Will JPA generate more than one auto generated coulmns - spring-data-jpa

Question

everyone I have a requirement that I want to generate two auto-generated values for two different columns. I am using Azure SQL DB as my RDBMS.
and I am using spring data JPA to persist my values.
Example:
#Entity
#Table(name="T_JUST_FOR_TEST")
public class TJustForTest implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#SequenceGenerator(name="SEQ_GEN", sequenceName="SEQ_JUST_FOR_TEST", allocationSize=1)
#GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SEQ_GEN")
private long id;
private String userRegistrationId;
public TJustForTest() {}
public long getId() {
return this.id;
}
public void setId(long id) {
this.id = id;
}
}
here, I would like to use Id as my primary key as auto-generated and userRegistration Id also auto-generated but not primary key just a unique key and some custom format
Example
I will append some string as prefix and id as a suffix, meaning I will use the same primary key to generate the userRegistration No.
is there any way to achieve this or any other way around it, please clarify.

Answer 1

finally, I found a better solution to generate userRegistration by using Id,
I need to write one Listener class to get the auto-generated Id in my using #PostPersist
annotation, actually this will be called once the entity object persists in DB.
public class TJustForTestListener {
#PostPersist
public void getPostPersist(TJustForTest ob) {
try {
ob.setuserRegistrationId("CR"+ob.getId());
}catch(Exception e) {
e.printStackTrace();
}
}
and in Entity level i need to declare my listener class by using #EntityListeners
#Entity
#Table(name="T_JUST_FOR_TEST")
#EntityListeners(TJustForTestListener .class)
public class TJustForTest implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#SequenceGenerator(name="SEQ_GEN", sequenceName="SEQ_JUST_FOR_TEST", allocationSize=1)
#GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SEQ_GEN")
private long id;
private String userRegistrationId;
public TJustForTest() {}
public long getId() {
return this.id;
}
public void setId(long id) {
this.id = id;
}
}
that's all it is required, JPA will insert the record first then update automatically.