Scan a document, find a line, extract numbers below - simulink

Question

I have the following .csv file:
Marker,"loop_-105"
Id,1
"Time (Seconds)","Sig (ts)"
"1.920576","3.98"
"1.957907","31.58"
"1.9912","34.422"
...
Marker,"loop_-102.1"
Id,1
"Time (Seconds)","Sig (ts)"
"4.920576","3.98"
"2.07","31.58"
"1.9912","34.422"
...
I want to open the file, extract the values -105 and -102.1 along with the values in quotes in two matrices. I have tried textscan and regex but did not quite work.
str2double(regexp(filetext, '(?<=loop_[^0-9]*)[0-9]*\.?[0-9]+', 'match'));
find(~cellfun(#isempty,strfind(new_measurement,'Time (Seconds)","Sig (ts)')))

Answer 1

Here is one attempt, I hope I understood correctly what you'd like to achieve.
I used the following file data.csv
Marker,"loop_-105"
Id,1
"Time (Seconds)","Sig (ts)"
"1.920576","3.98"
"1.957907","31.58"
"1.9912","34.422"
"1.920576","3.98"
"1.957907","31.58"
"1.9912","34.422"
Marker,"loop_-102.1"
Id,1
"Time (Seconds)","Sig (ts)"
"4.920576","3.98"
"2.07","31.58"
"1.9912","34.422"
and the following script to read it:
filename = './data.csv';
% read all lines as strings
fid = fopen(filename, 'r');
rawdata = textscan(fid, '%s');
fclose(fid);
% get the single lines
lines = rawdata{1};
% two regexp, one for the Marker, one for the values
startregexp = 'Marker,"loop_(?<startnum>-{0,1}\d+.{0,1}\d*)"';
valueregexp = '"(?<v1>\d+.{0,1}\d*)","(?<v2>\d+.{0,1}\d*)"';
% Data is stored in this cell
result = {};
% Loop through the lines
for lcount = 1:numel(lines)
start = regexp(lines{lcount}, startregexp, 'names');
if ~isempty(start)
% The Marker-Regexp matched, start a new cell entry
result{end+1} = struct(...
'Loop', str2double(start.startnum), ...
'values', []);
continue
end
values = regexp(lines{lcount}, valueregexp, 'names');
if ~isempty(values)
% the value regexp matched. Add data
result{end}.values(end+1, :) = [str2double(values.v1) str2double(values.v2)];
end
end
result is:
>> result
result =
1×2 cell array
{1×1 struct} {1×1 struct}
>> result{1}
ans =
struct with fields:
Loop: -105
values: [6×2 double]
>> result{1}.values
ans =
1.9206 3.9800
1.9579 31.5800
1.9912 34.4220
1.9206 3.9800
1.9579 31.5800
1.9912 34.4220