I'm trying to train a custom dataset using Darknet framework and Yolov4. I built up my own dataset but I get a Out of memory message in google colab. It also said "try to change subdivisions to 64" or something like that.
I've searched around the meaning of main .cfg parameters such as batch, subdivisions, etc. and I can understand that increasing the subdivisions number means splitting into smaller "pictures" before processing, thus avoiding to get the fatal "CUDA out of memory". And indeed switching to 64 worked well. Now I couldn't find anywhere the answer to the ultimate question: is the final weight file and accuracy "crippled" by doing this? More specifically what are the consequences on the final result? If we put aside the training time (which would surely increase since there are more subdivisions to train), how will be the accuracy?
In other words: if we use exactly the same dataset and train using 8 subdivisions, then do the same using 64 subdivisions, will the best_weight file be the same? And will the object detections success % be the same or worse?
Thank you.
first read comments
suppose you have 100 batches.
batch size = 64
subdivision = 8
it will divide your batch = 64/8 => 8
Now it will load and work one by one on 8 divided parts into the RAM, because of LOW RAM capacity you can change the parameter according to ram capacity.
you can also reduce batch size , so it will take low space in ram.
It will do nothing to the datasets images.
It is just splitting the large batch size which can't be load in RAM, so divided into small pieces.
I am using the KNIME Doc2Vec Learner node to build a Word Embedding. I know how Doc2Vec works. In KNIME I have the option to set the parameters
Batch Size: The number of words to use for each batch.
Number of Epochs: The number of epochs to train.
Number of Training Iterations: The number of updates done for each batch.
From Neural Networks I know that (lazily copied from https://stats.stackexchange.com/questions/153531/what-is-batch-size-in-neural-network):
one epoch = one forward pass and one backward pass of all the training examples
batch size = the number of training examples in one forward/backward pass. The higher the batch size, the more memory space you'll need.
number of iterations = number of passes, each pass using [batch size] number of examples. To be clear, one pass = one forward pass + one backward pass (we do not count the forward pass and backward pass as two different passes).
As far as I understand it makes little sense to set batch size and iterations, because one is determined by the other (given the data size, which is given by the circumstances). So why can I change both parameters?
This is not necessarily the case. You can also train "half epochs". For example, in Google's inceptionV3 pretrained script, you usually set the number of iterations and the batch size at the same time. This can lead to "partial epochs", which can be fine.
If it is a good idea or not to train half epochs may depend on your data. There is a thread about this but not a concluding answer.
I am not familiar with KNIME Doc2Vec, so I am not sure if the meaning is somewhat different there. But from the definitions you gave setting batch size + iterations seems fine. Also setting number of epochs could cause conflicts though leading to situations where numbers don't add up to reasonable combinations.
I understand that bigger batch size gives more accurate results from here. But I'm not sure which batch size is "good enough". I guess bigger batch sizes will always be better but it seems like at a certain point you will only get a slight improvement in accuracy for every increase in batch size. Is there a heuristic or a rule of thumb on finding the optimal batch size?
Currently, I have 40000 training data and 10000 test data. My batch size is the default which is 256 for training and 50 for the test. I am using NVIDIA GTX 1080 which has 8Gigs of memory.
Test-time batch size does not affect accuracy, you should set it to be the largest you can fit into memory so that validation step will take shorter time.
As for train-time batch size, you are right that larger batches yield more stable training. However, having larger batches will slow training significantly. Moreover, you will have less backprop updates per epoch. So you do not want to have batch size too large. Using default values is usually a good strategy.
See my masters thesis, page 59 for some of the reasons why to choose a bigger batch size / smaller batch size. You want to look at
epochs until convergence
time per epoch: higher is better
resulting model quality: lower is better (in my experiments)
A batch size of 32 was good for my datasets / models / training algorithm.
Hi I am trying to cluster using linkage(). Here is the code I am trying..
Y = pdist(data);
Z = linkage(Y);
T = cluster(Z,'maxclust',4096);
I am getting error as follows
The number of elements exceeds the maximum allowed size in
MATLAB.
Error in ==> linkage at 135
Z = linkagemex(Y,method);
data size is 56710*128. How can I apply the code on small chunks of data and then merge those clusters optimally?? Or any other solution to the problem.
Matlab probably cannot cluster this many objects with this algorithm.
Most likely they use distance matrixes in their implementation. A pairwise distance matrix for 56710 objects needs 56710*56709/2=1,607,983,695 entries, or some 12 GB of RAM; most likely also a working copy of this is needed. Chances are that the default Matlab data structures are not prepared to handle this amount of data (and you won't want to wait for the algorithm to finish either; probably that is why they "allow" only a certain amount).
Try using a subset, and see how well it scales. If you use 1000 instances, does it work? How long does the computation take? If you increase to 2000, how much longer does it take?
I have a project where I am asked to develop an application to simulate how different page replacement algorithms perform (with varying working set size and stability period). My results:
Vertical axis: page faults
Horizontal axis: working set size
Depth axis: stable period
Are my results reasonable? I expected LRU to have better results than FIFO. Here, they are approximately the same.
