Is there any way to group by continious values - postgresql

I have data from car gps tracker and I need to find parking and movement periods
Now every row have id of parking or movement in table
+------------+-------+----------+---------+------------+
| time | speed | ignition | trip_id | parking_id |
+------------+-------+----------+---------+------------+
| 05:48:50 | 0 | false | 0 | 300 |
| 05:49:20 | 0 | false | 0 | 300 |
| 05:49:20 | 10 | true | 300 | 0 |
| 05:50:01 | 20 | true | 300 | 0 |
| 05:51:20 | 17 | true | 300 | 0 |
| 05:51:20 | 0 | false | 0 | 301 |
| 05:52:40 | 0 | false | 0 | 301 |
| 05:52:40 | 12 | true | 301 | 0 |
| 05:52:50 | 22 | true | 301 | 0 |
| 05:53:00 | 30 | true | 301 | 0 |
| 05:53:30 | 40 | true | 301 | 0 |
| 05:53:30 | 0 | false | 0 | 302 |
| 05:55:00 | 0 | false | 0 | 302 |
+------------+-------+----------+---------+------------+
SELECT min(time) as time_start, max(time) as time_end, trip_id, parking_id
FROM 'tablename' GROUP BY trip_id, parking_id
result is
+------------+----------+---------+------------+
| time start | time end | trip id | parking id |
+------------+----------+---------+------------+
| 05:48:50 | 05:49:20 | 0 | 300|
| 05:49:20 | 05:51:20 | 300| 0 |
| 05:51:20 | 05:52:40 | 0 | 301|
| 05:52:40 | 05:53:30 | 301| 0 |
| 05:53:30 | 05:55:00 | 0 | 302|
+------------+----------+---------+------------+
How should I do group by so as not to use parking_id and trip_id. But generate parking ids and trip ids. And the final result must be:
+------------+----------+---------+------------+
| time start | time end | trip id | parking id |
+------------+----------+---------+------------+
| 05:48:50 | 05:49:20 | 0 | 1 |
| 05:49:20 | 05:51:20 | 1 | 0 |
| 05:51:20 | 05:52:40 | 0 | 2 |
| 05:52:40 | 05:53:30 | 2 | 0 |
| 05:53:30 | 05:55:00 | 0 | 3 |
+------------+----------+---------+------------+

Related

tableau calculate cumulative value with condition

I have a tableau table with columns like this:
| ID | ww | count_flag |
| 1 | ww1 | 0 |
| 1 | ww2 | 1 |
| 1 | ww3 | 1 |
| 1 | ww4 | 0 |
| 1 | ww5 | 1 |
| 2 | ww1 | 1 |
| 2 | ww2 | 1 |
| 2 | ww3 | 1 |
| 2 | ww4 | 0 |
| 2 | ww5 | 1 |
...
Now I'd like to add a new column to show the consistent status for each ID among all the ww(workweek), the consistent status will be reset every time when the count_flag is 0 or ID changes, so it will look like below:
|ID | ww | count_flag | consistent status|
| 1 | ww1 | 0 | 0 |
| 1 | ww2 | 1 | 1 |
| 1 | ww3 | 1 | 2 |
| 1 | ww4 | 0 | 0 |
| 1 | ww5 | 1 | 1 |
| 2 | ww1 | 1 | 1 |
| 2 | ww2 | 1 | 2 |
| 2 | ww3 | 1 | 3 |
| 2 | ww4 | 0 | 0 |
| 2 | ww5 | 1 | 1 |
...
How should I create the calculating field to add such a parameter to the table column.

