How to get List Interactive keyboard height in SwiftUI? - swift

Question

In SwiftUI we can let the keyboard be interactive in a List by swiping down. We only need to provide this code to the init() of the view.
init() {
UITableView.appearance().keyboardDismissMode = .interactive
}
This works fine but the view that is attached to the keyboard isn't moving with the keyboard itself.
I found this post which should solve the issue in UIKit. How to I solve it in SwiftUI?
This is how I handle Keyboard popping up:
final class KeyboardResponder: ObservableObject {
private var _center: NotificationCenter
#Published private(set) var currentHeight: CGFloat = 0
#Published private(set) var duration: Double = 0.0
init(center: NotificationCenter = .default) {
_center = center
_center.addObserver(self, selector: #selector(keyBoardWillShow(notification:)), name: UIResponder.keyboardWillShowNotification, object: nil)
_center.addObserver(self, selector: #selector(keyBoardWillHide(notification:)), name: UIResponder.keyboardWillHideNotification, object: nil)
}
deinit {
_center.removeObserver(self)
}
#objc func keyBoardWillShow(notification: Notification) {
if let keyboardSize = (notification.userInfo?[UIResponder.keyboardFrameEndUserInfoKey] as? NSValue)?.cgRectValue,
let duration = notification.userInfo?[UIResponder.keyboardAnimationDurationUserInfoKey] as? Double {
self.duration = duration
currentHeight = keyboardSize.height
}
}
#objc func keyBoardWillHide(notification: Notification) {
currentHeight = 0
}
}
struct KeyboardHandler: ViewModifier {
let height: CGFloat
let duration: Double
func body(content: Content) -> some View {
content
.padding(.bottom, height)
.animation(.spring(blendDuration: duration))
}
}