I have the following schema
I wanted to get all cars along with number of models for each car and number of remaining colors for each car.
I was able to get number of models but i am not able to get number of remaining colors for each car. I know i have to do Left [Outer] Join without Intersection. But its not working
I may also have model which does not have any colors. In such case there wont be any entry in ModelColors table
select
c.CarID,
c.CarName,
T1.[Num Of Models],
T2.[Remaining Colors]
from Cars c
LEFT JOIN
(
SELECT m.CarID, COUNT(1) AS 'Num Of Models'
FROM Models m
GROUP BY m.CarID
) AS T1 ON T1.CarID = c.CarID
LEFT JOIN
(
SELECT m1.CarID, COUNT(1) AS 'Remaining Colors'
FROM Colors col
LEFT JOIN ModelColors mc on mc.ColorID = col.ColorID
LEFT JOIN Models m1 on m1.ModelID = mc.ModelID
WHERE mc.ColorID IS NULL
GROUP BY m1.CarID
) AS T2 ON T2.CarID = c.CarID
Your from/join clause in the second derived table (T2) is wrong.
You should use Models and ModelColors only:
SELECT m1.CarID, COUNT(1) AS 'Remaining Colors'
FROM Models m
LEFT JOIN ModelColors mc
ON m.ModelID = mc.ModelID
The entire query should look like this:
SELECT
c.CarID,
c.CarName,
T1.[Num Of Models],
T2.[Remaining Colors]
FROM Cars c
LEFT JOIN
(
SELECT m.CarID, COUNT(1) AS 'Num Of Models'
FROM Models m
GROUP BY m.CarID
) AS T1 ON T1.CarID = c.CarID
LEFT JOIN
(
SELECT m1.CarID, COUNT(1) AS 'Remaining Colors'
FROM Models m
LEFT JOIN ModelColors mc
ON m.ModelID = mc.ModelID
) AS T2 ON T2.CarID = c.CarID
Since you only want to count the colors, you don't need the Colors table at all for this query.
Related
I have the following query:
SELECT array_agg(DISTINCT p.id) AS price_ids,
array_agg(p.name) AS price_names
FROM items
LEFT JOIN prices p on p.item_id = id
LEFT JOIN third_table t3 on third_table.item_id = id
WHERE id = 1;
When I LEFT JOIN the third_table all my prices are duplicated.
I'm using DISTINCT inside ARRAY_AGG() to get the ids without dups, but I want the names without dups aswell.
If I use array_agg(DISTINCT p.name) AS price_names, it will return distinct values based on the name, not the id.
I want to do something similar to array_agg(DISTINCT ON (p.id) p.name) AS price_names, but it is invalid.
How can I use DISTINCT ON inside ARRAY_AGG()?
Aggregate first, then join:
SELECT p.price_ids,
p.price_names,
t3.*
FROM items
LEFT JOIN (
SELECT pr.item_id,
array_agg(pr.id) AS price_ids,
array_agg(pr.name) AS price_names
FROM prices pr
GROUP BY pr.item_id
) p on p.item_id = items.id
LEFT JOIN third_table t3 on third_table.item_id = id
WHERE items.id = 1;
Using a lateral join might be faster if you only pick a single item:
SELECT p.price_ids,
p.price_names,
t3.*
FROM items
LEFT JOIN LATERAL (
SELECT array_agg(pr.id) AS price_ids,
array_agg(pr.name) AS price_names
FROM prices pr
WHERE pr.item_id = items.id
) p on true
LEFT JOIN third_table t3 on third_table.item_id = id
WHERE items.id = 1;
I have a requirement to pick up data that is in more than one place and I have some form of recognition if using the coalesce function. Basically I am looking to coalesce the join itself but looking online its seems as if i can only do this on the fields.
So we have a Products and Suppliers table, we also have these as a temp table so in total 4 tables (products, tempproducts, suppliers, tempsuppliers). In the suppliers and products table is where we store our products and suppliers and their temptables we store any new suppliers/products. We also have a tempsupplierproduct which joins new suppliers to new products. However we can end in a situation where a new supplier has an existing product so the new supplier will be in the tempsuppliers table and its product is in the products table NOT the tempproducts as it is not new, we will also have a new tempsupplierproduct to join the two up.