How to group MVA field for faceted in sphinx

I have an index where some data's has duplicate, all fields are similar except for latitude,longitude and id (field id is not realy ID, just generated row_number() OVER () AS id).
it's example:
mysql> select id,vacancy_id,prof_area_ids,latitude,longitude from jobVacancy;
+------+------------+---------------+----------+-----------+
| id | vacancy_id | prof_area_ids | latitude | longitude |
+------+------------+---------------+----------+-----------+
| 1 | 917 | 11,199,202 | 0.973178 | 0.743566 |
| 2 | 916 | 17,283,288 | 0.973178 | 0.743566 |
| 3 | 915 | 17,288 | 0.973178 | 0.743566 |
| 4 | 914 | 30,482 | 0.973178 | 0.743566 |
| 5 | 919 | 15,243 | 0.825153 | 0.692837 |
| 6 | 919 | 15,243 | 0.825162 | 0.692828 |
| 7 | 918 | 8,154 | 0.825153 | 0.692837 |
| 8 | 918 | 8,154 | 0.825162 | 0.692828 |
| 9 | 920 | 17,283,288 | 0.958914 | 1.282161 |
| 10 | 920 | 17,283,288 | 0.958915 | 1.282215 |
| 11 | 924 | 12,208 | 0.97333 | 0.658246 |
| 12 | 924 | 12,208 | 0.973336 | 0.658237 |
| 13 | 923 | 21,365 | 0.97333 | 0.658246 |
| 14 | 923 | 21,365 | 0.973336 | 0.658237 |
| 15 | 922 | 20,359 | 0.97333 | 0.658246 |
| 16 | 922 | 20,359 | 0.973336 | 0.658237 |
| 17 | 921 | 19,346 | 0.97333 | 0.658246 |
| 18 | 921 | 19,346 | 0.973336 | 0.658237 |
| 19 | 926 | 12,17,208,292 | 0.88396 | 2.389868 |
| 20 | 925 | 12,208 | 0.88396 | 2.389868 |
+------+------------+---------------+----------+-----------+
20 rows in set (0.00 sec)
Now I want to group data by vacancy_id
mysql> select id,vacancy_id,prof_area_ids,latitude,longitude from jobVacancy group by vacancy_id;
+------+------------+---------------+----------+-----------+
| id | vacancy_id | prof_area_ids | latitude | longitude |
+------+------------+---------------+----------+-----------+
| 1 | 917 | 11,199,202 | 0.973178 | 0.743566 |
| 2 | 916 | 17,283,288 | 0.973178 | 0.743566 |
| 3 | 915 | 17,288 | 0.973178 | 0.743566 |
| 4 | 914 | 30,482 | 0.973178 | 0.743566 |
| 5 | 919 | 15,243 | 0.825153 | 0.692837 |
| 7 | 918 | 8,154 | 0.825153 | 0.692837 |
| 9 | 920 | 17,283,288 | 0.958914 | 1.282161 |
| 11 | 924 | 12,208 | 0.97333 | 0.658246 |
| 13 | 923 | 21,365 | 0.97333 | 0.658246 |
| 15 | 922 | 20,359 | 0.97333 | 0.658246 |
| 17 | 921 | 19,346 | 0.97333 | 0.658246 |
| 19 | 926 | 12,17,208,292 | 0.88396 | 2.389868 |
| 20 | 925 | 12,208 | 0.88396 | 2.389868 |
| 21 | 961 | 4,105 | 0.959217 | 1.280721 |
| 23 | 960 | 8,155 | 0.959217 | 1.280721 |
| 25 | 959 | 12,208 | 0.959217 | 1.280721 |
| 27 | 928 | 1,60 | 0.963734 | 1.070297 |
| 29 | 927 | 32,513 | 0.963734 | 1.070297 |
| 31 | 929 | 6,140 | 0.786553 | 0.678649 |
