I have schema data like below
{
id:'5d60fd38f6999a7792c940a4'
name:'test',
department:[
{
d_name:'Rd',
_id:'5d61092b1f234c11348eb831'
equipements:[
{
id:'5d637abd7ddd183263fa4ebc'
e_name:'first'
},
]
}
]
}
and I'm try to update the equipments by following way
College.updateOne(
{
_id: productObjectID,
'department._id': variantObjectId
},
{ $set: data }
);
but unfortunately this query is not update my equipment data .
can let me know what is right way to update. thanks
You need to search with the equipements.id in order to udpate the name
This would work
College.updateOne({
_id: productObjectID,
"department._id": variantObjectId,
"department.equipements.id": equipementId
},{ "$set": {"department.equipements.$.name": "updatedName"} });
I assume you're trying to achieve the below:
db.dummyTest.updateOne({ "_id" : ObjectId("5d63a1791b761bfc0420e590"),
"department._id": "5d61092b1f234c11348eb831",
"department.equipements._id": "5d637abd7ddd183263fa4ebc" },
{ $set: { "department.$.equipements.0.e_name.0": "Update to last" }})
MongoDB's support for updating nested arrays is poor. So you're best off avoiding their use if you need to update the data frequently
Option 1: Make department its own collection (make department, as sub document instead of array)
Option 2: Achieve it through program
Related
I have a mongo collection where a field is supposed to point to another document's id in the same collection, but instead it is pointing to its "number". I need to perform an update on them but I'm having some problems on forming the query. Could you help me?
The structure of the document is like this:
{
"_id": "269410e2-cebf-40f1-a81f-fdce34185cdc",
"number": 1471,
"alternativeLocationId": "9871",
"locationType": "DUMMY"
},
{
"_id": "2945b24a-b82f-45a9-ad06-a884379b5597",
"number": 9871,
"locationType": "MAIN"
}
So as asked, I'd need to make document with number 1471 "alternativeLocationId" to be "2945b24a-b82f-45a9-ad06-a884379b5597" instead of 9871 (Note that the referenced documents are not locationType "DUMMY" nor have this alternativeLocationId field).
The query I've done so far goes like this, but when executed its not doing any changes:
db.location.find({alternativeLocationId: {$exists:true}}).forEach(
function (loc) {
var correctLocation = db.location.findOne({number: loc.alternativeLocationId});
db.location.update(
{_id: loc._id},
{$set: {alternativeLocationId: correctLocation._id} }
);
}
);
As mentioned by user20042973 the issue was the type mismatch between alternativeLocationId and locationNumber, after converting the value to int when looking for it, it works perfectly.
I'm in a trouble. I want to update the second item in a sorted doc in mongo. But the UpdateOne can't use skip in the filter param. I know the aggreate operation cant do it with skip and merge. However, how to use UpdateOne to realize it?
the data:
[
{"_id":1, "name": "tramp"},
{"_id":2, "name": "Biden"},
...
]
How to update them _id equal to 2, 3, and others?
thanks.
Even so, I'm not entirely clear about your query. I hope you'll find what you're looking for here.
const { data } = req.body;
data.forEach(async (e) => {
await User.findByIdAndUpdate({ _id: e._id }, { name: e.name});
})
User is your Collection Name
Use case
Adding a field to a specific object in an array of objects using updateOne during a bulkUpdateOps
Blockers
I have been unable to find a way to identify and update a specific object in the subdocument array of a specific record.
I only have access to this DB through MongoDB Compass, and I plan to use the provided mongosh tool.
Data example
Our purchaseorders model looks like this:
{
_id: uuid,
...rest,
documents:[
{
_id:uuid,
forignKey2:string (optional),
keyIWantToAdd:string (optional),
...rest
}
]
}
So if I have
{
_id:*1,
documents:[
{
_id:*2,
forignKey2:'no-test',
...rest
},
{
_id:*3,
forignKey2:'test',
...rest
},
]
}
I want to add a key and value like this (really I'm willing to do anything to set these values, this is just the closest I have been able to get):
var bulkUpdateOps = db.purchaseorders.initializeOrderedBulkOp();
bulkUpdateOps.find('*1').updateOne({
$set:{
documents.[index of document object with forignKey2:'test' or _id:*3 whichever is easier].keyIWantToAdd:'valueIWantToAdd'
}
})
bulkUpdateOps.execute();
Any help or suggestions would be greatly appreciated.
#rickhg12hs posted exactly what I was looking for. For anyone else using mongodb.com/docs/manual/reference/method/Bulk.find.arrayFilters the bulk find is being ran on an array of objects like this: { grades:[ { grade: 85, mean: number } ] }
Currently I use the following find query to get the latest document of a certain ID
Conditions.find({
caveId: caveId
},
{
sort: {diveDate:-1},
limit: 1,
fields: {caveId: 1, "visibility.visibility":1, diveDate: 1}
});
How can I use the same using multiple ids with $in for example
I tried it with the following query. The problem is that it will limit the documents to 1 for all the found caveIds. But it should set the limit for each different caveId.
