I'm using sublime to write my first Scala program, and I'm using terminal to run it.
First I use scalac assignment2.scala command to compile it, but it show error message:"error: object apache is not a member of package org"
How can I do to fix it?
This is my code:
import org.apache.spark.SparkConf
import org.apache.spark.SparkContext
import org.apache.spark.SparkContext._
object assignment2 {
def main(args: Array[String]) {
val conf = new SparkConf().setAppName("assignment2")
val sc = new SparkContext(conf)
val input = sc.parallelize(List(1, 2, 3, 4))
val result = input.map(x => x * x)
println(result.collect().mkString(","))
}
}
Where are you trying to submit the job. To run any spark application you need to submit it from bin/spark-submit in your spark installation directory or you need to have spark-home set in your environment, which you can refer while submitting.
Actually you can't run spark-scala file directly because for compilation your scala class, you need spark library. So for executing scala file you required spark-shell. For executing your spark scala file inside spark-shell, please find the below steps:
Open your spark-shell using next command-
'spark-shell --master yarn-client'
load your file with exact location-
':load File_Name_With_Absoulte_path'
Run you main method using class name- 'ClassName.main(null)'
Related
I'm running Scala code on Azure databricks well. Now I want to move this code from Azure notebook to eclipse.
I install databricks connection following Microsoft document successfully. Pass databricks data connection test.
I also installed SBT and import to my project in eclipse
I create scala object in eclipse and also I import all jar files as external file in pyspark
package Student
import org.apache.spark.sql.DataFrame
import org.apache.spark.sql.SparkSession
import java.util.Properties
//import com.databricks.dbutils_v1.DBUtilsHolder.dbutils
object Test {
def isTypeSame(df: DataFrame, name: String, coltype: String) = (df.schema(name).dataType.toString == coltype)
def main(args: Array[String]){
var Result = true
val Borrowers = List(("col1", "StringType"),("col2", "StringType"),("col3", "DecimalType(38,18)"))
val dfPcllcus22 = spark.read.format("parquet").load("/mnt/slraw/ServiceCenter=*******.parquet")
if (Result == false) println("Test Fail, Please check") else println("Test Pass")
}
}
When I run this code in eclipse, it shows cannot find main class. But if I comment "val dfPcllcus22 = spark.read.format("parquet").load("/mnt/slraw/ServiceCenter=*******.parquet")", pass the test.
So it seems spark.read.format cannot be recognized.
I'm new to Scala and DataBricks.
I was researching result for several days but still cannot solve it.
If anyone can help, really appreciate.
Environment is a bit complicated to me, if more information required, please let me know
SparkSession is needed to run your code in eclipse, since your provided code does not have this line for SparkSession creation leads to an error,
val spark = SparkSession.builder.appName("SparkDBFSParquet").master("local[*]".getOrCreate()
Please add this line and run the code and it should work.
I would like to run a scala code on Zeppelin from Spark cluster.
For example:
This is code into hdfs Spark "HelloWorldScala.scala":
object HelloWorldScala{
def main (arg: Array[String]): Unit = {
val conf = new SparkConf().setAppName("myApp_Enrico")
val spark = SparkSession.builder.config(conf).getOrCreate()
val aList = List(1,2,3,4,5,6,7,8,9,10)
val aRdd = spark.sparkContext.parallelize(aList)
println("********* HELLO WORLD AND HELLO SPARK!! ******")
println("Print even numbers")
aRdd.filter(x=>x%2==0).map(x=>x*2).collect().foreach(println)
}
}
I would like to import in Zeppelin the HelloWorldScala file and run main, but I see the error:
Error code Zeppelin
Unfortunately you can't import single file in Zeppelin. You can pack your scala files into .jar library and put it to spark.jars (setted as property in spark) directory, after you will can import your library using line: import your.libray.packages.YourClass and using non-private functions from it. If you don't know about jar packages, and spark.jar directories just read a bit more about that.
UPDATE:
%dep
z.load("your_package_group:artifact:version")
%spark
import com.yourpackage.HelloWorldScala
I'm very new to both Scala and Spark. I added the Scala IDE to Eclipse Luna. I created a maven project in the eclipse. I was to run the program within the eclipse with run as configuration option and able to get the output successfully. But when i create the jar for the following program and tried to run the spark shell am getting the following error.
error: ';' expected but 'class' found.