| 33 | 932 | 1,40,46 | 0.824627 | 0.694182 |
+------+------------+---------------+----------+-----------+
20 rows in set (0.00 sec)
Result is awesome! But problem begins when I want to get all grouped data with faceted
mysql> select id,vacancy_id,prof_area_ids,latitude,longitude from jobVacancy where prof_area_ids=199 group by vacancy_id facet prof_area_ids;
+------+------------+-----------------+----------+-----------+
| id | vacancy_id | prof_area_ids | latitude | longitude |
+------+------------+-----------------+----------+-----------+
| 1 | 917 | 11,199,202 | 0.973178 | 0.743566 |
| 191 | 1004 | 11,196,199 | 0.925335 | 2.768874 |
| 313 | 1072 | 1,11,60,197,199 | 0.963968 | 1.070624 |
| 318 | 1136 | 11,196,199 | 0.96071 | 1.448998 |
| 374 | 1097 | 11,199 | 0.785255 | 0.678504 |
+------+------------+-----------------+----------+-----------+
5 rows in set (0.00 sec)
+---------------+----------+
| prof_area_ids | count(*) |
+---------------+----------+
| 202 | 1 |
| 199 | 12 |
| 11 | 12 |
| 196 | 5 |
| 197 | 3 |
| 60 | 3 |
| 1 | 3 |
+---------------+----------+
7 rows in set (0.02 sec)
Faceted result is incorrect. Because in fact data's count where prof_area_ids=199 must be 5 and not 12. So how I can group field for faceted?
Additionaly
I fount here http://sphinxsearch.com/blog/2013/06/21/faceted-search-with-sphinx/ but just written "If you have a MVA facet, you need to use the GROUPBY() function which returns the actual value on which the grouping was made." and without examle.
mysql> select id,vacancy_id,prof_area_ids,latitude,longitude,GROUPBY() as selected,COUNT(*) from jobVacancy where prof_area_ids=199 group by vacancy_id facet prof_area_ids;
+------+------------+-----------------+----------+-----------+----------+----------+
| id | vacancy_id | prof_area_ids | latitude | longitude | selected | count(*) |
+------+------------+-----------------+----------+-----------+----------+----------+
| 1 | 917 | 11,199,202 | 0.973178 | 0.743566 | 917 | 1 |
| 191 | 1004 | 11,196,199 | 0.925335 | 2.768874 | 1004 | 2 |
| 313 | 1072 | 1,11,60,197,199 | 0.963968 | 1.070624 | 1072 | 3 |
| 318 | 1136 | 11,196,199 | 0.96071 | 1.448998 | 1136 | 3 |
| 374 | 1097 | 11,199 | 0.785255 | 0.678504 | 1097 | 3 |
+------+------------+-----------------+----------+-----------+----------+----------+
5 rows in set (0.00 sec)
+---------------+----------+
| prof_area_ids | count(*) |
+---------------+----------+
| 202 | 1 |
| 199 | 12 |
| 11 | 12 |
| 196 | 5 |
| 197 | 3 |
| 60 | 3 |
| 1 | 3 |
+---------------+----------+
7 rows in set (0.02 sec)
Also faceted result is wrong.

