I am trying to query below document structure
{
_id: '7ja9sjkadja',
parent: {
parentName: 'Super',
firstGenerations: [
{
name: 'First Generation',
secondGenerations: [
{
name: 'Second Generation 1',
value: 'Married'
},
{
name: 'Second Generation 2',
value: 'Single'
},
{
name: 'Second Generation 3',
value: 'Single'
}
]
}
]
}
}
Expected output:
{
firstGenerationName: 'First Generation',
totalCount: 3
values: [
{
categoryName: 'Married (1)',
count: 1,
firstGenerationName: 'First Generation'
},
{
categoryName: 'Single (2)',
count: 2,
firstGenerationName: 'First Generation'
}
]
}
Query tried by me:
db.generations.aggregrate([
{ $project: { 'firstGenerations': '$parent.firstGenerations'} },
{ $unwind: '$firstGenerations'},
{ $unwind: '$firstGenerations.secondGenerations'}
{
$group: {
_id: '$_id',
count: { 'sum': '$secondGenerations.value' },
firstGenerationName: { $first: '$firstGenerations.name'}
}
}
])
I am able to unwind properly but not able to club group functionality by taking one value from parent array and count from second array.
Any help will be appreciated
Basically you need to run $group twice to get inner counts first:
db.collection.aggregate([
{
$unwind: "$parent"
},
{
$unwind: "$parent.firstGenerations"
},
{
$unwind: "$parent.firstGenerations.secondGenerations"
},
{
$group: {
_id: {
fgName: "$parent.firstGenerations.name",
sgValue: "$parent.firstGenerations.secondGenerations.value"
},
count: { $sum: 1 }
}
},
{
$group: {
_id: "$_id.fgName",
values: {
$push: {
categoryName: { $concat: [ "$_id.sgValue", " (", { $toString: "$count" }, ")" ] },
count: "$count",
firstGenerationName: "$_id.fgName"
}
}
}
},
{
$project: {
_id: 0,
firstGenerationName: "$_id",
values: 1,
totalCount: { $sum: "$values.count" }
}
}
])
Mongo Playground
Related
I have grouped all the users by country, but I would also like to have a row showing the grand total (users are tagged to a single country in our use case).
Data Model / Sample Input
The collection is filled with objects representing a country (name) and each contains a list of user objects in an array under users.
{ _id: ObjectId("..."),
name: 'SG',
type: 'COUNTRY',
increment: 200,
users:
[ ObjectId("..."),
ObjectId("..."),
...
Query
db.collection.aggregate([{$match:{type:"COUNTRY"}},{$unwind:"$users"},{$sortByCount:"$name"}])
Current Results
{ _id: 'SG', count: 76 }
{ _id: 'IN', count: 6 }
{ _id: 'US', count: 4 }
{ _id: 'FR', count: 3 }
{ _id: 'UK', count: 2 }
{ _id: 'RU', count: 1 }
{ _id: 'CO', count: 1 }
{ _id: 'DK', count: 1 }
{ _id: 'ID', count: 1 }
{ _id: 'PH', count: 1 }
Expected Results
{ _id: 'SG', count: 76 }
{ _id: 'IN', count: 6 }
{ _id: 'US', count: 4 }
{ _id: 'FR', count: 3 }
{ _id: 'UK', count: 2 }
{ _id: 'RU', count: 1 }
{ _id: 'CO', count: 1 }
{ _id: 'DK', count: 1 }
{ _id: 'ID', count: 1 }
{ _id: 'PH', count: 1 }
{ _id: null, count: 96 } <<< TOTAL COUNT ADDED
Any tips to achieve this without resorting to complex or dirty tricks?
You can also try using $facet to calculate counts by country name and total count, and then combine them together. Something like this:
db.collection.aggregate([
{
$match: {
type: "COUNTRY"
}
},
{
"$unwind": "$users"
},
{
"$facet": {
"groupCountByCountry": [
{
"$sortByCount": "$name"
}
],
"totalCount": [
{
"$group": {
"_id": null,
"count": {
"$sum": 1
}
}
}
]
}
},
{
"$project": {
array: {
"$concatArrays": [
"$groupCountByCountry",
"$totalCount"
]
}
}
},
{
"$unwind": "$array"
},
{
"$replaceRoot": {
"newRoot": "$$ROOT.array"
}
}
])
Here's the playground link.
I recommend just doing this in memory as the alternative is "hacky" but in order to achieve this in Mongo you just need to group all documents, add a new documents and unwind again, like so:
db.collection.aggregate([
{
$group: {
_id: null,
roots: {
$push: "$$ROOT"
},
sum: {
$sum: "$count"
}
}
},
{
$addFields: {
roots: {
"$concatArrays": [
"$roots",
[
{
_id: null,
count: "$sum"
}
]
]
}
}
},
{
$unwind: "$roots"
},
{
$replaceRoot: {
newRoot: "$roots"
}
}
])
Mongo Playground
I've created an aggregate query but for some reason it doesn't seem to work for custom fields created in the aggregation pipeline.
