I'm using the command ls *Pattern*Date* Files.txt to get a list of files from FTP to my local text file.
I'm now required to get multiple patterned files (The Date and Pattern may come in different order). So when I try to add another line ls *Date*Pattern* Files.txt, this clears the FCCfiles.txt and I'm not able to get the first set of files.
Is there any command that can append the list of files rather than creating new files list?
You cannot append the listing to a file with ftp.
But you can merge multiple listings in PowerShell. I assume that you run ftp from PowerShell, based on your use of powershell tag.
In ftp script do:
ls *Pattern*Date* files1.txt
ls *Date*Pattern* files2.txt
And then in PowerShell do:
Get-Content files1.txt,files2.txt | Set-Content files.txt
(based on How do I concatenate two text files in PowerShell?)
Related
I am working on a script for auto deployment, where I need to replace my files with the same filenames.
For example, I have the following files in my current directory
deployment.properties
wrapper.conf
config.properties
Later, I will generate another set of files like this
deployment.properties.tokenized
wrapper.conf.tokenized
config.properties.tokenized
Lastly, I want to replace the existing config files (in the first code block) using the *.tokenized version and remove the tokenized files.
In Linux, the following can do the job. But I don't know how to do in Windows
for f in *tokenized;
do mv "$f" "`echo $f | sed s/tokenized//`";
done
I tried to use powershell's move-item, rename-item but still cannot figure out the right way to do it. Could somebody help? bat / powershell scripts are both welcomed. Using loop is also okay. Thank you.
It is almost the same code but in cmd / batch files we have access to the elements of the file name.
From command line
for %a in (*.tokenized) do move /y "%a" "%~na"
Or, for a batch file (you need to escape the for replaceable parameter)
for %%a in (*.tokenized) do move /y "%%a" "%%~na"
As the extension of the file (the text after the last dot) is .tokenized, when you request just the name (without extension) of the file being referenced (%%~na) you get the original file name.
This PowerShell script should do the job:
Get-ChildItem *.tokenized | % {
move $_.Name ([System.IO.Path]::GetFileNameWithoutExtension($_.Name)) -Force
}
I have got a robust script which gets, parse and uses some data from .csv file. To run the script I can use
.\script.ps1 -d data_file.csv
The thing is I cannot interfere into script itself that is why i need to create some kind of a wrapper which will create new csv file and use script.ps1 with a new made file. I am wondering if there is a possibility to create a csv file as an object which will be passed directly to the command like this
.\script.ps1 -d csv_file_as_object.csv
without creating file in some path directory.
What you'd need in this case is the equivalent of Bash's process substitution (<(...)), which, in a nutshell, would allow you to present a command's output as the content of a temporary file whose path is output:
.\scripts.ps1 -d <(... | ConvertTo-Csv) # !! does NOT work in PowerShell
Note: ... | ConverTo-Csv stands for whatever command is needed to transform the original CSV in-memory.
No such feature exists in PowerShell as of Windows PowerShell v5.1 / PowerShell Core v6.1, but it has been proposed.
If .\scripts.ps1 happens to also accept stdin input (via pseudo-path - indicating stdin input), you could try:
... | ConvertTo-Csv | .\script.ps1 -d -
Otherwise, your only option is to:
save your modified CSV data to a temporary file
pass that temporary file's path to .\script.ps1
remove the temporary file.
Okay so I want to know how I would go about doing this, using grep to locate .txt files named "cocacola1", "cocacola2", "cocacola3" & then copying them to another directory. So searching for files named "cocacola" &/even if it contains other characters within the file name to then copy them to another directory/location.
You can just use unix find. Assuming the files you're searching for are in 'source' and you want to copy to 'destination':
find source -name '*cocacola*' -exec cp {} destination \;
I put the wildcard '*' before and after cocacola since you said other characters might exist in the file name.
Suppose I have a directory structure like
C:\Users\Desktop\abc\d
I want to rar archive the abc folder so that the structure of rar is:
abc\d
When I try using powershell to archive, winrar replicates the full path inside the archive, like:
\Users\Desktop\abc\d
I dont want the full path to be created inside the archive
Here's the script:
https://gist.github.com/saurabhwahile/50f1091fb29c2bb327b7
What am I doing wrong?
Use the command line:
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc"
Rar.exe is the console version of WinRAR stored in same directory as WinRAR.exe. You can use this command line also with WinRAR.exe if you want to see the compression process in a graphic window.
a is the command and means add files to archive.
-r is a switch to recursively add all files and subdirectories including empty subdirectories to the archive.
-ep1 is another switch which results in execluding base directory.
For this command line the base directory is "C:\Users\Desktop\" and therefore the created archive Test.rar contains only abc and all files and subdirectories in directory abc which is what you want.
One more hint: Using the command line
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc\"
results in adding all files and subdirectories of directory abc to the archive, but without directory name abc being also stored in the archive. The backslash at end makes this difference.
In other words: On using switch -ep1 everything up to last backslash in file/directory specification is not added to the archive.
For more information about available switches see the text file Rar.txt in the program files directory of WinRAR.
occasionally I run a backup of my phpbb forum files from the Shell command line:
zip -r forum_backup ~/public_html/forum/*
I'd like to add date elements to the file name, so that the zip file created is automatically formed as
forum_backup_05182013.zip
any other similar current date format would also be acceptable
now=$(date +"%m%d%Y")
zip -r forum_backup_$now ~/public_html/forum/
Without defining a variable first you can do it in one line with
zip -r "forum_backup_$(date +"%Y-%m-%d").zip" filelist
As taken from here
the following shell command, change the format as you want
FORMAT="%Y%m%d"
_DATE=$(date +"$FORMAT" )
zip -r "forum_bakcup_${_DATE}" ~/public_html/forum/*