So i want a query which looks in the tempsupplierproducts table and then gets basic information about the supplier and products. To do this i am using a coalesce.
SELECT DISTINCT SP.*, COALESCE(P.Product, PD.Product) 'Product', COALESCE(S.Supplier, SU.Supplier) 'Supplier'
FROM tempsupplierproduct SP
LEFT JOIN tempProduct P ON SP.ProductCode = P.Code
LEFT JOIN Products PD ON SP.ProductCode = PD.Code
LEFT JOIN tempSupplier S ON SP.SupplierCode = S.Code
LEFT JOIN Suppliers SU ON SP.SupplierCode = SU.Code
Now while this works, something at the back of my head tells me it is not entirely right, ideally i want if data is not in table A then join to table B. I have seen maybe coalescing inside the join itself but I am unsure how to do this
LEFT JOIN Suppliers Su ON SP.SupplierCode = COALESCE(S.Code, SU.Code)
maybe away, but I am confused by this, all it is saying is use code in temptable if not there then use supplier code. So what would this mean if we have a code in the temptable, will this try to join on it, if so then this is incorrect also.
Any help is appreciated
You can union the two suppliers tables together and then join them in one go like this. I'm assuming that there are no duplicates between the two tables in this case but with a bit of extra work that could be resolved as well.
WITH AllSuppliers AS
(
SELECT Code, Supplier FROM Suppliers
UNION ALL
SELECT Code, Supplier FROM tempSupplier
)
SELECT DISTINCT SP.*, COALESCE(P.Product, PD.Product) 'Product', S.Supplier
FROM tempsupplierproduct SP
LEFT JOIN tempProduct P ON SP.ProductCode = P.Code
LEFT JOIN Products PD ON SP.ProductCode = PD.Code
LEFT JOIN AllSuppliers S ON SP.SupplierCode = S.Code
If you need to handle duplicates in the two suppliers tables then an approach like this should work, essentially we rank the duplicates and then pick the highest ranked result. For two tables you could use a full outer join between the two but this approach will scale to any number of tables.
WITH AllSuppliers AS
(
SELECT Code, Supplier, 1 AS TablePriority FROM Suppliers
UNION ALL
SELECT Code, Supplier, 2 AS TablePriority FROM tempSupplier
),
SuppliersRanked AS
(
SELECT Code, Supplier,
ROW_NUMBER() OVER (PARTITION BY Code ORDER BY TablePriority) AS RowPriority
FROM AllSuppliers
)
SELECT DISTINCT SP.*, COALESCE(P.Product, PD.Product) 'Product', S.Supplier
FROM tempsupplierproduct SP
LEFT JOIN tempProduct P ON SP.ProductCode = P.Code
LEFT JOIN Products PD ON SP.ProductCode = PD.Code
LEFT JOIN SuppliersRanked S ON SP.SupplierCode = S.Code
AND RowPriority = 1
You can absolutely join on a coalesced field. Here is a snippet from one of my production views:
LEFT JOIN [Portal].tblHelpdeskresource supplier ON PO.fld_str_SupplierID = supplier.fld_str_SupplierID
-- Job type a
LEFT JOIN [Portal].tblHelpDeskFault HDF ON PO.fld_int_HelpdeskFaultID = HDF.fld_int_ID
-- Job Type b
LEFT JOIN [Portal].tblProjectHeader PH ON PO.fld_int_ProjectHeaderID = PH.fld_int_ID
LEFT JOIN [Portal].tblPPMScheduleLine PSL ON PH.fld_int_PPMScheduleRef = PSL.fld_int_ID
-- Managers (used to be separate for a & b type, now converged)
LEFT JOIN [Portal].uvw_HelpDeskSiteManagers PSM ON COALESCE(PSL.fld_int_StoreID,HDF.fld_int_StoreID) = PSM.PortalSiteId
LEFT JOIN [Portal].tblHelpdeskResource PHDR ON PSM.PortalResourceId = PHDR.fld_int_ID
This query was taken from a Rails application log...I'm trying to edit a massive postgresql statement I didn't write....If I don't add a distinct keyword after the SELECT, 2 duplicate rows appear for each braintree account. Why is this and is there another way to avoid having to use the distinct to avoid duplicates?