Seems, wanting effectively COUNT(DISTINCT vacancy_id) on the FACET rather than the default COUNT(*), but alas it turns out
... FACET prof_area_ids,COUNT(DISTINCT vacancy_id) AS vacancies BY prof_area_ids
doesnt work. The bit before BY only supports attributes, not custom functions.
... will just have to write it out the long way, with full queries...
select id,vacancy_id,prof_area_ids,latitude,longitude from jobVacancy
where prof_area_ids=199 group by vacancy_id;
SELECT GROUPBY() AS prof_area_id, COUNT(DISTINCT vacancy_id) FROM jobVacancy
WHERE prof_area_ids=199 GROUP BY prof_area_id;
Same results, just slightly more verbose. ie rather than using FACET shorthand, write it
out in full, as multiple seperate queries.

Faceted result is incorrect. Because in fact data's count where prof_area_ids=199 must be 5 and not 12. So how I can group field for faceted?
It looks like you misunderstand how FACET works. It seems to me, that you think it takes as a base the main query's result, but it actually just does another grouping. E.g. here:
mysql> select g, t from idx_mva where t = 11 group by g facet t;
+------+----------+
| g | t |
+------+----------+
| 1 | 11,12 |
| 2 | 11,13,15 |
| 3 | 9,11 |
| 5 | 11,12,15 |
+------+----------+
4 rows in set (0.00 sec)
+------+----------+
| t | count(*) |
+------+----------+
| 12 | 2 |
| 11 | 6 |
| 15 | 4 |
| 13 | 1 |
| 9 | 1 |
| 3 | 1 |
+------+----------+
6 rows in set (0.00 sec)
for t=11 you can see that as in your case it's found 3 times in the 1st query's result, but the count for that is 6 in the FACET's query result. This is because it actually occurs 6 times in the index:
mysql> select * from idx_mva where t = 11;
+------+------+----------+
| id | g | t |
+------+------+----------+
| 2 | 1 | 11,12 |
| 3 | 1 | 11,15 |
| 3 | 2 | 11,13,15 |
| 6 | 3 | 9,11 |
| 8 | 5 | 11,12,15 |
| 11 | 2 | 3,11,15 |
+------+------+----------+
6 rows in set, 1 warning (0.00 sec)
and it happens 3 times in the 1st case only because the t's value is returned only once for each of the groups. You can use group_concat() to see more values from the same group:
mysql> select g, group_concat(to_string(t)) from idx_mva where t = 11 group by g facet t;
+------+----------------------------+
| g | group_concat(to_string(t)) |
+------+----------------------------+
| 1 | 11,12,11,15 |
| 2 | 11,13,15,3,11,15 |
| 3 | 9,11 |
| 5 | 11,12,15 |
+------+----------------------------+
4 rows in set (0.00 sec)
+------+----------+
| t | count(*) |
+------+----------+
| 12 | 2 |
| 11 | 6 |
| 15 | 4 |
| 13 | 1 |
| 9 | 1 |
| 3 | 1 |
+------+----------+
6 rows in set (0.00 sec)
If you want to learn more about faceting here's an interactive course about that - https://play.manticoresearch.com/faceting/

ERROR: column "table.column_name" must appear in the GROUP BY clause or be used in an aggregate function

I have the following table:
SELECT * FROM trips_motion_xtics
+------------+---------+-------------+------------+-------------+------------+-----+------------------+------------------+-------+--------------+-------+-------------+
| session_id | trip_id | lat_start | lat_end | lon_start | lon_end | alt | distance | segments_length | speed | acceleration | track | travel_mode |
+------------+---------+-------------+------------+-------------+------------+-----+------------------+------------------+-------+--------------+-------+-------------+
| 652 | 303633 | 41.1523521 | 41.1524966 | -8.6097233 | -8.6096833 | 0 | 42.7424443438547 | 28.0353622436523 | 0 | 74.208 | 0 | foot |
| 652 | 303633 | 41.1523521 | 41.1524966 | -8.6097233 | -8.6096833 | 0 | 42.7424443438547 | 28.0353622436523 | 0 | 74.154 | 0 | foot |
| 652 | 303633 | 41.1523521 | 41.1524966 | -8.6097233 | -8.6096833 | 0 | 42.7424443438547 | 28.0353622436523 | 0 | 68.226 | 0 | foot |
| 656 | 303637 | 41.14454009 | 41.1631127 | -8.56292593 | -8.5870161 | 0 | 5921.07030809987 | 2785.6088546142 | 0 | 99.028 | 0 | car |
| 656 | 303637 | 41.14454009 | 41.1631127 | -8.56292593 | -8.5870161 | 0 | 5921.07030809987 | 2785.6088546142 | 0 | 109.992 | 0 | car |
+------------+---------+-------------+------------+-------------+------------+-----+------------------+------------------+-------+--------------+-------+-------------+
Now would like to compute the average value for columns alt, distance, speed ... for unique value of session_id, trip_id, lat_start,...
Query:
SELECT DISTINCT(session_id, trip_id, lat_start, lat_end, lon_start, lon_end, travel_mode), AVG(alt) AS avg_alt, AVG(distance) AS avg_disntance, AVG(speed) AS avg_speed, AVG(acceleration) AS avg_acc FROM akil.trips_motion_xtics;
ERROR: column "trips_motion_xtics.session_id" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT DISTINCT(session_id, trip_id, lat_start, lat_end, lon...
Required result:
+------------+---------+-------------+------------+-------------+------------+-----+------------------+------------------+-------+--------------+-------+-------------+
| session_id | trip_id | lat_start | lat_end | lon_start | lon_end | alt | distance | segments_length | speed | acceleration | track | travel_mode |
+------------+---------+-------------+------------+-------------+------------+-----+------------------+------------------+-------+--------------+-------+-------------+
| 652 | 303633 | 41.1523521 | 41.1524966 | -8.6097233 | -8.6096833 | 0 | 42.7424443438547 | 28.0353622436523 | 0 | 72.196 | 0 | foot |
| 656 | 303637 | 41.14454009 | 41.1631127 | -8.56292593 | -8.5870161 | 0 | 5921.07030809987 | 2785.6088546142 | 0 | 104.51 | 0 | car |
+------------+---------+-------------+------------+-------------+------------+-----+------------------+------------------+-------+--------------+-------+-------------+

