Convert UIColor initialization to Color Literal Xcode - swift

Question

I have multiple different UIColor objects. Some of them are initialized by a constructor some of them are shown as color literals.
static let optionsHeader = UIColor([ ]) // XCode is showing a color rect.
static let optionButtonSelected = UIColor(red: 0.865, green: 0.804, blue: 0.0, alpha: 1.0)
How can I convert the UIColor.init(...) statements to a color literal.

Answer 1

RGB color literal is same as UIColor initialization:
#colorLiteral(red: 1, green: 1, blue: 1, alpha: 1)
Or you can select color after typing #colorLiteral().

Answer 2

You can also use extensions to use hex color instead of inputting rgba values
extension UIColor {
convenience init(hexString: String, alpha: CGFloat = 1.0) {
let hexString: String = hexString.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)
let scanner = Scanner(string: hexString)
if (hexString.hasPrefix("#")) {
scanner.scanLocation = 1
}
var color: UInt32 = 0
scanner.scanHexInt32(&color)
let mask = 0x000000FF
let r = Int(color >> 16) & mask
let g = Int(color >> 8) & mask
let b = Int(color) & mask
let red = CGFloat(r) / 255.0
let green = CGFloat(g) / 255.0
let blue = CGFloat(b) / 255.0
self.init(red:red, green:green, blue:blue, alpha:alpha)
}
func toHexString() -> String {
var r:CGFloat = 0
var g:CGFloat = 0
var b:CGFloat = 0
var a:CGFloat = 0
getRed(&r, green: &g, blue: &b, alpha: &a)
let rgb:Int = (Int)(r*255)<<16 | (Int)(g*255)<<8 | (Int)(b*255)<<0
return String(format:"#%06x", rgb)
}
}
Then you can code it with:
self.backgroundColor = UIColor(hexString: "#4A4A4A")