SwiftUI - Alert displays twice after setting its state variable only once - swift

Question

I want to have this button run a certain command and if it fails, I want it to display an Alert saying it failed. It does this fine except when the alert displays, it displays twice but I only set it once.
Here are the two state variables I use to display the alert:
#State private var alert = false
#State private var alertView = Alert(
title: Text("Well Hello There"),
message: Text("You probably shouldn't be seeing this alert but if you are, hello there! (This is a bug)")
)
And here's my button:
Button(action: {
DispatchQueue.global(qos: .background).async {
if let command = action.command {
let error = Connection.shared.run(command: command)
if error != nil {
self.alertView = Alert(
title: Text("Failed to Run Action"),
message: Text("An error occurred while attempting to \(action.label).")
)
print("Displaying alert") // This only gets printed once
self.alert = true
}
}
}
}) {
Text(action.label)
}.alert(isPresented: self.$alert) {
self.alertView
}

Answer 1

Well I think I have found what the problem is, If you put the alert modifier inside a forEach it actually happens to trigger twice for some reason.
Just bring it out and it works as intended.

Answer 2

What if you set false to self.alert forcibly ?
.alert(isPresented: self.$alert) {
self.alertView
}.onAppear{
self.alert = false
}

Answer 3

It's my experience running on macOS. That might be different from yours.
I had a routine in Alert() closure that would trigger a UI refresh because it alters a state variable. It happened the refresh occurred before "isPresent" being toggled automatically by closing the alert presentation, so the view caught the "isPresent" again during the refresh. I can avoid this either by adding some delay to the routine or, in a safer way, hook the alert modifier to a view that is not affected by the refresh.