I have a bash script that returns an NLB cname. I want to use the returned cname as an input for my api-gateway integration.
I was deploying this code in a terraform template:
#!/bin/bash
nlbcname=$(aws-env terraform output nlb_arn | grep arn | awk '$1=$1' FS="/" OFS=":" | awk 'BEGIN{ VAR1="elb";VAR2="amazonaws.com"; FS=":"; OFS="."} {print $8,$9,VAR1,$4,VAR2}' | sed -e 's/\./-/')
echo -n "{\"nlburl\":\"${nlbcname}\"}"
But I get
Error refreshing state: 1 error occurred:
* data.external.nlbcname: 1 error occurred:
* data.external.nlbcname: data.external.nlbcname: command "bash" produced invalid JSON: invalid character '\r' in string literal
Related
Problem
I'm trying to emit a hex string like:
echo hello | hexdump -ve '/1 "_%02X"' ; echo
but with % instead.
Actual vs Expected
echo hello | hexdump -ve '/1 "%%%02X"' ; echo
fails with
hexdump: bad conversion character %%
Question
Is there any way to escape % in hexdump format string?
I don't see any way to get hexdump to emit a '%' character directly. Perhaps you could continue to emit the '_' character and then pipe the result through sed to convert the '_' into a '%'. Something like this:
echo hello | hexdump -ve '/1 "_%02X"' | sed -e 's/_/%/g'
which produces:
%68%65%6C%6C%6F%0A
The goal is to insert the following complex lines before a specific pattern in a file:
NDPI_VERSION_SHORT=$(cat Makefile | grep -P "^NDPI_VERSION_SHORT = " | sed -E 's|^NDPI_VERSION_SHORT = (.*)$|\1|g') \
NDPI_VERSION_SHORT=${NDPI_VERSION_SHORT//[[:space:]]/} \
NDPI_MAJOR=$(cat Makefile | grep -P "^NDPI_MAJOR = " | sed -E 's|^NDPI_MAJOR = (.*)$|\1|g') \
NDPI_MAJOR=${NDPI_MAJOR//[[:space:]]/}
I unsuccessfully tried the following:
sed -i '/pattern/i \
NDPI_VERSION_SHORT=$(cat Makefile | grep -P "^NDPI_VERSION_SHORT = " | sed -E \'s|^NDPI_VERSION_SHORT = (.*)$|\1|g\') \
NDPI_VERSION_SHORT=${NDPI_VERSION_SHORT\/\/[[:space:]]\/} \
NDPI_MAJOR=$(cat Makefile | grep -P "^NDPI_MAJOR = " | sed -E \'s|^NDPI_MAJOR = (.*)$|\1|g\') \
NDPI_MAJOR=${NDPI_MAJOR\/\/[[:space:]]\/}' file
bash: syntax error near unexpected token `('
I also tried to quote all inserted lines leading to the same result.
What am I doing wrong?
This should work:
sed "/pattern/i \
NDPI_VERSION_SHORT=\$\(cat Makefile | grep -P \"^NDPI_VERSION_SHORT = \" | sed -E 's|^NDPI_VERSION_SHORT = \(.*\)\$|\\\1|g'\) \\\ \n\
NDPI_VERSION_SHORT=\${NDPI_VERSION_SHORT//[[:space:]]/} \\\ \n\
NDPI_MAJOR=\$\(cat Makefile | grep -P \"^NDPI_MAJOR = \" | sed -E 's|^NDPI_MAJOR = \(.*\)\$|\\\1|g'\) \\\ \n\
NDPI_MAJOR=\${NDPI_MAJOR//[[:space:]]/}" file
The problem is the single quote within the inserted text, which will end the sed script and which cannot be escaped. You can use single quotes, though, if you use double quotes to enclose the script. This, however, means you'll need to escape quite a lot of things in your text: The $, ", (, ). Since the shell itself uses up a backslash for escaping, you need to write \\\ where you have a \. And the line break is achieved via a \n. Note that the / does not need to be escaped since sed does not use it as delimiter here.
I have the following script to extract text inside "reportBody" text, but I need also to decode this text from a new file to base64. How can I do this?
Here's a script:
cat $1 | tr "\n" "|" | grep -o '<reportBody>.*</reportBody>' | sed 's/\(<reportBody>\|<\/reportBody>\)//g' | sed 's/|/\n/g' | sed '/^\s*$/d' > $2
tried :
cat $1 | tr "\n" "|" | grep -o '<reportBody>.*</reportBody>' | sed 's/\(<reportBody>\|<\/reportBody>\)//g' | sed 's/|/\n/g' | sed '/^\s*$/d' | base64 -d $2 > $2
but it doesn't decode it,
Can I overwrite the same file or at least save decoded text in a new one? without calling addition modules from python etc.
Note: File contains 20k+ symbols to decode.
I'm using this code to get all titles from urls with http://something.txt:
#!/usr/bin/perl -w
$output = `cat source.html | grep -o '<a .*href=.*>' | grep -E 'txt' | sed -e 's/<a /\n<a /g' | sed -e 's/<a .*title="//' | cut -f1 -d '"'`;
print("$output");
When i run this on perl i get the error:
sed: -e expression #1, char 6: unterminated `s' command
The error is related with this portion of code:
sed -e 's/<a /\n<a /g'
In backquotes, Perl uses the same rules as in double quotes. Therefore, \n corresponds to a newline; you have to backslash the backslash to pass literal \ to the shell:
`sed -e 's/<a /\\n<a /g'`
I'm having some trouble with backtics and pipe in perl. I have following code:
my #arr_lsdev = `lsdev -C | grep inet | awk '{print \$1}'` ;
print Dumper #arr_lsdev ;
But I get following error:
sh[2]: 0403-057 Syntax error : `|' is not expected
I'm guessing it has something to with my escape commands. I have tried escaping the | but it still results in the same error.
OS: AIX
Shell: KSH
Notice that the error is on line 2. You are actually executing
my #arr_lsdev = `lsdev -C | grep inet
| awk '{print \$1}'` ;
You can reduce the number of pipes:
my #arr_lsdev = map {(split ' ')[0]} grep {/inet/} `lsdev -C`;