How to split column in Spark Dataframe to multiple columns - scala

In my case how to split a column contain StringType with a format '1-1235.0 2-1248.0 3-7895.2' to another column with ArrayType contains ['1','2','3']

this is relatively simple with UDF:
val df = Seq("1-1235.0 2-1248.0 3-7895.2").toDF("input")
val extractFirst = udf((s: String) => s.split(" ").map(_.split('-')(0).toInt))
df.withColumn("newCol", extractFirst($"input"))
.show()
gives
+--------------------+---------+
| input| newCol|
+--------------------+---------+
|1-1235.0 2-1248.0...|[1, 2, 3]|
+--------------------+---------+
I could not find an easy soluton with spark internals (other than using split in combination with explode etc and then re-aggregating)

You can split the string to an array using split function and then you can transform the array using Higher Order Function TRANSFORM (it is available since Sark 2.4) together with substring_index:
import org.apache.spark.sql.functions.{split, expr}
val df = Seq("1-1235.0 2-1248.0 3-7895.2").toDF("stringCol")
df.withColumn("array", split($"stringCol", " "))
.withColumn("result", expr("TRANSFORM(array, x -> substring_index(x, '-', 1))"))
Notice that this is native approach, no UDF applied.

Related

Apply a transformation to all the columns with the same data type on Spark

I need to apply a transformation to all the Integer columns of my Data Frame before writting a CSV. The transformation consists on changing the type to String and then transform the format to the European one (E.g. 1234567 -> "1234567" -> "1.234.567").
Has Spark any way to apply this transformation to all the Integer Columns? I want it to be a generic functionality (because I need to write multiple CSVs) instead of hardcoding all the columns to transform for each dataframe.
DataFrame has dtypes method, which returns column names along with their data types: Array[("Column name", "Data Type")].
You can map this array, applying different expressions to each column, based on their data type. And you can then pass this mapped list to the select method:
import spark.implicits._
import org.apache.spark.sql.functions._
val dataSeq = Seq(
(1246984, 993922, "test_1"),
(246984, 993922, "test_2"),
(246984, 993922, "test_3"))
val df = dataSeq.toDF("int_1", "int_2", "str_3")
df.show
+-------+------+------+
| int_1| int_2| str_3|
+-------+------+------+
|1246984|993922|test_1|
| 246984|993922|test_2|
| 246984|993922|test_3|
+-------+------+------+
val columns =
df.dtypes.map{
case (c, "IntegerType") => regexp_replace(format_number(col(c), 0), ",", ".").as(c)
case (c, t) => col(c)
}
val df2 = df.select(columns:_*)
df2.show
+---------+-------+------+
| int_1| int_2| str_3|
+---------+-------+------+
|1,246,984|993,922|test_1|
| 246,984|993,922|test_2|
| 246,984|993,922|test_3|
+---------+-------+------+

