I have Grp_ids feild which i need to assign "Pass" or "Fail" based on the results of measure_ids
For example : If one of the measure_ids in the group is failed, i want the whole group to be failed.
Thank you.
Define Grp_Result as MIN([Measure_Results] = "Pass")
That will be True if Measure_Results = "Pass" for every data row for your selected dimensions (Grp_Ids and Measure_is in your example). If you can have null values in your Measure_Results column and if you want to treat those nulls as a Fail, then would use instead MIN(IFNULL([Measure_Results] = "Pass"), False)
This works because Tableau treats True as greater than False. So MAX() holds if is satisfied for EVERY data row, and MAX() holds if is satisfied for ANY data row.
You can simplify a bit further by using boolean values in place of strings to begin with to represent whether a record passed or failed.
This should do the trick -
IIF({ FIXED [Grp_ids]: SUM(IIF([Measure_Results] = 'Pass',0,1)) }>0,'Fail','Pass')
Sum the failures by GRP_ID. If the sum is greater than 0 (GRP_ID contains a Fail) then Fail the entire GRP_ID.
Related
I am trying to remove the formula from a column in a existing sheet with python.
I tryed to set my formula to None using the column object (column.formula = None)
It does not work and my column object remains unchanged. Anyone have inputs to solve this issue ? Thank you !
This took me a bit to figure out, but seems like I've found a solution. Turns out that this is a 2-step process:
Update the column object to remove the formula (by setting column.formula to an empty string).
For each row in the sheet, update the cell within that column to remove the formula (set cell.value to an empty string and cell.formula to None).
Completing the STEP 1 will remove the formula from the column object -- but that cell in each row will still contain the formula. That's why STEP 2 is needed -- STEP 2 will remove the formula from the individual cell in each row.
Here's some example code in Python that does what I've described. (Be sure to update the id values to correspond to your sheet.)
STEP 1: Remove formula from the Column
column_spec = smartsheet.models.Column({
'formula': ''
})
# Update column
sheetId = 3932034054809476
columnId = 4793116511233924
result = smartsheet_client.Sheets.update_column(sheetId, columnId, column_spec)
STEP 2: Remove the formula from that cell in each row
Note: This sample code updates only one specific row -- in your case, you'll need to update every row in the sheet. Just build a row object for each row in the sheet (like shown below), then call smartsheet_client.Sheets.update_rows once, passing in the array of row objects that you've built corresponding to all rows in the sheet. By doing things this way, you're only calling the API once, which is the most efficient way of doing things.
# Build new cell value
new_cell = smartsheet.models.Cell()
new_cell.column_id = 4793116511233924
new_cell.value = ''
new_cell.formula = None
# Build the row to update
row_to_update = smartsheet.models.Row()
row_to_update.id = 5225480965908356
row_to_update.cells.append(new_cell)
# Update row
sheetId = 3932034054809476
result = smartsheet_client.Sheets.update_rows(sheetId, [row_to_update])
I created a routing problem and added some dimension to it. A solution assignment is found and I want to know the cumulative value at each index. I noticed that the CumulVar of an assignment does not only have a Value method but also Min and Max methods. Apparently the cumulative variables are implemented in such a way that they can represent intervals. I can see how setting
slack_max>0
fix_start_cumul_to_zero=False
introduces an ambiguity for the cumulative variables as their is a choice in how to start and how much slack to add at each stop. But
Question: How are the Min and Max at each index computed?
You can get the Min and Max range of a given node index from solution.Min(dimension.Cumulvar(index))
Note you'll get Min and Max exactly the same when slack_max=0 unless you know something I don't ;)
Assuming you are using an output solution object solution and a time dimension time_dimension, this will store em as a dict with min-max tuples, you may wish to adapt the output format however you wish:
time_dict = {}
for vehicle_id in range(num_vehicles):
vehicle_time_dict={}
index = routing.Start(vehicle_id)
start_time = solution.Min(time_dimension.CumulVar(index))
vehicle_time_dict[index]=(index_min,index_max)
while not routing.isEnd(index):
previous_index = index
index = solution.Value(routing.NextVar(index))
index_min = solution.Min(time_dimension.CumulVar(index))
index_max = solution.Max(time_dimension.CumulVar(index))
vehicle_time_dict[index]=(index_min,index_max)
time_dict[vehicle_id]=vehicle_time_dict
routing.IsEnd(index) returns True if it's the last index of that vehicle's route (or anywhere after the last index, so if it's 10 nodes long:
routing.IsEnd(8) will return False,
routing.IsEnd(9) will return True,
routing.IsEnd(10) will also return True, etc)
I am using a MongoDB for a new app I am creating and I only need certain data from it. I require the following fields: current (boolean), position, sector, and name. The position field is populated with one of four values - "cash, SPVR, OFF, and training", while the sector field has one of two values - "Break or Working". I want a query that will give me all records where the following conditions exist:
1. current = TRUE
2. Position = "SPVR" or "CASH" OR Sector = "BREAK" and
3. Name is not NULL
The problem I have is that there are hundreds of records that have a value of BREAK, but most of them do not have a value in the Name field. I don't want any records that do not have a name associated with them. So in that respect, in line 2 above, I'm guessing the OR could be AND?
