086630406426 -10.0081546318487 -9.50764673120954 -9.00713933821711 -8.50663245236405 -8.00612607314350 -7.50562020004906 -7.00511483257487 -6.50460997021554 -6.00410561246623 -5.50360175882257 -5.00309840878072 -4.50259556183731 -4.00209321748951 -3.50159137523496 -3.00109003457184 -2.50058919499879 -2.00008885601498 -1.49958901712007 -0.999089677814209 -0.498590837598075 0.00190750402718064
a = sim('Motor_Control','SimulationMode','normal');
out = a.get('T_l')
end
Link to .mat and .slx files is: https://drive.google.com/open?id=1kGeA4Cmt8mEeM3ku_C4NtXclVlHsssuw

Answer 1

If you set the Save format in the To Workspace block to Timeseries the output will have the dimensions of the signal times the number of timesteps.
In your case I activated the option Display->Signals & Ports->Signal dimensions and the signal dimensions in your model look like this:
So the signal that you output to the workspace has the size 90. Now if I print size(out.Data) I get
ans = 138 90
where 90 is the signal dimension and 138 is the number of timesteps in your Simulink model.
You could now use the last row of the data (which has the length 90) and add it to your array.

Answer 2

I edit your code, the code has [21,3] output size. "21" is coming from (t_final*1/sample_time+1)
In your code, time t should start from 0.
Motor_Control.slx model has 0.1 sample time if you run the model for a 9 second, the output file has 91 samples for each signal and that's why you have [91, 90] sized output. I download from your drive link and this Simulink model has 2 sec. simulation.
T_u is used as an input of the Simulink model, it is not constant so T_u must be time series.
The edited code is below;
load('Motor_Param.mat')
t = 0:0.1:10;
T_o = [0.05*(10-t);0.04*(10-t);0.03*(10-t)];
T_d = zeros(size(T_o));
T_e = (T_d - T_o);
C_PD = pid(100,0,10,100);
T_u = timeseries(zeros(size(T_e)),t);
for k=1:size(T_e,1)
T_u.Data(k,:) = lsim(C_PD,T_e(k,:),t);
a = sim('Motor_Control','SimulationMode','normal');
out = a.get('T_l')
end