Spark generate a list of column names that contains(SQL LIKE) a string

This one below is a simple syntax to search for a string in a particular column uisng SQL Like functionality.
val dfx = df.filter($"name".like(s"%${productName}%"))
The questions is How do I grab each and every column NAME that contained the particular string in its VALUES and generate a new column with a list of those "column names" for every row.
So far this is the approach I took but stuck as I cant use spark-sql "Like" function inside a UDF.
import org.apache.spark.sql.functions._
import org.apache.spark.sql.DataFrame
import org.apache.spark.sql.types._
import spark.implicits._
val df1 = Seq(
(0, "mango", "man", "dit"),
(1, "i-man", "man2", "mane"),
(2, "iman", "mango", "ho"),
(3, "dim", "kim", "sim")
).toDF("id", "col1", "col2", "col3")
val df2 = df1.columns.foldLeft(df1) {
(acc: DataFrame, colName: String) =>
acc.withColumn(colName, concat(lit(colName + "="), col(colName)))
}
val df3 = df2.withColumn("merged_cols", split(concat_ws("X", df2.columns.map(c=> col(c)):_*), "X"))
Here is a sample output. Note that here there are only 3 columns but in the real job I'll be reading multiple tables which can contain dynamic number of columns.
+--------------------------------------------+
|id | col1| col2| col3| merged_cols
+--------------------------------------------+
0 | mango| man | dit | col1, col2
1 | i-man| man2 | mane | col1, col2, col3
2 | iman | mango| ho | col1, col2
3 | dim | kim | sim|
+--------------------------------------------+
This can be done using a foldLeft over the columns together with when and otherwise:
val e = "%man%"
val df2 = df1.columns.foldLeft(df.withColumn("merged_cols", lit(""))){(df, c) =>
df.withColumn("merged_cols", when(col(c).like(e), concat($"merged_cols", lit(s"$c,"))).otherwise($"merged_cols"))}
.withColumn("merged_cols", expr("substring(merged_cols, 1, length(merged_cols)-1)"))
All columns that satisfies the condition e will be appended to the string in the merged_cols column. Note that the column must exist for the first append to work so it is added (containing an empty string) to the dataframe when sent into the foldLeft.
The last row in the code simply removes the extra , that is added in the end. If you want the result as an array instead, simply adding .withColumn("merged_cols", split($"merged_cols", ",")) would work.
An alternative appraoch is to instead use an UDF. This could be preferred when dealing with many columns since foldLeft will create multiple dataframe copies. Here regex is used (not the SQL like since that operates on whole columns).
val e = ".*man.*"
val concat_cols = udf((vals: Seq[String], names: Seq[String]) => {
vals.zip(names).filter{case (v, n) => v.matches(e)}.map(_._2)
})
val df2 = df.withColumn("merged_cols", concat_cols(array(df.columns.map(col(_)): _*), typedLit(df.columns.toSeq)))
Note: typedLit can be used in Spark versions 2.2+, when using older versions use array(df.columns.map(lit(_)): _*) instead.

How to add prefix and suffix values for a column in spark dataframe using scala [duplicate]