You want aggregation. You will get a unique record for each combination of the column listed in the GROUP BY clause, and you can apply aggregate functions (such as AVG()) on other columns:
SELECT
session_id,
trip_id,
lat_start,
lat_end,
lon_start,
lon_end,
travel_mode,
AVG(alt) AS avg_alt,
AVG(distance) AS avg_disntance,
AVG(speed) AS avg_speed,
AVG(acceleration) AS avg_acc
FROM akil.trips_motion_xtics
GROUP BY
session_id,
trip_id,
lat_start,
lat_end,
lon_start,
lon_end,
travel_mode

Retrieve additional columns on aggregation and date operator

I have the following PostgreSQL table structure, which gathers temperature records for every second:
+----+--------+-------------------------------+---------+
| id | value | date | station |
+----+--------+-------------------------------+---------+
| 1 | 0 | 2017-08-22 14:01:09.314625+02 | 1 |
| 2 | 0 | 2017-08-22 14:01:09.347758+02 | 1 |
| 3 | 25.187 | 2017-08-22 14:01:10.315413+02 | 1 |
| 4 | 24.937 | 2017-08-22 14:01:10.322528+02 | 1 |
| 5 | 25.187 | 2017-08-22 14:01:11.347271+02 | 1 |
| 6 | 24.937 | 2017-08-22 14:01:11.355005+02 | 1 |
| 18 | 24.875 | 2017-08-22 14:01:17.35265+02 | 1 |
| 19 | 25.187 | 2017-08-22 14:01:18.34673+02 | 1 |
| 20 | 24.875 | 2017-08-22 14:01:18.355082+02 | 1 |
| 21 | 25.187 | 2017-08-22 14:01:19.361491+02 | 1 |
| 22 | 24.875 | 2017-08-22 14:01:19.371154+02 | 1 |
| 23 | 25.187 | 2017-08-22 14:01:20.354576+02 | 1 |
| 30 | 24.937 | 2017-08-22 14:01:23.372612+02 | 1 |
| 31 | 0 | 2017-08-22 15:58:53.576238+02 | 1 |
| 32 | 0 | 2017-08-22 15:58:53.590872+02 | 1 |
| 33 | 26.625 | 2017-08-22 15:58:54.59986+02 | 1 |
| 38 | 26.375 | 2017-08-22 15:58:56.593205+02 | 1 |
| 39 | 0 | 2017-08-21 15:59:40.181317+02 | 1 |
| 40 | 0 | 2017-08-21 15:59:40.190221+02 | 1 |
| 41 | 26.562 | 2017-08-21 15:59:41.182622+02 | 1 |
| 42 | 26.375 | 2017-08-21 15:59:41.18905+02 | 1 |
+----+--------+-------------------------------+---------+
I want now to retrieve the maximum value for every hour, along with the data associated to that entry (id, date). As such, I tried the following:
select max(value) as m, (date_trunc('hour', date)) as d
from temperature
where station='1'
group by (date_trunc('hour', date));
Which works fine (fiddle), but I only get the columns m and d as a result. If I now try to add the date or id columns to the SELECT statement, I get the usual column "temperature.id" must appear in the GROUP BY clause or be used in an aggregate function error.
I have already tried approaches such as the ones described here, unfortunately to no avail, as for instance I seem to be unable to perform a join on the date_trunc-generated columns.
The result I am aiming for is this:
+----+--------+-------------------------------+---------+
| id | value | date | station |
+----+--------+-------------------------------+---------+
| 3 | 25.187 | 2017-08-22 14:01:10.315413+02 | 1 |
| 33 | 26.625 | 2017-08-22 15:58:54.59986+02 | 1 |
| 41 | 26.562 | 2017-08-21 15:59:41.182622+02 | 1 |
+----+--------+-------------------------------+---------+
It does not matter which record was retrieved in case two or more entries have the same value.

