Flutter optionally include / exclude parent widget in widget tree - flutter

Question

I have this widget tree
return Container(
color: Colors.blue,
child: Container(
child: Text("Child"),
),
);
Is there a way to remove a parent widget from the tree or conditionally include it?
For example if a state variable such as includeBlueContainer was false, I would like to not render the blue container (but show everything else).

Answer 1

I couldn't achieve an optionally include reusable widget but I've been using this pattern which does achieve what I wanted to achieve. I haven't given this a great amount of thought but I still feel there is a better solution somewhere.
class MyContainer extends StatelessWidget {
final Widget child;
final bool isIncluded;
MyContainer({this.child, this.isIncluded = true});
Widget build(BuildContext context) {
if (!isIncluded) return child;
return Container(
color: Colors.blue,
child: child,
);
}
}

Answer 2

Edit: I made a package out of this: https://pub.dev/packages/conditional_parent_widget
Which you can use like:
import 'package:flutter/widgets.dart';
import 'package:conditional_parent_widget/conditional_parent_widget.dart';
// ...
return ConditionalParentWidget(
condition: includeBlueContainer,
child: Text("Child"),
parentBuilder: (Widget child) => Container(
color: Colors.blue,
child: child,
),
);
Internally it is just:
import 'package:flutter/widgets.dart';
class ConditionalParentWidget extends StatelessWidget {
const ConditionalParentWidget({
Key? key,
required this.condition,
required this.child,
required this.parentBuilder,
}) : super(key: key);
final Widget child;
final bool condition;
final Widget Function(Widget child) parentBuilder;
#override
Widget build(BuildContext context) {
return condition ? this.parentBuilder(this.child) : this.child;
}
}