How do we concatenate two columns in an Apache Spark DataFrame?
Is there any function in Spark SQL which we can use?
With raw SQL you can use CONCAT:
In Python
df = sqlContext.createDataFrame([("foo", 1), ("bar", 2)], ("k", "v"))
df.registerTempTable("df")
sqlContext.sql("SELECT CONCAT(k, ' ', v) FROM df")
In Scala
import sqlContext.implicits._
val df = sc.parallelize(Seq(("foo", 1), ("bar", 2))).toDF("k", "v")
df.registerTempTable("df")
sqlContext.sql("SELECT CONCAT(k, ' ', v) FROM df")
Since Spark 1.5.0 you can use concat function with DataFrame API:
In Python :
from pyspark.sql.functions import concat, col, lit
df.select(concat(col("k"), lit(" "), col("v")))
In Scala :
import org.apache.spark.sql.functions.{concat, lit}
df.select(concat($"k", lit(" "), $"v"))
There is also concat_ws function which takes a string separator as the first argument.
Here's how you can do custom naming
import pyspark
from pyspark.sql import functions as sf
sc = pyspark.SparkContext()
sqlc = pyspark.SQLContext(sc)
df = sqlc.createDataFrame([('row11','row12'), ('row21','row22')], ['colname1', 'colname2'])
df.show()
gives,
+--------+--------+
|colname1|colname2|
+--------+--------+
| row11| row12|
| row21| row22|
+--------+--------+
create new column by concatenating:
df = df.withColumn('joined_column',
sf.concat(sf.col('colname1'),sf.lit('_'), sf.col('colname2')))
df.show()
+--------+--------+-------------+
|colname1|colname2|joined_column|
+--------+--------+-------------+
| row11| row12| row11_row12|
| row21| row22| row21_row22|
+--------+--------+-------------+
One option to concatenate string columns in Spark Scala is using concat.
It is necessary to check for null values. Because if one of the columns is null, the result will be null even if one of the other columns do have information.
Using concat and withColumn:
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull, col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull, col("COL2")).otherwise(lit("null"))))
Using concat and select:
val newDf = df.selectExpr("concat(nvl(COL1, ''), nvl(COL2, '')) as NEW_COLUMN")
With both approaches you will have a NEW_COLUMN which value is a concatenation of the columns: COL1 and COL2 from your original df.
concat(*cols)
v1.5 and higher
Concatenates multiple input columns together into a single column. The function works with strings, binary and compatible array columns.
Eg: new_df = df.select(concat(df.a, df.b, df.c))
concat_ws(sep, *cols)
v1.5 and higher
Similar to concat but uses the specified separator.
Eg: new_df = df.select(concat_ws('-', df.col1, df.col2))
map_concat(*cols)
v2.4 and higher
Used to concat maps, returns the union of all the given maps.
Eg: new_df = df.select(map_concat("map1", "map2"))
Using concat operator (||):
v2.3 and higher
Eg: df = spark.sql("select col_a || col_b || col_c as abc from table_x")
Reference: Spark sql doc
If you want to do it using DF, you could use a udf to add a new column based on existing columns.
val sqlContext = new SQLContext(sc)
case class MyDf(col1: String, col2: String)
//here is our dataframe
val df = sqlContext.createDataFrame(sc.parallelize(
Array(MyDf("A", "B"), MyDf("C", "D"), MyDf("E", "F"))
))
//Define a udf to concatenate two passed in string values
val getConcatenated = udf( (first: String, second: String) => { first + " " + second } )
//use withColumn method to add a new column called newColName
df.withColumn("newColName", getConcatenated($"col1", $"col2")).select("newColName", "col1", "col2").show()
From Spark 2.3(SPARK-22771) Spark SQL supports the concatenation operator ||.
For example;
val df = spark.sql("select _c1 || _c2 as concat_column from <table_name>")
Here is another way of doing this for pyspark:
#import concat and lit functions from pyspark.sql.functions
from pyspark.sql.functions import concat, lit
#Create your data frame
countryDF = sqlContext.createDataFrame([('Ethiopia',), ('Kenya',), ('Uganda',), ('Rwanda',)], ['East Africa'])
#Use select, concat, and lit functions to do the concatenation
personDF = countryDF.select(concat(countryDF['East Africa'], lit('n')).alias('East African'))
#Show the new data frame
personDF.show()
----------RESULT-------------------------
84
+------------+
|East African|
+------------+
| Ethiopian|
| Kenyan|
| Ugandan|
| Rwandan|
+------------+
Here is a suggestion for when you don't know the number or name of the columns in the Dataframe.
val dfResults = dfSource.select(concat_ws(",",dfSource.columns.map(c => col(c)): _*))
Do we have java syntax corresponding to below process
val dfResults = dfSource.select(concat_ws(",",dfSource.columns.map(c => col(c)): _*))
In Spark 2.3.0, you may do:
spark.sql( """ select '1' || column_a from table_a """)
In Java you can do this to concatenate multiple columns. The sample code is to provide you a scenario and how to use it for better understanding.
SparkSession spark = JavaSparkSessionSingleton.getInstance(rdd.context().getConf());
Dataset<Row> reducedInventory = spark.sql("select * from table_name")
.withColumn("concatenatedCol",
concat(col("col1"), lit("_"), col("col2"), lit("_"), col("col3")));
class JavaSparkSessionSingleton {
private static transient SparkSession instance = null;
public static SparkSession getInstance(SparkConf sparkConf) {
if (instance == null) {
instance = SparkSession.builder().config(sparkConf)
.getOrCreate();
}
return instance;
}
}
The above code concatenated col1,col2,col3 seperated by "_" to create a column with name "concatenatedCol".
In my case, I wanted a Pipe-'I' delimited row.
from pyspark.sql import functions as F
df.select(F.concat_ws('|','_c1','_c2','_c3','_c4')).show()
This worked well like a hot knife over butter.
use concat method like this:
Dataset<Row> DF2 = DF1
.withColumn("NEW_COLUMN",concat(col("ADDR1"),col("ADDR2"),col("ADDR3"))).as("NEW_COLUMN")
Another way to do it in pySpark using sqlContext...
#Suppose we have a dataframe:
df = sqlContext.createDataFrame([('row1_1','row1_2')], ['colname1', 'colname2'])
# Now we can concatenate columns and assign the new column a name
df = df.select(concat(df.colname1, df.colname2).alias('joined_colname'))
Indeed, there are some beautiful inbuilt abstractions for you to accomplish your concatenation without the need to implement a custom function. Since you mentioned Spark SQL, so I am guessing you are trying to pass it as a declarative command through spark.sql(). If so, you can accomplish in a straight forward manner passing SQL command like:
SELECT CONCAT(col1, '<delimiter>', col2, ...) AS concat_column_name FROM <table_name>;
Also, from Spark 2.3.0, you can use commands in lines with:
SELECT col1 || col2 AS concat_column_name FROM <table_name>;
Wherein, is your preferred delimiter (can be empty space as well) and is the temporary or permanent table you are trying to read from.
We can simple use SelectExpr as well.
df1.selectExpr("*","upper(_2||_3) as new")
We can use concat() in select method of dataframe
val fullName = nameDF.select(concat(col("FirstName"), lit(" "), col("LastName")).as("FullName"))
Using withColumn and concat
val fullName1 = nameDF.withColumn("FullName", concat(col("FirstName"), lit(" "), col("LastName")))
Using spark.sql concat function
val fullNameSql = spark.sql("select Concat(FirstName, LastName) as FullName from names")
Taken from https://www.sparkcodehub.com/spark-dataframe-concat-column
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull, col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull, col("COL2")).otherwise(lit("null"))))
Note: For this code to work you need to put the parentheses "()" in the "isNotNull" function. -> The correct one is "isNotNull()".
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull(), col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull(), col("COL2")).otherwise(lit("null"))))

