How to convert int into Uint32 in flutter - flutter

Is there a way to convert an integer into the format Uint32.
int x = 94;
Uint32 y = x.toUint32(); ///Pseudocode

Dart doesn't have a unsigned integers.
You can however use a BigInt and use toUnsigned(32) after each operation you do to it.

Related

same Int has different values in Swift, mysterious riddle

with this code :
let rand : Int = Int(arc4random())
NSLog("rand = %d %i %# \(rand)",rand,rand,String(rand))
I get :
rand = -1954814774 -1954814774 2340152522 2340152522
why all 4 values are not the same ?
arc4random generates an unsigned 32bit int. Int is probably 64 bit on your machine so you get the same number and it doesn't overflow. But %i and %d are signed 32-bit format specifiers. See here and here. That's why you get a negative number when arc4random returns a number greater than 2^32-1, aka Int32.max.
For example, when 2340152522 is generated, you get -1954814774 in the %i position because:
Int32(bitPattern: 2340152522) == -1954814774
On the other hand, converting an Int to String won't change the number. Int is a signed 64 bit integer.

Vala: Convert int to uint16

How do I convert from int to uint16 in vala?
My requirement is to convert the text in decimal in a gtkEntry to uint16.
How do I do this?
Just cast. uint16 as_uint16 = (uint16) as_int;
You may want to first check that the value is between uint16.MIN and uint16.MAX.
int myint = 543;
uint16 z = 0 + myint;

Difference between Int and Uint8 swift

What are the differences between the data types Int & UInt8 in swift.
Looks like UInt8 is used for binary data, i need to convert UInt8 to Int is this possible.
That U in UInt stands for unsigned int.
It is not just using for binary data. Uint is used for positive numbers only, like natural numbers.
I recommend you to get to know how negative numbers are understood from a computer.
Int8 is an Integer type which can store positive and negative values.
UInt8 is an unsigned integer which can store only positive values.
You can easily convert UInt8 to Int8 but if you want to convert Int8 to UInt8 then make sure value should be positive.
UInt8 is an 8bit store, while Int not hardly defined or defined by the compiler:
https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/TheBasics.html
Int could be 32 or 64 bits
Updated for swift:
Operation Output Range Bytes per Element
uint8 0 to 255 1
Int - 9223372036854775808 to 9223372036854775807 2 or 4
If you want to find the max and min range of Int or UInt8:
let maxIntValue = Int.max
let maxUInt8Value = UInt8.max
let minIntValue = Int.min
let minUInt8Value = UInt8.min
If you want to convert UInt8 to Int, used below simple code:
func convertToInt(unsigned: UInt) -> Int {
let signed = (unsigned <= UInt(Int.max)) ?
Int(unsigned) :
Int(unsigned - UInt(Int.max) - 1) + Int.min
return signed
}

Parse signed number from hex using BigInt

I'm trying to parse a signed number using a BigInt. Here have been my attempts
scala> -1.toHexString
res7: String = ffffffff
scala> val bigInt = BigInt(res7,16)
bigInt: scala.math.BigInt = 4294967295
Is there any way to easily parse a signed number from a hex using BigInt?
If your hex string began life as an Integer or a Long—before converting it to a BigInt—parse it as an unsigned number with
java.lang.Integer.parseUnsignedInt("ffffffff",16) // Results in -1
or
java.lang.Long.parseUnsignedLong("ffffffffffffffff",16) // Results in -1
You have to tell it how long your number is one way or another. Without it, just saying "ffffffff" is ambiguous: as an Int it is -1, but as a long it is a large positive value:
bigInt.toLong
res48: Long = 4294967295
bigInt.toInt
res49: Int = -1

Unsigned long Int in Core data

I have an Entity with attribute of type Int64. But, I need to save an object with type Unsigned Long Int or unsigned long long Int. How can I do it?
Swift, please (:
Simply:
let x = Int64(5) //Int64
let y = CUnsignedLongLong(bitPattern: x) //Unsigned Long Long