distinct on:
select distinct on (date_trunc('hour', date)) *
from temperature
where station = '1'
order by date_trunc('hour', date), value desc
Fiddle

PostgreSQL aggregate function for each row across multiple unknown number of columns

I looked through similar questions like this one, but they seem to have a definite number of columns. I would like to input a table that I do not know the number of columns.
Question:
How to calculate aggregate functions (e.g. avg() or sum() ) for each row across several columns if number of columns is not known in advance?
I have put the input table panel_stats_rnd csv and a DLL to create it here.
I would like to calculate for each row the rnd_avg_parcelcount as average of all columns c_1_avg_parcelcount, c_2_avg_parcelcount, ... where I can have input tables with any number (say 100) columns of _avg_parcelcount. And for columns rnd_sum_parcelcount I would like to calculate sum() of all columns that start with c_ and end with _sum_parcelcount.
The table looks like this:
SELECT * FROM panel_stats_rnd;
gid | d | dist_from | dist_to | distlabel | rnd_avg_parcelcount | rnd_sum_parcelcount | rnd_avg_callcount | rnd_sum_callcount | rnd_avg_perccalled | called_avg_parcelcount | called_sum_parcelcount | called_avg_callcount | called_sum_callcount | called_avg_perccalled | c_1_avg_parcelcount | c_1_sum_parcelcount | c_1_avg_callcount | c_1_sum_callcount | c_1_avg_perccalled | c_2_avg_parcelcount | c_2_sum_parcelcount | c_2_avg_callcount | c_2_sum_callcount | c_2_avg_perccalled
-----+----+-----------+---------+-----------+---------------------+---------------------+-------------------+-------------------+--------------------+------------------------+------------------------+----------------------+----------------------+-----------------------+---------------------+---------------------+-------------------+-------------------+----------------------+---------------------+---------------------+-------------------+-------------------+----------------------
1 | 0 | 0 | 100 | 0-100 | | | | | | 119045 | 119045 | 119045 | 23 | 0.000193204250493511 | 119045 | 119045 | 119045 | 16 | 0.000134402956865051 | 119045 | 119045 | 119045 | 16 | 0.000134402956865051
2 | 1 | 100 | 200 | 100-200 | | | | | | 163140 | 163140 | 163140 | 22 | 0.000134853500061297 | 163140 | 163140 | 163140 | 17 | 0.000104204977320093 | 163140 | 163140 | 163140 | 18 | 0.000110334681868334
3 | 2 | 200 | 300 | 200-300 | | | | | | 135934 | 135934 | 135934 | 10 | 7.3565112481057e-05 | 135934 | 135934 | 135934 | 18 | 0.000132417202465903 | 135934 | 135934 | 135934 | 15 | 0.000110347668721585