How to concatenate multiple columns into single column (with no prior knowledge on their number)?

Let say I have the following dataframe:
agentName|original_dt|parsed_dt| user|text|
+----------+-----------+---------+-------+----+
|qwertyuiop| 0| 0|16102.0| 0|
I wish to create a new dataframe with one more column that has the concatenation of all the elements of the row:
agentName|original_dt|parsed_dt| user|text| newCol
+----------+-----------+---------+-------+----+
|qwertyuiop| 0| 0|16102.0| 0| [qwertyuiop, 0,0, 16102, 0]
Note: This is a just an example. The number of columns and names of them is not known. It is dynamic.
TL;DR Use struct function with Dataset.columns operator.
Quoting the scaladoc of struct function:
struct(colName: String, colNames: String*): Column Creates a new struct column that composes multiple input columns.
There are two variants: string-based for column names or using Column expressions (that gives you more flexibility on the calculation you want to apply on the concatenated columns).
From Dataset.columns:
columns: Array[String] Returns all column names as an array.
Your case would then look as follows:
scala> df.withColumn("newCol",
struct(df.columns.head, df.columns.tail: _*)).
show(false)
+----------+-----------+---------+-------+----+--------------------------+
|agentName |original_dt|parsed_dt|user |text|newCol |
+----------+-----------+---------+-------+----+--------------------------+
|qwertyuiop|0 |0 |16102.0|0 |[qwertyuiop,0,0,16102.0,0]|
+----------+-----------+---------+-------+----+--------------------------+
I think this works perfect for your case
here is with an example
val spark =
SparkSession.builder().master("local").appName("test").getOrCreate()
import spark.implicits._
val data = spark.sparkContext.parallelize(
Seq(
("qwertyuiop", 0, 0, 16102.0, 0)
)
).toDF("agentName","original_dt","parsed_dt","user","text")
val result = data.withColumn("newCol", split(concat_ws(";", data.schema.fieldNames.map(c=> col(c)):_*), ";"))
result.show()
+----------+-----------+---------+-------+----+------------------------------+
|agentName |original_dt|parsed_dt|user |text|newCol |
+----------+-----------+---------+-------+----+------------------------------+
|qwertyuiop|0 |0 |16102.0|0 |[qwertyuiop, 0, 0, 16102.0, 0]|
+----------+-----------+---------+-------+----+------------------------------+
Hope this helped!
In general, you can merge multiple dataframe columns into one using array.
df.select($"*",array($"col1",$"col2").as("newCol")) \\$"*" will capture all existing columns
Here is the one line solution for your case:
df.select($"*",array($"agentName",$"original_dt",$"parsed_dt",$"user", $"text").as("newCol"))
You can use udf function to concat all the columns into one. All you have to do is define a udf function and pass all the columns you want to concat to the udf function and call the udf function using .withColumn function of dataframe
Or
You can use concat_ws(java.lang.String sep, Column... exprs) function available for dataframe.
var df = Seq(("qwertyuiop",0,0,16102.0,0))
.toDF("agentName","original_dt","parsed_dt","user","text")
df.withColumn("newCol", concat_ws(",",$"agentName",$"original_dt",$"parsed_dt",$"user",$"text"))
df.show(false)
Will give you output as
+----------+-----------+---------+-------+----+------------------------+
|agentName |original_dt|parsed_dt|user |text|newCol |
+----------+-----------+---------+-------+----+------------------------+
|qwertyuiop|0 |0 |16102.0|0 |qwertyuiop,0,0,16102.0,0|
+----------+-----------+---------+-------+----+------------------------+
That will get you the result you want
There may be syntax errors in my answer. This is useful if you are using java<8 and spark<2.
String columns=null
For ( String columnName : dataframe.columns())
{
Columns = columns == null ? columnName : columns+"," + columnName;
}
SqlContext.sql(" select *, concat_ws('|', " +columns+ ") as complete_record " +
"from data frame ").show();

