I have column with cell format date or time (DD.MM.YYYY HH:MM:SS) and values like
03.12.2013 14:01:49
04.12.2013 10:19:27
04.12.2013 12:44:56
04.12.2013 14:20:12
04.12.2013 18:30:21
I need those values converted to unix epoch (seconds since 1970). Somehow it feels like the values are not recognized as dates, but rather as strings. I tried different formats, had little luck with dates without time.
Operations performed on date data should be automatic provided that the cells are formatted as as a user defined DD.MM.YYYY HH:MM:SS in the 'Format' > 'Cells' > 'Numbers' tab.
If you're using the standard settings, LibreOffice Calc uses 12/30/1899 as it's default date. So the first step is getting the number of days between 12/30/1899 and 1/1/1970:
=(DATE(1970,1,1) - DATE(1899,12,30)) = 25569
Number of seconds in a day:
=(60 * 60 * 24) = 86400
If, for example, in cell A2 you have the date 03.12.2013 14:01:49. I subtract the difference between Calc's default date and the Unix Epoch we just calculated, and multiply it by the number of seconds in a day:
=(A2 - 25569) * 86400
The result is a value of 1363096909 which is the Epoch time in seconds. If you need it in milliseconds, multiply the equation by 1000.
If it's something you use a lot, you can create a custom function that does this. Go to Tools > Macros > Edit Macros, and type out the following into whichever module comes up:
REM ***** BASIC *****
Function EPOCH(date_cell)
EPOCH = (date_cell - 25569)*86400
End Function
Close the macro IDE, and now you can use your EPOCH() like any other function!
This formula worked for me, where the others above did not:
= DATE( 1970, 1, 1 ) + ( A1 / 86400 )
Related
I was wondering if someone could help me.
I'm very new at ASP I want to format the current date and time as follows:
yyyy-mm-dd hh:mm:ss
But all i can do is the following
Response.Write Date
Can someone help me out please.
Date formatting options are limited in Classic ASP by default, there is a function FormatDateTime() which can format your date is various ways based on the servers regional settings.
For more control over date formatting though there are built in date time functions
Year(date) - Returns a whole number representing the year. Passing Date() will give back the current year.
Month(date) - Returns a whole number between 1 and 12, inclusive, representing the month of the year. Passing Date() will return the current month of the year.
MonthName(month[, abbv]) - Returns a string indicating the specified month. Passing in Month(Date()) as the month will give back the current Month string. As suggested by #Martha
Day(date) - Returns a whole number between 1 and 31, inclusive, representing the day of the month. Passing Date() will return the current day of the month.
Hour(time) - Returns a whole number between 0 and 23, inclusive, representing the hour of the day. Passing Time() will return the current hour.
Minute(time) - Returns a whole number between 0 and 59, inclusive, representing the minute of the hour. Passing Time() will return the current minute.
Second(time) - Returns a whole number between 0 and 59, inclusive, representing the second of the minute. Passing Time() will return the current second.
IMPORTANT:
When formatting date / time values, always store the date / time value first. Also, any needed calculations (DateAdd() etc.) should be applied before attempting to format or you will get unexpected results.
The functions Month(), Day(), Hour(), Minute() and Second() all return whole numbers. Luckily there is an easy workaround that lets you pad these values quickly Right("00" & value, 2) what it does is append 00 to the front of the value then from the right take the first two characters. This ensures that all single digit values return prefixed with a 0.
Dim dd, mm, yy, hh, nn, ss
Dim datevalue, timevalue, dtsnow, dtsvalue
'Store DateTimeStamp once.
dtsnow = Now()
'Individual date components
dd = Right("00" & Day(dtsnow), 2)
mm = Right("00" & Month(dtsnow), 2)
yy = Year(dtsnow)
hh = Right("00" & Hour(dtsnow), 2)
nn = Right("00" & Minute(dtsnow), 2)
ss = Right("00" & Second(dtsnow), 2)
'Build the date string in the format yyyy-mm-dd
datevalue = yy & "-" & mm & "-" & dd
'Build the time string in the format hh:mm:ss
timevalue = hh & ":" & nn & ":" & ss
'Concatenate both together to build the timestamp yyyy-mm-dd hh:mm:ss
dtsvalue = datevalue & " " & timevalue
Call Response.Write(dtsvalue)
Note: You can build the date string in one call but decided to break it down into the three variables to make it easier to read.
How Can I Format Date
Example of Parsing a Date String (Answers provide approaches to taking a date string format and parsing it to a valid Date variable).
Format the date of the previous day format yyyymmdd with VBScript (Example of why storing date / time before performing formatting is important)
VBScript ISO8601 (Example of functions to construct an ISO 8601 compliant date string)
Is there a method in matlab to convert seconds from a known date to a standard date time format?
