how to pass a variable in "get-content command " in powershell - powershell

Question

I have to get the particular file from one remote desktop to local machine or another server.How to pass a variable in get-content to fetch the file from remote desktop connection?
I store the file path as variable and try to pass it in get-content.
Invoke-Command -Computername $Server -ScriptBlock{get-content -path $file }
Invoke-Command -Computername $Server -ScriptBlock{get-content -path ${file} }
$file="C:\Users\Documents\new DB_connection\\log2.txt"
$Server="servername"
$answer= Invoke-Command -Computername $Server -ScriptBlock{get-content -path $file }
write-output $answer
Cannot bind argument to parameter 'Path' because it is null.
+ CategoryInfo : InvalidData: (:) [Get-Content], ParameterBindingValidationException
+ FullyQualifiedErrorId : ParameterArgumentValidationErrorNullNotAllowed,Microsoft.PowerShell.Commands.GetContentCommand

Answer 1

You can copy the file over a PSSession instead of using Invoke-Command. To copy from a remote server to a local path or different remote server:
$session = New-PSSession -ComputerName server.domain.tld
Copy-Item -Source $originatingServerFilePath -Destination $localOrUNCFilePath -FromSession $session
If you need to copy a local file to a destination server:
Copy-Item -Source $localFilePath -Destination $destinationServerFilePath -ToSession $session
This has the benefit of not double-hopping, though the server you run the command on will need to have access to any remote file paths. If you need to copy a file from one server to another server, but the destination server doesn't have the filepath exposed as a shared folder (or you don't have access to it) you cannot specify -ToSession and -FromSession at the same time, so you'll have to copy the file locally and use two sessions like so:
$sourceSession = New-PSSession -ComputerName source.domain.tld
$destinationSession = New-PSSession -ComputerName destination.domain.tld
# Copy the remote file(s) from the source session to a local path first
Copy-Item -Source $sourceSessionFilePath -Destination $localTempFilePath -FromSession $sourceSession
# Copy the new local files to the destination session from your local path
Copy-Item -Source $localTempFilePath -Destination $destinationSessionFilePath -ToSession $destinationSession

Answer 2

Try to define the variable inside the ScriptBlock
$Server="servername"
$answer= Invoke-Command -Computername $Server -ScriptBlock{
$file="C:\Users\Documents\new DB_connection\\log2.txt";
get-content -path $file}
write-output $answer