full process of Joining 2 diffrent filed from a table and creating new filed in spark sql [duplicate]

How do we concatenate two columns in an Apache Spark DataFrame?
Is there any function in Spark SQL which we can use?
With raw SQL you can use CONCAT:
In Python
df = sqlContext.createDataFrame([("foo", 1), ("bar", 2)], ("k", "v"))
df.registerTempTable("df")
sqlContext.sql("SELECT CONCAT(k, ' ', v) FROM df")
In Scala
import sqlContext.implicits._
val df = sc.parallelize(Seq(("foo", 1), ("bar", 2))).toDF("k", "v")
df.registerTempTable("df")
sqlContext.sql("SELECT CONCAT(k, ' ', v) FROM df")
Since Spark 1.5.0 you can use concat function with DataFrame API:
In Python :
from pyspark.sql.functions import concat, col, lit
df.select(concat(col("k"), lit(" "), col("v")))
In Scala :
import org.apache.spark.sql.functions.{concat, lit}
df.select(concat($"k", lit(" "), $"v"))
There is also concat_ws function which takes a string separator as the first argument.
Here's how you can do custom naming
import pyspark
from pyspark.sql import functions as sf
sc = pyspark.SparkContext()
sqlc = pyspark.SQLContext(sc)
df = sqlc.createDataFrame([('row11','row12'), ('row21','row22')], ['colname1', 'colname2'])
df.show()
gives,
+--------+--------+
|colname1|colname2|
+--------+--------+
| row11| row12|
| row21| row22|
+--------+--------+
create new column by concatenating:
df = df.withColumn('joined_column',
sf.concat(sf.col('colname1'),sf.lit('_'), sf.col('colname2')))
df.show()
+--------+--------+-------------+
|colname1|colname2|joined_column|
+--------+--------+-------------+
| row11| row12| row11_row12|
| row21| row22| row21_row22|
+--------+--------+-------------+
One option to concatenate string columns in Spark Scala is using concat.
It is necessary to check for null values. Because if one of the columns is null, the result will be null even if one of the other columns do have information.
Using concat and withColumn:
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull, col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull, col("COL2")).otherwise(lit("null"))))
Using concat and select:
val newDf = df.selectExpr("concat(nvl(COL1, ''), nvl(COL2, '')) as NEW_COLUMN")
With both approaches you will have a NEW_COLUMN which value is a concatenation of the columns: COL1 and COL2 from your original df.
concat(*cols)
v1.5 and higher
Concatenates multiple input columns together into a single column. The function works with strings, binary and compatible array columns.
Eg: new_df = df.select(concat(df.a, df.b, df.c))
concat_ws(sep, *cols)
v1.5 and higher
Similar to concat but uses the specified separator.
Eg: new_df = df.select(concat_ws('-', df.col1, df.col2))
map_concat(*cols)
v2.4 and higher
Used to concat maps, returns the union of all the given maps.
Eg: new_df = df.select(map_concat("map1", "map2"))
Using concat operator (||):
v2.3 and higher
Eg: df = spark.sql("select col_a || col_b || col_c as abc from table_x")
Reference: Spark sql doc
If you want to do it using DF, you could use a udf to add a new column based on existing columns.
val sqlContext = new SQLContext(sc)
case class MyDf(col1: String, col2: String)
//here is our dataframe
val df = sqlContext.createDataFrame(sc.parallelize(
Array(MyDf("A", "B"), MyDf("C", "D"), MyDf("E", "F"))
))
//Define a udf to concatenate two passed in string values
val getConcatenated = udf( (first: String, second: String) => { first + " " + second } )
//use withColumn method to add a new column called newColName
df.withColumn("newColName", getConcatenated($"col1", $"col2")).select("newColName", "col1", "col2").show()
From Spark 2.3(SPARK-22771) Spark SQL supports the concatenation operator ||.
For example;
val df = spark.sql("select _c1 || _c2 as concat_column from <table_name>")
Here is another way of doing this for pyspark:
#import concat and lit functions from pyspark.sql.functions
from pyspark.sql.functions import concat, lit
#Create your data frame
