i cant find out what does name_get()[0][1]
display_name = product_id.name_get()[0][1]
if product_id.description_sale:
display_name += '\n' + product_id.description_sale
Breaking it down backwards: [0][1] indicates an element of a 2d array (an array that has elements which are also arrays), so therefore we can infer that the expectation is that name_get() returns a 2d array - we can't say anything about the type of values inside those arrays though - python is dynamically typed.
product.name_get() indicates that name_get() is a method/function of the product class/file.
As an example - name_get() might return something like
[ ["savings account", "current account"], ["credit card", "store card"] ]
so name_get()[0][1] would evaluate to "current account"
Related
I want to go through my list of strings, and add it to a text element for display, but I want to remove the commas and remove the [] as well as the whitespace, but leave the symbols except the commas and brackets.
So if the List is.
[1,2,#3,*4,+5]
In the text field I want it to show - "12#3*4+5"
I can figure out how to display it, but Im using
Text(myList.tostring().replaceAll('[\\]\\,\\', '')
Is there a way to do this?
You should use the reduce method on your list.
List<String> myList = ["1", "2", "#3", "*4", "+5"];
String finalStr = myList.reduce((value, element) {
return value + element;
});
print(finalStr);
# output: "12#3*4+5"
This method reduces a collection to a single value by iteratively combining elements of the collection using the provided function.
The method takes a function that receives two parameters: one is the current concatenated value, which starts out with the value of the first element of your list, and the second parameter is the next element on your list. So you can do something with those two values, and return it for the next iterations. At last, a single reduced value is returned. In this case, using strings, the code in my answer will concatenate the values. If those were numbers, the result would be a sum of the elements.
If you want to add anything in between elements, simply use the return value. For instance, to separate the elements by comma and whitespace, it should look like return value + " ," + element;.
Unless I'm misunderstanding the question, the most obvious solution would be to use List.join().
List<String> myList = ["1", "2", "#3", "*4", "+5"];
print( myList.join() );
// Result
// 12#3*4+5
You could also specify a separator
print( myList.join(' ') );
// Result
// 1 2 #3 *4 +5
I am trying to grab data from an excel spread sheet and grab only the information from cells that match a string. Eg. if cell A10 contains the word 'Canada' it should return that cell.
I have tried using strcmp(https://www.mathworks.com/help/matlab/ref/strcmp.html) to check if string in argument 1 is contained in a cell array containing many strings, the second argument
[num,txt,raw] = xlsread('\\Client\C$\Users\Fish\Desktop\dataset\dataset.csv');
mytable = cell(raw);
for i = 1:54841
array_index = i;
string_index = mytable(i,2);
string_eastern = {'Canada', 'Ontario'};
if strcmp(string_index,string_eastern);
fprintf('%d\n',array_index)
end
end
In the above example if my string_eastern only contains one element, say 'Canada', it will return the index value of every instance of 'Canada'. If I add more elements I expect it would return index values for every instance where string_index would match with a string contained in string_eastern. However I get no results at all if I add more elements.
Pretty much I wanted to check my string_index agaisnt string_eastern, if the values match then I want it to return that cell value. This works when string_eastern is only 1 element but does not work with more than 1.
To access cell contents, use the curly brackets {}. So if I wanted to access the first element of my cell, I would say this:
string = cell{1};
Read more on the MATLAB Documentation about cells to learn more and to answer any of your further questions.
If you use the length() function on an associative array, it will return the "largest index" in use within the array. So, if you have any keys which are not integers, length() will not return the actual number of elements within your array. (And this could happen for other reasons as well.)
Is there a more useful version of length() for finding the length of an associative array?
Or do I need to actually cycle through and count each element? I'm not sure how I would do that without knowing all of the possible keys beforehand.
If you have a flat array, then Array.MaxIndex() will return the largest integer in the index. However this isn't always the best because AutoHotKey will allow you to have an array whose first index is not 1, so the MaxIndex() could be misleading.
Worse yet, if your object is an associative hashtable where the index may contain strings, then MaxIndex() will return null.
So it's probably best to count them.
DesiredDroids := object()
DesiredDroids["C3P0"] := "Gold"
DesiredDroids["R2D2"] := "Blue&White"
count :=0
for key, value in DesiredDroids
count++
MsgBox, % "We're looking for " . count . " droid" . ( count=1 ? "" : "s" ) . "."
Output
We're looking for 2 droids.
I have a loop for example :
for my $something ( #place[1..$#thing] ) {
}
I don't get this statement 1..$#thing
I know that # is for comments but my IDE doesn't color #thing as comment. Or is it really just a comment for someone to know that what is in "$" is "thing" ? And if it's a comment why was the rest of the line not commented out like ] ) { ?
If it has other meanings, i will like to know. Sorry if my question sounds odd, i am just new to perl and perplexed by such an expression.
The $# is the syntax for getting the highest index of the array in question, so $#thing is the highest index of the array #thing. This is documented in perldoc perldata
.. is the range operator, and 1 .. $#thing means a list of numbers, from 1 to whatever the highest index of #thing is.
Using this list inside array brackets with the # sigill denotes that this is an array slice, which is to say, a selected number of elements in the #place array.
So assuming the following:
my #thing = qw(foo bar baz);
my #place = qw(home work restaurant gym);
then #place[1 .. $#thing] (or 1 .. 2) would expand into the list work, restaurant.
It is correct that # is used for comments, but not in this case.
it's how you define a range. From starting value to some other value.
for my $something ( #place[1..3] ) {
# Takes the first three elements
}
Binary ".." is the range operator, which is really two different
operators depending on the context. In list context, it returns a list
of values counting (up by ones) from the left value to the right
value. If the left value is greater than the right value then it
returns the empty list. The range operator is useful for writing
foreach (1..10) loops and for doing slice operations on arrays. In the
current implementation, no temporary array is created when the range
operator is used as the expression in foreach loops, but older
versions of Perl might burn a lot of memory when you write something
like this:
http://perldoc.perl.org/perlop.html#Range-Operators
I have a form with a table in it. In each row is a table cell with a hidden input item with the name of it starting with "hf_id_" followed by a number so that row 1's field has a name of "hf_id_1", row 2 is "hf_id_2" and so on. I need to search all of these fields for a particular value but I'm not quite sure how to get to the hidden fields. I know how to get to them when the full name is known but in this case I'm not sure if there's a way to get an array of these where name starts with "hf_id_". Thanks.
You can search elements with ^ (starting with) and $ (ending with), example:
$('input[name^="hf_id_"]');
So you can get all those elements like:
var elements = $('input[name^="hf_id_"]');
And you can iterate over them to search for a particular value like:
$('input[name^="hf_id_"]').each(function(){
if ($(this).val() === 'search value here')
{
// found..........
}
});
Or you could simply use
$('input[type="hidden"]');