For random, stability period and working set size doesnt seem to affect the performance at all? I expected similar graphs as FIFO & LRU just worst performance? If the reference string is highly stable (little branches) and have a small working set size, it should still have less page faults that an application with many branches and big working set size?
More Info
My Python Code | The Project Question
Length of reference string (RS): 200,000
Size of virtual memory (P): 1000
Size of main memory (F): 100
number of time page referenced (m): 100
Size of working set (e): 2 - 100
Stability (t): 0 - 1
Working set size (e) & stable period (t) affects how reference string are generated.
|-----------|--------|------------------------------------|
0 p p+e P-1
So assume the above the the virtual memory of size P. To generate reference strings, the following algorithm is used:
Repeat until reference string generated
pick m numbers in [p, p+e]. m simulates or refers to number of times page is referenced
pick random number, 0 <= r < 1
if r < t
generate new p
else (++p)%P
UPDATE (In response to #MrGomez's answer)
However, recall how you seeded your input data: using random.random,
thus giving you a uniform distribution of data with your controllable
level of entropy. Because of this, all values are equally likely to
occur, and because you've constructed this in floating point space,
recurrences are highly improbable.
I am using random, but it is not totally random either, references are generated with some locality though the use of working set size and number page referenced parameters?
I tried increasing the numPageReferenced relative with numFrames in hope that it will reference a page currently in memory more, thus showing the performance benefit of LRU over FIFO, but that didn't give me a clear result tho. Just FYI, I tried the same app with the following parameters (Pages/Frames ratio is still kept the same, I reduced the size of data to make things faster).
--numReferences 1000 --numPages 100 --numFrames 10 --numPageReferenced 20
The result is
Still not such a big difference. Am I right to say if I increase numPageReferenced relative to numFrames, LRU should have a better performance as it is referencing pages in memory more? Or perhaps I am mis-understanding something?
For random, I am thinking along the lines of:
Suppose theres high stability and small working set. It means that the pages referenced are very likely to be in memory. So the need for the page replacement algorithm to run is lower?
Hmm maybe I got to think about this more :)
UPDATE: Trashing less obvious on lower stablity
Here, I am trying to show the trashing as working set size exceeds the number of frames (100) in memory. However, notice thrashing appears less obvious with lower stability (high t), why might that be? Is the explanation that as stability becomes low, page faults approaches maximum thus it does not matter as much what the working set size is?
These results are reasonable given your current implementation. The rationale behind that, however, bears some discussion.
When considering algorithms in general, it's most important to consider the properties of the algorithms currently under inspection. Specifically, note their corner cases and best and worst case conditions. You're probably already familiar with this terse method of evaluation, so this is mostly for the benefit of those reading here whom may not have an algorithmic background.
Let's break your question down by algorithm and explore their component properties in context:
FIFO shows an increase in page faults as the size of your working set (length axis) increases.
This is correct behavior, consistent with Bélády's anomaly for FIFO replacement. As the size of your working page set increases, the number of page faults should also increase.
FIFO shows an increase in page faults as system stability (1 - depth axis) decreases.
Noting your algorithm for seeding stability (if random.random() < stability), your results become less stable as stability (S) approaches 1. As you sharply increase the entropy in your data, the number of page faults, too, sharply increases and propagates the Bélády's anomaly.
So far, so good.
LRU shows consistency with FIFO. Why?
Note your seeding algorithm. Standard LRU is most optimal when you have paging requests that are structured to smaller operational frames. For ordered, predictable lookups, it improves upon FIFO by aging off results that no longer exist in the current execution frame, which is a very useful property for staged execution and encapsulated, modal operation. Again, so far, so good.
However, recall how you seeded your input data: using random.random, thus giving you a uniform distribution of data with your controllable level of entropy. Because of this, all values are equally likely to occur, and because you've constructed this in floating point space, recurrences are highly improbable.
As a result, your LRU is perceiving each element to occur a small number of times, then to be completely discarded when the next value was calculated. It thus correctly pages each value as it falls out of the window, giving you performance exactly comparable to FIFO. If your system properly accounted for recurrence or a compressed character space, you would see markedly different results.
For random, stability period and working set size doesn't seem to affect the performance at all. Why are we seeing this scribble all over the graph instead of giving us a relatively smooth manifold?
In the case of a random paging scheme, you age off each entry stochastically. Purportedly, this should give us some form of a manifold bound to the entropy and size of our working set... right?
Or should it? For each set of entries, you randomly assign a subset to page out as a function of time. This should give relatively even paging performance, regardless of stability and regardless of your working set, as long as your access profile is again uniformly random.
So, based on the conditions you are checking, this is entirely correct behavior consistent with what we'd expect. You get an even paging performance that doesn't degrade with other factors (but, conversely, isn't improved by them) that's suitable for high load, efficient operation. Not bad, just not what you might intuitively expect.
So, in a nutshell, that's the breakdown as your project is currently implemented.
As an exercise in further exploring the properties of these algorithms in the context of different dispositions and distributions of input data, I highly recommend digging into scipy.stats to see what, for example, a Gaussian or logistic distribution might do to each graph. Then, I would come back to the documented expectations of each algorithm and draft cases where each is uniquely most and least appropriate.
All in all, I think your teacher will be proud. :)