countryDF = sqlContext.createDataFrame([('Ethiopia',), ('Kenya',), ('Uganda',), ('Rwanda',)], ['East Africa'])
#Use select, concat, and lit functions to do the concatenation
personDF = countryDF.select(concat(countryDF['East Africa'], lit('n')).alias('East African'))
#Show the new data frame
personDF.show()
----------RESULT-------------------------
84
+------------+
|East African|
+------------+
| Ethiopian|
| Kenyan|
| Ugandan|
| Rwandan|
+------------+
Here is a suggestion for when you don't know the number or name of the columns in the Dataframe.
val dfResults = dfSource.select(concat_ws(",",dfSource.columns.map(c => col(c)): _*))
Do we have java syntax corresponding to below process
val dfResults = dfSource.select(concat_ws(",",dfSource.columns.map(c => col(c)): _*))
In Spark 2.3.0, you may do:
spark.sql( """ select '1' || column_a from table_a """)
In Java you can do this to concatenate multiple columns. The sample code is to provide you a scenario and how to use it for better understanding.
SparkSession spark = JavaSparkSessionSingleton.getInstance(rdd.context().getConf());
Dataset<Row> reducedInventory = spark.sql("select * from table_name")
.withColumn("concatenatedCol",
concat(col("col1"), lit("_"), col("col2"), lit("_"), col("col3")));
class JavaSparkSessionSingleton {
private static transient SparkSession instance = null;
public static SparkSession getInstance(SparkConf sparkConf) {
if (instance == null) {
instance = SparkSession.builder().config(sparkConf)
.getOrCreate();
}
return instance;
}
}
The above code concatenated col1,col2,col3 seperated by "_" to create a column with name "concatenatedCol".
In my case, I wanted a Pipe-'I' delimited row.
from pyspark.sql import functions as F
df.select(F.concat_ws('|','_c1','_c2','_c3','_c4')).show()
This worked well like a hot knife over butter.
use concat method like this:
Dataset<Row> DF2 = DF1
.withColumn("NEW_COLUMN",concat(col("ADDR1"),col("ADDR2"),col("ADDR3"))).as("NEW_COLUMN")
Another way to do it in pySpark using sqlContext...
#Suppose we have a dataframe:
df = sqlContext.createDataFrame([('row1_1','row1_2')], ['colname1', 'colname2'])
# Now we can concatenate columns and assign the new column a name
df = df.select(concat(df.colname1, df.colname2).alias('joined_colname'))
Indeed, there are some beautiful inbuilt abstractions for you to accomplish your concatenation without the need to implement a custom function. Since you mentioned Spark SQL, so I am guessing you are trying to pass it as a declarative command through spark.sql(). If so, you can accomplish in a straight forward manner passing SQL command like:
SELECT CONCAT(col1, '<delimiter>', col2, ...) AS concat_column_name FROM <table_name>;
Also, from Spark 2.3.0, you can use commands in lines with:
SELECT col1 || col2 AS concat_column_name FROM <table_name>;
Wherein, is your preferred delimiter (can be empty space as well) and is the temporary or permanent table you are trying to read from.
We can simple use SelectExpr as well.
df1.selectExpr("*","upper(_2||_3) as new")
We can use concat() in select method of dataframe
val fullName = nameDF.select(concat(col("FirstName"), lit(" "), col("LastName")).as("FullName"))
Using withColumn and concat
val fullName1 = nameDF.withColumn("FullName", concat(col("FirstName"), lit(" "), col("LastName")))
Using spark.sql concat function
val fullNameSql = spark.sql("select Concat(FirstName, LastName) as FullName from names")
Taken from https://www.sparkcodehub.com/spark-dataframe-concat-column
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull, col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull, col("COL2")).otherwise(lit("null"))))
Note: For this code to work you need to put the parentheses "()" in the "isNotNull" function. -> The correct one is "isNotNull()".
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull(), col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull(), col("COL2")).otherwise(lit("null"))))