Swift - how to make window unactivable? - swift

Question

I want to make application unactivable.
I mean its must be inactive and non-foreground even by click on it. Active window must be the same app as it was before click on my app.
How can I do this?
upd:
Let's imagine some window/panel. Like a Dock. Let's call it "Docky"
Docky is inactive, Active window is Safari:
NSRunningApplicationSafari.isActive == true
NSRunningApplicationDocky.isActive == false
I'm clicking on ANY empty point of Docky.
Expected result:
Safari is still active window. Like before click:
NSRunningApplicationSafari.isActive == true
NSRunningApplicationDocky.isActive == false
Actual result:
Docky is active window, Safari is inactive:
NSRunningApplicationSafari.isActive == false
NSRunningApplicationDocky.isActive == true
Another sample is Keyboard Viewer. You are clicking on the virtual keyboard, but active window is another app. Ant exactly active window getting keyPress events.

Answer 1

Actually all you need is .nonactivatingPanel style panel. Everything else is details, like level of this window, custom views with overridden acceptsFirstMouse:, needsPanelToBecomeKey, etc. Btw, button accepts first click by default, non activating app in this case.
So your AppDelegate, for example, might look like the following:
class AppDelegate: NSObject, NSApplicationDelegate {
var docky: NSPanel!
func applicationDidFinishLaunching(_ aNotification: Notification) {
// Create the window and set the content view.
docky = NSPanel(
contentRect: NSRect(x: 0, y: 0, width: 120, height: 600),
styleMask: [.nonactivatingPanel],
backing: .buffered, defer: false)
docky.level = .mainMenu
....
docky.orderFrontRegardless()
}