This is mu current start at the Mongoid statement
get '/currentstate*' do
StateTransaction.where( current: true, :position.in =>["SPVR", "CASH"] ).to_json
end
Any help would be greatly appreciated.
Thanks!!
It should work
StateTransaction.where(current: true, :name.ne => ["",nil]).and(
StateTransaction.or(
{:position.in =>["SPVR", "CASH"]},
{sector: "BREAK"}
).selector
)
Following is arguably simpler:
sts = StateTransaction.where(current: true, :name.ne => ["",nil])
sts.any_of(:position.in => ["SPVR", "CASH"], sector: 'BREAK')
include "globals.mzn";
%Data
time_ID = [11,12,13,14,15];
eventId = [0011, 0012, 0013, 0021, 0022, 0031, 0041, 0051, 0061, 0071];
int:ntime = 5;
int:nevent = 10;
set of int: events =1..nevent;
set of int: time = 1..ntime;
array[1..nevent] of int:eventId;
array[1..nevent] of var time:event_time;
array[1..ntime] of int:time_ID;
solve satisfy;
constraint
forall(event in eventId)(
exists(t in time_ID)(
event_time[event] = t ));
output[ show(event_time) ];
I'm trying to assign times to an event using the code above.
But rather than randomly assign times to the events, it returns an error " array access out of bounds"
How can I make it select randomly from the time array?
Thank you
The error was because you tried to assign the index 11 (the first element in eventId array) in "event_time" array.
The assigment of just 1's is correct since you haven't done any other constraints on the "event_time" array. If you set the number of solutions to - say - 3 you will see other solutions. And, in fact, the constraint as it stand now is not really meaningful since it just ensures that there is some assignment to the elements in "event_time", but this constraint is handled by the domain of "event_time" (i.e. that all indices are in the range 1..ntime).
I'm trying to sum only the visible rows for a report and I know the format is:
=Sum( iif( <use the condition of the Visibility.Hidden expression>, 0, Fields!A.Value))
In my report, I've set row visbility to:
=IIF(CInt(Fields!EM_ET.Value)=1 Or CInt(Fields!EM_ET.Value)= 2,True,False)
Not exactly sure what I'm missing, but when I use this as an expression:
=Sum(IIF(CInt(Fields!EM_ET.Value)=1 Or CInt(Fields!EM_ET.Value)= 2,True,False),0,Fields!EM_ET.Value)
I get this following error: Value expression for textrun'FTD1.Paragraph[0].TextRuns[0]' has a scope argument that is not valid for aggregate function.
You are giving the True/False as output to the SUM() from your expression.You need to change your expression as,
=Sum(IIF(CInt(Fields!EM_ET.Value) = 1 Or CInt(Fields!EM_ET.Value)= 2,0,Fields!EM_ET.Value))
Thanks coder of code.
I am getting some error message if i am using '0', so i replaced with nothing it's working. I thought it would be helpful.
=SUM(IIF(ISNOTHING(Fields!value1.Value) OR ISNOTHING(Fields!value2.Value),NOTHING,Fields!value1.Value))
I was having similar issues. I know this question has a marked answer, however it isn't entirely correct.
The following contains the code from the "marked correct" answer:
=Sum(IIF(CInt(Fields!EM_ET.Value) = 1 Or CInt(Fields!EM_ET.Value) = 2,0,Fields!EM_ET.Value))
The following snipit of code contains the code from above, with a slight tweak:
=Sum(IIF(CInt(Fields!EM_ET.Value) = 1 Or CInt(Fields!EM_ET.Value) = 2,NOTHING,Fields!EM_ET.Value))
By changing the "0" to "NOTHING" this will resolve any lingering issues with your formula. The formula I was having issues with was returning "#Error" in the cell that was supposed to return the sum of the visible cells in the column within the row group.
My formula originally looked like this:
=IIF(Sum(Fields!VCBitType.Value) <> 0 OR (Parameters!Details.Value = "Detail"), Sum(IIF((Fields!VCBitType.Value = 0) and (Parameters!Details.Value = "Dangerous"),0,Fields!VC.Value)), "")
I altered my formula after seeing Hari's comment above:
=IIF(SUM(Fields!VCBitType.Value) <> 0 OR (Parameters!Details.Value = "Detail"), SUM(IIF((Fields!VCBitType.Value = 0) and (Parameters!Details.Value = "Dangerous"),NOTHING, Fields!VC.Value)), "")
I wanted to set the cells value to "" (empty) rather than hide the cell entirely or set that cell's value to "0" in my report (due to the fact that not displaying the cell entirely made the report look really funky). Because I did this, using a "0" in my formula conflicted with the value of the cell which was "" (empty), causing the formula to break. The only change I made was to alter "0" to "Nothing", this resolved the issue I was having with the cell's formula.