EDIT: I understand what distinct is supposed to do, the reason I'm asking is that it doesn't generate duplicates for other toy lines. By other toy lines, this query is building a "table" for a particular toy id (this specific example toys.id = 12). How do I figure out where the duplicate rows are being generated?
SELECT accounts.braintree_account_id as braintree_account_id,
accounts.braintree_account_id as braintree_account_id, format('%s %s', addresses.first_name,
addresses.last_name) as shipping_address_full_name,
users.email as email, addresses.line_1 as shipping_address_line_1,
addresses.line_2 as shipping_address_line_2, addresses.city as
shipping_address_city, addresses.state as shipping_address_state,
addresses.zip as shipping_address_zip_code, addresses.country
as shipping_address_country, CASE WHEN xy_shirt IS NULL THEN '' ELSE xy_shirt END, plans.name as plan_name, toys.sku as sku, to_char(accounts.created_at, 'MM/DD/YYYY HH24:MM:SS') as
account_created_at,
to_char(accounts.next_assessment_at, 'MM/DD/YYYY HH24:MM:SS') as account_next_assessment_at,
accounts.account_status as account_status FROM \"accounts\" INNER JOIN \"addresses\" ON
\"addresses\".\"id\" = \"accounts\".\"shipping_address_id\" AND \"addresses\".\"type\" IN
('ShippingAddress') LEFT OUTER JOIN shipping_methods ON
shipping_methods.account_id = accounts.id LEFT OUTER JOIN plans ON
accounts.plan_id = plans.id
LEFT OUTER JOIN users ON
accounts.user_id = users.id LEFT OUTER JOIN toys ON plans.toy_id = toys.id
LEFT OUTER JOIN account_variations ON accounts.id =
account_variations.account_id LEFT OUTER JOIN variations ON
account_variations.variation_id = variations.id
LEFT OUTER JOIN
choice_value_variations ON variations.id =
choice_value_variations.variation_id
LEFT OUTER JOIN choice_values ON
choice_value_variations.choice_value_id = choice_values.id LEFT OUTER
JOIN choice_types ON choice_values.choice_type_id = choice_types.id
LEFT
OUTER JOIN choice_type_toys ON choice_type_toys.toy_id = toys.id
AND choice_type_toys.choice_type_id = choice_types.id
LEFT OUTER JOIN
(SELECT * FROM crosstab('SELECT accounts.id, choice_types.id,
choice_values.presentation FROM accounts\n
LEFT JOIN account_variations ON
accounts.id=account_variations.account_id\n
LEFT JOIN variations ON account_variations.variation_id=variations.id\n
LEFT JOIN choice_value_variations ON
variations.id=choice_value_variations.variation_id\n
LEFT JOIN choice_values ON
choice_value_variations.choice_value_id=choice_values.id\n
LEFT JOIN choice_types ON choice_values.choice_type_id=choice_types.id
ORDER BY 1,2',\n 'select distinct choice_types.id
from choice_types JOIN choice_values ON choice_values.choice_type_id =
choice_types.id JOIN choice_value_variations ON
choice_value_variations.choice_value_id = choice_values.id JOIN
variations ON choice_value_variations.variation_id = variations.id JOIN choice_type_toys ON choice_type_toys.choice_type_id = choice_types.id JOIN toys ON toys.id = choice_type_toys.toy_id
where toys.id=12 ORDER
BY choice_types.id ASC')\n
AS (account_id int, xy_shirt
VARCHAR)) account_variation_view\n ON
accounts.id=account_variation_view.account_id WHERE
\"accounts\".\"account_status\" = 'active' AND
\"addresses\".\"flagged_invalid_at\" IS NULL AND \"toys\".\"id\" = 12
AND (NOT EXISTS (SELECT \"account_skipped_months\".* FROM
\"account_skipped_months\" WHERE
\"account_skipped_months\".\"month_year\" = 'JUL2016' AND
(account_skipped_months.account_id = accounts.id)))"
The purpose of using DISTINCT in a SELECT statement is to eliminate duplicate rows.
these are the five given tables
http://i58.tinypic.com/53wcxe.jpg
this is the recomanded result
http://i58.tinypic.com/2vsrts7.jpg
please help how can i write a query to have this result.
no idea how!!!!