return this.repository.mongo().aggregate([
{
$match: { q1_avg: { $regex: baseQuery['value'], $options: 'i' } }, // NOT WORKING
},
{
$group: {
_id: '$product_sku',
id: { $first: "$_id" },
product_name: { $first: '$product_name' },
product_category: { $first: '$product_category' },
product_sku: { $first: '$product_sku' },
q1_cnt: { $sum: 1 },
q1_votes: { $push: "$final_rating" }
},
},
{
$facet: {
pagination: [ { $count: 'total' } ],
data: [
{
$project: {
_id: 1,
id: 1,
product_name: 1,
product_category: 1,
product_sku: 1,
q1_cnt: 1,
q1_votes: {
$filter: {
input: '$q1_votes',
as: 'item',
cond: { $ne: ['$$item', null] }
}
},
},
},
{
$set: {
q1_avg: { $round: [ { $avg: '$q1_votes' }, 2 ] },
}
},
{ $unset: ['q1_votes'] },
{ $skip: skip },
{ $limit: limit },
{ $sort: sortList }
]
}
},
{ $unwind : "$pagination" },
]).next();
q1_avg value is an integer and as far as I know, regex only works with strings. Could that be the reason
I'm trying to return size of 'orders' and sum of 'item' values for each 'order' for each order from documents like the example document:
orders: [
{
order_id: 1,
items: [
{
item_id: 1,
value:100
},
{
item_id: 2,
value:200
}
]
},
{
order_id: 2,
items: [
{
item_id: 3,
value:300
},
{
item_id: 4,
value:400
}
]
}
]
I'm using following aggregation to return them, everything works fine except I can't get size of 'orders' array because after unwind, 'orders' array is turned into an object and I can't call $size on it since it is an object now.
db.users.aggregate([
{
$unwind: "$orders"
},
{
$project: {
_id: 0,
total_values: {
$reduce: {
input: "$orders.items",
initialValue: 0,
in: { $add: ["$$value", "$$this.value"] }
}
},
order_count: {$size: '$orders'}, //I get 'The argument to $size must be an array, but was of type: object' error
}
},
])
the result I expected is:
{order_count:2, total_values:1000} //For example document
{order_count:3, total_values:1500}
{order_count:5, total_values:2500}
I found a way to get the results that I wanted. Here is the code
db.users.aggregate([
{
$project: {
_id: 1, orders: 1, order_count: { $size: '$orders' }
}
},
{ $unwind: '$orders' },
{
$project: {
_id: '$_id', items: '$orders.items', order_count: '$order_count'
}
},
{ $unwind: '$items' },
{
$project: {
_id: '$_id', sum: { $sum: '$items.value' }, order_count: '$order_count'
}
},
{
$group: {
_id: { _id: '$_id', order_count: '$order_count' }, total_values: { $sum: '$sum' }
}
},
])
output:
{ _id: { _id: ObjectId("5dffc33002ef525620ef09f1"), order_count: 2 }, total_values: 1000 }
{ _id: { _id: ObjectId("5dffc33002ef525620ef09f2"), order_count: 3 }, total_values: 1500 }
I would like to count the status and group them by country.
Data:
[
{ id: 100, status: 'ordered', country: 'US', items: [] },
{ id: 101, status: 'ordered', country: 'UK', items: [] },
{ id: 102, status: 'shipped', country: 'UK', items: [] },
]
Desired aggregation outcome:
[
{ _id: 'US', status: { ordered: 1} },
{ _id: 'UK', status: { ordered: 1, shipped: 1 } }
]
I can $count and $group, but I am not sure how to put this together. Any hint is appreciated.
Thanks,
bluepuama
$group by country and status, and count total
$group by only country and construct array of status and count in key-value format
$set to update status field to object using $arrayToObject
db.collection.aggregate([
{
$group: {
_id: { country: "$country", status: "$status" },
count: { $sum: 1 }
}
},
{
$group: {
_id: "$_id.country",
status: { $push: { k: "$_id.status", v: "$count" } }
}
},
{ $set: { status: { $arrayToObject: "$status" } } }
])
Playground
You can do it with a single $group stage like so:
db.collection.aggregate([
{
$group: {
_id: "$country",
"shipped": {
$sum: {
$cond: [
{
$eq: [
"$status",
"ordered"
]
},
0,
1
]
}
},
"ordered": {
$sum: {
$cond: [
{
$eq: [
"$status",
"shipped"
]
},
0,
1
]
}
}
}
},
{
$project: {
_id: 1,
status: {
shipped: "$shipped",
ordered: "$ordered"
}
}
}
])
Mongo Playground
I have a collection with documents similar to the following format:
{
departure:{name: "abe"},
arrival:{name: "tom"}
},
{
departure:{name: "bob"},
arrival:{name: "abe"}
}
And to get output like so:
{
name: "abe",
departureCount: 1,
arrivalCount: 1
},
{
name: "bob",
departureCount: 1,
arrivalCount: 0
},
{
name: "tom",
departureCount: 0,
arrivalCount: 1
}
I'm able to get the counts individually by doing a query for the specific data like so:
db.sched.aggregate([
{
"$group":{
_id: "$departure.name",
departureCount: {$sum: 1}
}
}
])
But I haven't figured out how to merge the arrival and departure name into one document along with counts for both. Any suggestions on how to accomplish this?
You should use a $map to split your doc into 2, then $unwind and $group..
[
{
$project: {
dep: '$departure.name',
arr: '$arrival.name'
}
},
{
$project: {
f: {
$map: {
input: {
$literal: ['dep', 'arr']
},
as: 'el',
in : {
type: '$$el',
name: {
$cond: [{
$eq: ['$$el', 'dep']
}, '$dep', '$arr']
}
}
}
}
}
},
{
$unwind: '$f'
}, {
$group: {
_id: {
'name': '$f.name'
},
departureCount: {
$sum: {
$cond: [{
$eq: ['$f.type', 'dep']
}, 1, 0]
}
},
arrivalCount: {
$sum: {
$cond: [{
$eq: ['$f.type', 'arr']
}, 1, 0]
}
}
}
}, {
$project: {
_id: 0,
name: '$_id.name',
departureCount: 1,
arrivalCount: 1
}
}
]