Powershell Unzip One Specific Folder in a File with Dynamic Name - powershell

Question

I found a piece of code here that almost does what I need, which is extract just one folder from an archived file.
The only issue I have is that the archive name changes month on month, therefore I wanted to use a wildcard. Once a wildcard is specified (* in $zipfile), the script does not work for me.
I would be grateful for any suggestions.
[Reflection.Assembly]::LoadWithPartialName('System.IO.Compression.FileSystem') | Out-Null
$zipfile = 'C:\ALL\Debtor*.zip'
$folder = 'tmp\st\sd'
$dst = 'C:\ALL\ZipOutput'
[IO.Compression.ZipFile]::OpenRead($zipfile).Entries | ? {
$_.FullName -like "$($folder -replace '\\','/')/*.*"
} | % {
$file = Join-Path $dst $_.FullName
$parent = Split-Path -Parent $file
if (-not (Test-Path -LiteralPath $parent)) {
New-Item -Path $parent -Type Directory | Out-Null
}
[IO.Compression.ZipFileExtensions]::ExtractToFile($_, $file, $true)

Answer 1

Try this out for size. Just use Get-ChildItem to locate the zip file in your ALL directory.
[Reflection.Assembly]::LoadWithPartialName('System.IO.Compression.FileSystem') | Out-Null
$zipfile = Get-ChildItem -Path C:\ALL\ -Filter *.zip | Where-Object {$_.Name -like "Debtor*"} | Select-Object -ExpandProperty FullName
$folder = 'tmp\st\sd\'
$dst = 'C:\ALL\ZipOutput'
[IO.Compression.ZipFile]::OpenRead($zipfile).Entries | Where-Object {
$_.FullName -like "$($folder -replace '\\','/')/*.*"
} | ForEach-Object {
$file = Join-Path $dst $_.FullName
$parent = Split-Path -Parent $file
if(-not (Test-Path -LiteralPath $parent)) {
New-Item -Path $parent -Type Directory | Out-Null
}
[IO.Compression.ZipFileExtensions]::ExtractToFile($_, $file, $true)
}
I am also assuming that the archive name changes but there are not multiple archives with that name. If there are you will need to wrap everything in a Foreach($zip in $zipfile){ ... }