4 | 3 | 300 | 400 | 300-400 | | | | | | 116874 | 116874 | 116874 | 13 | 0.000111230898232284 | 116874 | 116874 | 116874 | 11 | 9.41184523503944e-05 | 116874 | 116874 | 116874 | 18 | 0.000154012012937009
5 | 4 | 400 | 500 | 400-500 | | | | | | 93216 | 93216 | 93216 | 12 | 0.000128733264675592 | 93216 | 93216 | 93216 | 10 | 0.000107277720562993 | 93216 | 93216 | 93216 | 12 | 0.000128733264675592
6 | 5 | 500 | 600 | 500-600 | | | | | | 69992 | 69992 | 69992 | 7 | 0.0001000114298777 | 69992 | 69992 | 69992 | 10 | 0.000142873471253858 | 69992 | 69992 | 69992 | 7 | 0.0001000114298777
7 | 6 | 600 | 700 | 600-700 | | | | | | 50816 | 50816 | 50816 | 10 | 0.000196788413098237 | 50816 | 50816 | 50816 | 6 | 0.000118073047858942 | 50816 | 50816 | 50816 | 0 | 0
8 | 7 | 700 | 800 | 700-800 | | | | | | 34814 | 34814 | 34814 | 0 | 0 | 34814 | 34814 | 34814 | 6 | 0.000172344459125639 | 34814 | 34814 | 34814 | 4 | 0.000114896306083759
9 | 8 | 800 | 900 | 800-900 | | | | | | 23023 | 23023 | 23023 | 1 | 4.34348260435217e-05 | 23023 | 23023 | 23023 | 4 | 0.000173739304174087 | 23023 | 23023 | 23023 | 1 | 4.34348260435217e-05
10 | 9 | 900 | 1000 | 900-1000 | | | | | | 14215 | 14215 | 14215 | 1 | 7.03482237073514e-05 | 14215 | 14215 | 14215 | 1 | 7.03482237073514e-05 | 14215 | 14215 | 14215 | 5 | 0.000351741118536757
11 | 10 | 1000 | 5000 | 1000-5000 | | | | | | 23527 | 23527 | 23527 | 0 | 0 | 23527 | 23527 | 23527 | 0 | 0 | 23527 | 23527 | 23527 | 3 | 0.000127513070089684
(11 rows)
I tried the following for 2 columns (works but I'd rather not write it 5 times for 100 columns, besides the number of columns has to be a parameter):
SELECT d,c_1_avg_parcelcount,c_2_avg_parcelcount,
(SELECT avg(c) FROM (VALUES (c_1_avg_parcelcount) , (c_2_avg_parcelcount) ) T (c)) AS Avg_,
(SELECT sum(c) FROM (VALUES (c_1_avg_parcelcount) , (c_2_avg_parcelcount) ) T (c)) AS sum_
FROM panel_stats_rnd;
I also tried the following but doesn't work.
WITH cols AS (
select value(column_name) from information_schema.columns
where table_name = 'panel_stats_rnd'
AND column_name SIMILAR TO 'c_%avg_parcelcount'
AND column_name != 'called_avg_parcelcount'
)
SELECT *, (SELECT avg(Col) FROM cols V(Col) ) AS col_average
FROM panel_stats_rnd;
I am almost there but something is missing...

select
*,
(select avg(v::numeric)
from json_each_text(row_to_json(panel_stats_rnd.*)) as j(k,v)
where k like 'c\_%\_avg\_parcelcount') as rnd_avg_parcelcount,
(select sum(v::numeric)
from json_each_text(row_to_json(panel_stats_rnd.*)) as j(k,v)
where k like 'c\_%\_sum\_parcelcount') as rnd_sum_parcelcount
from
panel_stats_rnd;
Look at the documentation about functions involved.
There are escapes for underlying characters (\_) because for like operator it is meaning any single character, for example select 'a' like '_'; is true.