WKWebview: how to prevent Laravel Page links from opening in safari? - swift

Question

I am new to swift.
I built a web application and serving it as an iOS app using WKWebView (this is for internal company use only).
In the web app, I used laravel pagination, this works properly on a browser and android webview.
what happens on iOS is, when I click the page number link inside the WKWebView, the link opens up in safari. What I want to do is open it on the same Webview.
This is my code inside ViewController.swift
import UIKit
import WebKit
class ViewController: UIViewController, WKNavigationDelegate {
var webView : WKWebView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
let url = URL(string: "https://domain-online.asia")!
let urlRequest = URLRequest(url: url)
webView.load(urlRequest)
let refresh = UIBarButtonItem(barButtonSystemItem: .refresh, target: webView, action: #selector(webView.reload))
toolbarItems = [refresh]
navigationController?.isToolbarHidden = false
}
override func loadView() {
let source: String = "var meta = document.createElement('meta');" +
"meta.name = 'viewport';" +
"meta.content = 'width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no';" +
"var head = document.getElementsByTagName('head')[0];" + "head.appendChild(meta);";
let script: WKUserScript = WKUserScript(source: source, injectionTime: .atDocumentEnd, forMainFrameOnly: true)
let userContentController: WKUserContentController = WKUserContentController()
let conf = WKWebViewConfiguration()
conf.userContentController = userContentController
userContentController.addUserScript(script)
webView = WKWebView(frame: CGRect.zero, configuration: conf)
webView.navigationDelegate = self
view = webView
}
func webView(webView: WKWebView!, createWebViewWithConfiguration configuration: WKWebViewConfiguration!, forNavigationAction navigationAction: WKNavigationAction!, windowFeatures: WKWindowFeatures!) -> WKWebView! {
if navigationAction.targetFrame == nil {
webView.load(navigationAction.request)
}
return nil
}}

Answer 1

Implement decidePolicyFor and set policy as below,
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: #escaping (WKNavigationActionPolicy) -> Void) {
guard navigationAction.navigationType == .linkActivated,
let url = navigationAction.request.url,
url.host?.contains("domain-online.asia") == false,
UIApplication.shared.canOpenURL(url) else {
decisionHandler(.allow)
return
}
UIApplication.shared.open(url)
decisionHandler(.cancel)
}