Conditions.find({
caveId: {$in: caveIds}
},
{
sort: {diveDate:-1},
limit: 1,
fields: {caveId: 1, "visibility.visibility":1, diveDate: 1}
});
One solution I came up with is using the aggregate functionality.
var conditionIds = Conditions.aggregate(
[
{"$match": { caveId: {"$in": caveIds}}},
{
$group:
{
_id: "$caveId",
conditionId: {$last: "$_id"},
diveDate: { $last: "$diveDate" }
}
}
]
).map(function(child) { return child.conditionId});
var conditions = Conditions.find({
_id: {$in: conditionIds}
},
{
fields: {caveId: 1, "visibility.visibility":1, diveDate: 1}
});
You don't want to use $in here as noted. You could solve this problem by looping through the caveIds and running the query on each caveId individually.
you're basically looking at a join query here: you need all caveIds and then lookup last for each.
This is a problem of database schema/denormalization in my opinion: (but this is only an opinion!):
You could as mentioned here, lookup all caveIds and then run the single query for each, every single time you need to look up last dives.
However I think you are much better off recording/updating the last dive inside your cave document, and then lookup all caveIds of interest pulling only the lastDive field.
That will give you immediately what you need, rather than going through expensive search/sort queries. This is at the expense of maintaining that field in the document, but it sounds like it should be fairly trivial as you only need to update the one field when a new event occurs.
I am totally new to MongoDB... I am missing a "newbie" tag, so the experts would not have to see this question.
I am trying to update all documents in a collection using an expression. The query I was expecting to solve this was:
db.QUESTIONS.update({}, { $set: { i_pp : i_up * 100 - i_down * 20 } }, false, true);
That, however, results in the following error message:
ReferenceError: i_up is not defined (shell):1
At the same time, the database did not have any problem with eating this one:
db.QUESTIONS.update({}, { $set: { i_pp : 0 } }, false, true);
Do I have to do this one document at a time or something? That just seems excessively complicated.
Update
Thank you Sergio Tulentsev for telling me that it does not work. Now, I am really struggling with how to do this. I offer 500 Profit Points to the helpful soul, who can write this in a way that MongoDB understands. If you register on our forum I can add the Profit Points to your account there.
I just came across this while searching for the MongoDB equivalent of SQL like this:
update t
set c1 = c2
where ...
Sergio is correct that you can't reference another property as a value in a straight update. However, db.c.find(...) returns a cursor and that cursor has a forEach method:
Queries to MongoDB return a cursor, which can be iterated to retrieve
results. The exact way to query will vary with language driver.
Details below focus on queries from the MongoDB shell (i.e. the
mongo process).
The shell find() method returns a cursor object which we can then iterate to retrieve specific documents from the result. We use
hasNext() and next() methods for this purpose.
for( var c = db.parts.find(); c.hasNext(); ) {
print( c.next());
}
Additionally in the shell, forEach() may be used with a cursor:
db.users.find().forEach( function(u) { print("user: " + u.name); } );
So you can say things like this:
db.QUESTIONS.find({}, {_id: true, i_up: true, i_down: true}).forEach(function(q) {
db.QUESTIONS.update(
{ _id: q._id },
{ $set: { i_pp: q.i_up * 100 - q.i_down * 20 } }
);
});
to update them one at a time without leaving MongoDB.
If you're using a driver to connect to MongoDB then there should be some way to send a string of JavaScript into MongoDB; for example, with the Ruby driver you'd use eval:
connection.eval(%q{
db.QUESTIONS.find({}, {_id: true, i_up: true, i_down: true}).forEach(function(q) {
db.QUESTIONS.update(
{ _id: q._id },
{ $set: { i_pp: q.i_up * 100 - q.i_down * 20 } }
);
});
})
Other languages should be similar.
//the only differnce is to make it look like and aggregation pipeline
db.table.updateMany({}, [{
$set: {
col3:{"$sum":["$col1","$col2"]}
},
}]
)
You can't use expressions in updates. Or, rather, you can't use expressions that depend on fields of the document. Simple self-containing math expressions are fine (e.g. 2 * 2).
If you want to set a new field for all documents that is a function of other fields, you have to loop over them and update manually. Multi-update won't help here.
Rha7 gave a good idea, but the code above is not work without defining a temporary variable.
This sample code produces an approximate calculation of the age (leap years behinds the scene) based on 'birthday' field and inserts the value into suitable field for all documents not containing such:
db.employers.find({age: {$exists: false}}).forEach(function(doc){
var new_age = parseInt((ISODate() - doc.birthday)/(3600*1000*24*365));
db.employers.update({_id: doc._id}, {$set: {age: new_age}});
});
Example to remove "00" from the beginning of a caller id:
db.call_detail_records_201312.find(
{ destination: /^001/ },
{ "destination": true }
).forEach(function(row){
db.call_detail_records_201312.update(
{ _id: row["_id"] },
{ $set: {
destination: row["destination"].replace(/^001/, '1')
}
}
)
});