Command use to run the jar
spark-submit --class com.kirthi.spark.proj.sparkexamples.WordsCount --master local /home/cloudera/workspace/sparkwc1.jar hdfs://localhost:8020/kirthi3/dataset.txt hdfs://localhost:8020/kirthi3/sparkwco
The word count program which i tried
package com.kirthi.spark.proj.sparkexamples
import org.apache.spark.SparkConf
import org.apache.spark.SparkContext
import org.apache.spark.SparkContext._
object WordsCount {
def main(args: Array[String]){
val conf = new SparkConf()
.setAppName("Word Count")
.setMaster("local")
val sc = new SparkContext(conf)
val textFile = sc.textFile(args(0))
val words = textFile.flatMap(line => line.split(","))
val counts = words.map(word => (word,1))
val wordcount = counts.reduceByKey(_+_)
val wordcount_sorted = wordcount.sortByKey()
wordcount_sorted.foreach(println)
wordcount_sorted.saveAsTextFile(args(1))
}
}
Kindly help me out in this as I am struck with initial program for spark.
I am using cloudera quickstart CDH 5.5
As shown in the comments, you ran the above command in the Scala REPL, and which you should run it from a regular linux shell.
I have to run a simple wordcount on a cluster Hdinsight in Azure. I have created a cluster with hadoop and spark and i have already the jar file with the code, the problem that i don't know how to set-up the cluster and the right line of code to launch spark on Azure,I want to try different combination of nodes(workers , 2-4-8) to see how the program scale.
Every time i launch the app with spark-submit in mode yarn-client, it work but always with 2 executor and 1 core taking for 1gb input text file around 3 minute,also if i set more executor and more core he take the settings but he don't use that,so i think that the problem it's with the RDD, it don't split the input file in the right mode because it create only 2 task that start in 2 worknode and the other nodes remain inactive.
The jar file it's created with sbt package.
Command to launch Spark:
spark-submit --class "SimpleApp" --master yarn-client --num-executors 2 simpleapp_2.10-1.0.jar
WordCount Code:
import org.apache.spark.SparkContext
import org.apache.spark.SparkContext._
import org.apache.spark.SparkConf
import java.io._
import org.apache.hadoop.fs
import org.apache.spark.rdd.RDD
object SimpleApp {
def main(args: Array[String]){
//settingsparkcontext
val conf = new SparkConf().setAppName("SimpleApp")
val sc = new SparkContext(conf)
//settingthewordtosearch
val word = "word"
//settingtime
val now = System.nanoTime
//settingtheinputfile
val input = sc.textFile("wasb://xxx#storage.blob.core.windows.net/dizionario1gb.txt")
//wordlookup
val splittedLines = input.map(line=>line.split(""))
val find = System.nanoTime
val tot = splittedLines.map(x => x.equals(word)).count()
val w=(System.nanoTime-find)/1000000
val rw=(System.nanoTime-now)/1000000
//reportingtheresultofexecutioninatxtfile
val writer = new FileWriter("D:\\Users\\user\\Desktop\\File\\output.txt",true)
try {
writer.write("Word found "+tot+" time total "+rw+" mstimesearch "+w+" time read "+(rw-w)+"\n")
}
finally writer.close()
//terminatingthesparkserver
sc.stop()
}}
Level of Parallelism
"Clusters will not be fully utilized unless you set the level of parallelism for each operation high enough. Spark automatically sets the number of “map” tasks to run on each file according to its size (though you can control it through optional parameters to SparkContext.textFile, etc) You can pass the level of parallelism as a second argument (see the spark.PairRDDFunctions documentation), or set the config property spark.default.parallelism to change the default. In general, we recommend 2-3 tasks per CPU core in your cluster."
Source:
https://spark.apache.org/docs/1.3.1/tuning.html
I build a spark application to count the number of word in a file. I run the application on the cloudera quickstart VM, all is fine when i use the cloudera user directory but when i want to write or read in an other user directory i have a permission denied from hadoop. I would like to know how to change the hadoop user in spark.
package user1.item1
import user1.{Article}
import org.apache.spark.{SparkContext, SparkConf}
import org.apache.spark.SparkContext._
import scala.util.{Try, Success, Failure}
object WordCount {
def main(args: Array[String]) {
Context.User = 'espacechange'
val filename = "hdfs://quickstart.cloudera:8020/user/user1/test/wiki_test/wikipedia.txt"
val conf = new SparkConf().setAppName("word count")
val sc = new SparkContext(conf)
val wikipedia = sc.textFile(filename).map(Article.parseWikipediaArticle)
val counts = wikipedia.flatMap(line => line.text.split(" ")).map(word => (word, 1)).reduceByKey(_ + _)
counts.saveAsTextFile("hdfs://quickstart.cloudera:8020/user/user1/test/word_count")
}
}
It depends on your cluster's authentication. By default, you can set following environment variable:
$ export HADOOP_USER_NAME=hdfs
Try the above before submitting spark job.
You need to launch the spark-submit script using a different OS user.
For example, use the following command to run the spark application as (and get the permissions of) the HDFS user:
sudo -u hdfs spark-submit ....