Kubernetes POD delete with Pattern Match or Wildcard - kubernetes

Question

When I am using below it deletes the running POD after matching the pattern from commandline:
kubectl get pods -n bi-dev --no-headers=true | awk '/group-react/{print $1}' | xargs kubectl delete -n bi-dev pod
However when I am using this command as an alias in .bash_profile it doesn't execute .
This is how I defined it :
alias kdpgroup="kubectl get pods -n bi-dev --no-headers=true | awk '/group-react/{print $1}'| kubectl delete -n bi-dev pod"
when execute this as below I get below error in commandline:
~ $ kdpgroup
error: resource(s) were provided, but no name, label selector, or --all flag specified
When I define this in .bash_profile I get this :
~ $ . ./.bash_profile
-bash: alias: }| xargs kubectl delete -n bi-dev pod: not found
~ $
Am I missing something to delete POD using Pattern Match or with Wilcard ?
thanks

Answer 1

Am I missing something to delete POD using Pattern Match or with Wilcard?
When using Kubernetes it is more common to use labels and selectors. E.g. if you deployed an application, you usually set a label on the pods e.g. app=my-app and you can then get the pods with e.g. kubectl get pods -l app=my-app.
Using this aproach, it is easier to delete the pods you are interested in, with e.g.
kubectl delete pods -l app=my-app
or with namespaces
kubectl delete pods -l app=my-app -n default
See more on Kubernetes Labels and Selectors
Set-based selector
I have some pod's running in the name of "superset-react" and "superset-graphql" and I want to search my wildcard superset and delete both of them in one command
I suggest that those pods has labels app=something-react and app=something-graphql. If you want to classify those apps, e.g. if your "superset" varies, you could add a label app-type=react and app-type=graphql to all those type of apps.
Then you can delete pods for both app types with this command:
kubectl delete pods -l 'app-type in (react, graphql)'

Answer 2

As the question asks, this is about using a wild card. Let me give examples on using wild cards to delete pods.
Delete Pods which contain the word "application"
Replace <namespace> with the namespace you want to delete pods from.
kubectl get pods -n <namespace> --no-headers=true | awk '/application/{print $1}'| xargs kubectl delete -n <namespace> pod
This will give a response like the following. It will print out the deleted pods.
pod "sre-application-7fb4f5bff9-8crgx" deleted
pod "sre-application-7fb4f5bff9-ftzfd" deleted
pod "sre-application-7fb4f5bff9-rrkt2" deleted
Delete Pods which contain "application" or "service"
Replace <namespace> with the namespace you want to delete pods from.
kubectl get pods -n <namespace> --no-headers=true | awk '/application|service/{print $1}'| xargs kubectl delete -n <namespace> pod
This will give a response like the following. It will print out the deleted pods.
pod "sre-application-7fb4f5bff9-8crgx" deleted
pod "sre-application-7fb4f5bff9-ftzfd" deleted
pod "sre-service-7fb4f5bff9-rrkt2" deleted

Answer 3

You just need to escape the '$1' variable in the awk command:
alias kdpgroup="kubectl get pods -n bi-dev --no-headers=true | awk '/group-react/{print \$1}'| xargs kubectl delete -n bi-dev pod"
I know that escape is boring, and if you want to avoid it you can use as a function in you .bash_profile:
kdpgroup() {
kubectl get pods -n default --no-headers=true | awk '{print $1}' | xargs kubectl delete pod -n default
}

Answer 4

A robust way with variables, based on #keetSugathadasa answer:
ns="optional-namespace"
regex="pattern"
kubectl get pods ${ns:+ -n $ns} --no-headers | awk /${regex}/'{print $1}' \
| xargs kubectl delete ${ns:+ -n $ns} pod

Answer 5

using grep you can filter the keyword like this and delete matching pod name like this
kubectl get pods --no-headers=true | awk '{print $1}' | grep keyword | xargs kubectl delete pod