How create multidimensional dynamic array in powershell - powershell

Question

How i can create array like:
$a -> [1] ->
[1] = value1
[2] = value2
.................
[n] = valueN
[2] ->
[1] = value1
[2] = value2
.................
[n] = valueN
and so on.
Thank you
i have tried like this:
$b = #{}
$b[0][0] = 1
$b[0][1] = 2
$b[0][2] = 3
$b[1][0] = 4
$b[1][1] = 5
$b[1][2] = 6
$b
But it doesn't give the required output

Answer 1

I think this has been posted multiple times, but simply declare the array and give it values:
[array]$1 = "value1","value2"
[array]$2 = "value1","value2"
[array]$a = $1,$2
$a[0][0]
will output -> value1 from the first
Please note that declaring the array with [array] is for clarifiying, it is not necessary. If you add comma-seperated values the variable automatically is an array.
EDIT:
What you have tried is a hashtable. A hashtable contains a key and a value. An array is only a list of values. A hashtable is created as follows:
$b = #{
1 = #{
1 = "value1"
2 = "value2"
}
2 = #{
1 = "value1"
2 = "value2"
}
3 = "value3"
}
$b
As you can see, you can add as many sublevels as you like. To show the value of the first "value1" type:
$b[1].1

Answer 2

You could use the class approach as well I would prefer:
Add-Type -AssemblyName System.Collections
# Create class with needed members
class myListObject {
[int]$myIndex
[System.Collections.Generic.List[string]]$myValue = #()
}
# generic list of class
[System.Collections.Generic.List[myListObject]]$myList = #()
#create and add objects to generic list
$myObject = [myListObject]::new()
$myObject.myIndex = 1
$myObject.myValue = #( 'value1', 'value2' )
$myList.Add( $myObject )
$myObject = [myListObject]::new()
$myObject.myIndex = 2
$myObject.myValue = #( 'value3', 'value4' )
$myList.Add( $myObject )
# search items
$myList | Where-Object { $_.myIndex -eq 1 } | Select-Object -Property myValue
$myList | Where-Object { $_.myValue.Contains('value3') } | Select-Object -Property myIndex

Answer 3

The Windows Powershell in Action answer.
$2d = New-Object -TypeName 'object[,]' -ArgumentList 2,2
$2d.Rank
#2
$2d[0,0] = "a"
$2d[1,0] = 'b'
$2d[0,1] = 'c'
$2d[1,1] = 'd'
$2d[1,1]
#d
# slice
$2d[ (0,0) , (1,0) ]
#a
#b
# index variable
$one = 0,0
$two = 1,0
$pair = $one,$two
$2d[ $pair ]
#a
#b