SELECT K.* , COUNT (A.Au_ID) AS AnzahlAuftr
FROM Kunde K
LEFT JOIN Auftrag A ON K.Kd_ID = A.Au_Kd_ID
GROUP BY K.Kd_ID,K.Kd_Firma,K.Kd_Strasse,K.Kd_PLZ,K.Kd_Ort
ORDER BY K.Kd_PLZ DESC;
SELECT COUNT (F.F_ID) AS AnzahlFahrt
FROM Fahrten F
RIGHT JOIN Auftrag A ON A.Au_ID = F.F_Au_ID
SELECT SUM (T.Ts_Strecke) AS SumStrecke
FROM Teilstrecke T
LEFT JOIN Fahrten F ON F.F_ID = T.Ts_F_ID
how to join these 3 in one?
Grouping on Strasse etc. is not necessary and can be quite expensive. What about this approach:
SELECT K.*, ISNULL(Au.AnzahlAuftr,0) AS AnzahlAuftr, ISNULL(Au.AnzahlFahrt,0) AS AnzahlFahrt, ISNULL(Au.SumStrecke,0) AS SumStrecke
FROM Kunde K
LEFT OUTER JOIN
(SELECT A.Au_Kd_ID, COUNT(*) AS AnzahlAuftr, SUM(Fa.AnzahlFahrt1) AS AnzahlFahrt, SUM(Fa.SumStrecke2) AS SumStrecke
FROM Auftrag A LEFT OUTER JOIN
(SELECT F.F_Au_ID, COUNT(*) AS AnzahlFahrt1, SUM(Ts.SumStrecke1) AS SumStrecke2
FROM Fahrten F LEFT OUTER JOIN
(SELECT T.Ts_F_ID, SUM(T.Ts_Strecke) AS SumStrecke1
FROM Teilstrecke T
GROUP BY T.Ts_F_ID) AS Ts
ON Ts.Ts_F_ID = F.F_ID
GROUP BY F.F_Au_ID) AS Fa
ON Fa.F_Au_ID = A.Au_ID
GROUP BY A.Au_Kd_ID) AS Au
ON Au.Au_Kd_ID = K.Kd_ID
My database has following structure:
Every Region (CountryStates) can have many cities (Areas). Every Area can have many tourist attractions or points of interest (POIs). I want to get list of how many Areas and Attractions are there in each Region. If there is none, I want to display 0.
This is my query:
SELECT Tab1.Reg AS Reg, CountAreas, CountPois
FROM
(SELECT
c.Name AS Reg,
COUNT(a.Id) AS CountAreas
FROM
CountryStates as c LEFT JOIN
Areas AS a ON a.CountryStates_Id = c.Id
GROUP BY c.Name
) as Tab1 left join
(SELECT
c1.Name AS Reg,
COUNT(p.Id) AS CountPois
FROM
CountryStates as c1 LEFT JOIN
Areas AS a ON a.CountryStates_Id = c1.Id LEFT JOIN
POIs AS p ON a.Id = p.Areas_Id
GROUP BY c1.Name
) as Tab2 on Tab1.Reg = Tab2.Reg
How can I make this query in just one SELECT?
This query returns the same result:
SELECT c.Name AS Reg,
COUNT(DISTINCT(a.Id)) AS CountAreas,
COUNT(p.Id) AS CountPois
FROM CountryStates as c
LEFT JOIN Areas as a ON a.CountryStates_Id = c.Id
LEFT JOIN POIs AS p ON a.Id = p.Areas_Id
GROUP BY c.Name