How can i use open in new tab in swift ?(WEBKIT) - swift

Question

How can i use safari-open in new tab in my webkit app
I am creating a internet browser and i need that
Just like the photo
For example, I want to show the open in new tab option when I hold my finger on a link in Google
enter image description here
class ViewController: UIViewController, UITextFieldDelegate, WKNavigationDelegate {
#IBOutlet weak var backButton: UIButton!
#IBOutlet weak var forwardButton: UIButton!
#IBOutlet weak var webView: WKWebView!
#IBOutlet weak var urlTextField: UITextField!
override func viewDidLoad() {
super.viewDidLoad()
urlTextField.delegate = self
webView.navigationDelegate = self
}
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear( animated )
let urlString:String = "https://www.google.com"
let url:URL = URL(string: urlString)!
let urlRequest:URLRequest = URLRequest(url: url)
webView.load(urlRequest)
urlTextField.text = urlString
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func textFieldShouldReturn(_ textField: UITextField) -> Bool {
let urlString:String = urlTextField.text!
let url:URL = URL(string: urlString)!
let urlRequest:URLRequest = URLRequest(url: url)
webView.load(urlRequest)
textField.resignFirstResponder()
return true
}
#IBAction func backButtonTapped(_ sender: Any) {
if webView.canGoBack {
webView.goBack()
}
}
#IBAction func forwardButtonTapped(_ sender: Any) {
if webView.canGoForward {
webView.goForward()
}
}
func webView(_ webView: WKWebView, didFinish navigation: WKNavigation!) {
backButton.isEnabled = webView.canGoBack
forwardButton.isEnabled = webView.canGoForward
urlTextField.text = webView.url?.absoluteString
}
}

Answer 1

Use this delegate method in bellow you last medhod :
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: #escaping (WKNavigationActionPolicy) -> Void) {
if navigationAction.targetFrame == nil {
if let url = navigationAction.request.url {
let app = UIApplication.shared
if app.canOpenURL(url) {
app.open(url, options: [:], completionHandler: nil)
}
}
}
decisionHandler(.allow)
}
is It oky ?