For example, if I have a vector of values shown as seconds from 1901/01/01, how would I convert them to a dateTime? In this case a value of 28125 would correspond to 1981/01/01. Is there an efficient method for doing this?
The numbers in your example do not make sense so it is not clear if your time is in seconds or days but since you asked for seconds I will use this.
What you want to achieve can be done using datenum function. This function returns the number of (fractional) days from 1/1/0000. So first you need to find your offset, e.g.:
offsetInDays = datenum(1901,1,1);
Next, you convert the date from seconds to days:
dateInDays = YourRequiredDateInSec * 3600 * 24;
Finally, you date is given by
RequiredDate = datestr(offsetInDays + dateInDays);
Is there a way to convert time= 08/10/2014 23:34:02 to Epoch seconds (array of numbers) in MATLAB?
So you want the Unix standard which can be calculated as follows:
InputDate=datenum('20141008 233402','yyyymmdd HHMMSS');
UnixOrigin=datenum('19700101 000000','yyyymmdd HHMMSS');
EpochSecond=round((InputDate-UnixOrigin)*86400);
>> 1412811242
EDIT for the OP's date format:
MYSTRING = '08/10/2014 23:34:02';
InputDate = datenum(MYSTRING,'dd/mm/yyyy HH:MM:SS');
UnixOrigin=datenum('19700101 000000','yyyymmdd HHMMSS'); %//This can stay the same, unless you want to change it for consistency.
EpochSecond=round((InputDate-UnixOrigin)*86400);
>>1412811242
I have date & time in intervals of one hour(3600 seconds) in number format, e.g 0,3600, 7200, 10800, 14400, 18000 etc.
I have starting date and time , e.g 0 corresponds to 2005/06/01 01:00 in 'yyyy/mm/dd HH:MM' format.
I am writing this data to Excel file, so I am looking for way where I can convert time given in Hour (in seconds) to Date Time (2005/06/01 01:00, 2005/06/01 02:00 etc) before writing to excel file.
I have explored 'datenum' and 'datestr' functions but they are not useful since I can not give them customised start time i.e (0 corresponds to 2005/06/01 01:00).
May be if some one can help me to point me in right direction.
tempMatrix = [NrID time_inSec ff X Y];
tempMatrix_dataCell=num2cell(tempMatrix);
col_header={'NrID','Time','ff','X','Y'};
data_for_xls_file=[col_header; tempMatrix_dataCell];
xlswrite('My_file.xls',data_for_xls_file);
time_inSec is column with values 0, 3600, 7200, 10800 etc which need to be converted.
When I use datenum it returns 7.3246e+05 so when I add 3600 to get 2005/06/01 02:00 and pass it to datestr it returns 2015/04/10 01:00.
temp_time = datenum('2005/06/01 01:00','yyyy/mm/dd HH:MM')
This works with a given start time:
startTime = datenum('2005/06/01 01:00', 'yyyy/mm/dd HH:MM'); % Define start time.
currentTime = datenum('2005/06/01 02:00', 'yyyy/mm/dd HH:MM'); % Current time.
timePassedHours = (currentTime - startTime) * 24; % Time that has passed in hours.
display(timePassedHours); % Print the output.
I have some data files with Unix timestamps (in this case, number of milliseconds since Jan 1, 1970 00:00 UTC). I would like to convert these to human-friendly date/time strings (e.g. 31-Aug-2012 11:36:24) in Matlab. Is there an easy way to do this in Matlab, or am I better off using an external library (e.g. java.text.SimpleDateFormat)?
How about
date = datestr(unix_time/86400 + datenum(1970,1,1))
if unix_time is given in seconds, unix_time/86400 will give the number of days since Jan. 1st 1970. Add to that the offset used by Matlab's datenum (datenum(0000,1,1) == 1), and you have the amount of days since Jan. 1st, 0000. This can be easily converted to human-readable form by Matlab's datestr.
If you have milliseconds, just use
date = datestr(unix_time/86400/1000 + datenum(1970,1,1))
Wrapped in functions, these would be
function dn = unixtime_to_datenum( unix_time )
dn = unix_time/86400 + 719529; %# == datenum(1970,1,1)
end
function dn = unixtime_in_ms_to_datenum( unix_time_ms )
dn = unix_time_ms/86400000 + 719529; %# == datenum(1970,1,1)
end
datestr( unixtime_to_datenum( unix_time ) )
Newer versions of MATLAB (verified in R2015a) have a datetime type that is useful for working with and formatting dates and times. You can convert UNIX timestamps into a MATLAB datetime with
dt = datetime( unix_time, 'ConvertFrom', 'posixtime' );
and then use datestr as before for formatting as a string
datestr( dt )