When I run this command :
db.runCommand(
{
aggregate:"myColl",
pipeline:[
{
$group:{
_id:{os_name:"$os_name",os_version:"$os_version"},
"events.login":{$sum:"$events.login"},
count:{$sum:NumberInt(1)}}
}
],
cursor:{}
}
)
I receive the error:
The field name 'events.login' cannot contain '.'
How can i do to keep the '.' in the returned field name (ie: events.login)
It's not quiet clear what you're trying to do, So look at these :
Error :
The field name 'events.login' cannot contain '.'
It's because as in $group stage when it creates a new field on each document for a given name, You'll not be able to create it like this : "events.login" means cannot create a sub-doc it has to be an object to a top level field events basically you can not use . notation, So to make it work you need to have one more stage like this :
db.collection.aggregate([{
$group: {
_id: { os_name: "$os_name", os_version: "$os_version" },
"events": { $sum: "$events.login" },
count: { $sum: NumberInt(1) }
}
}, { $addFields: { 'events.login': '$events' } }])
Test : MongoDB-Playground
If in a case you need to update login field inside events field & to retain all other fields inside events, try below query which would get last document in iteration of each _id (this will last document inserted to DB on that _id criteria) & append login to it :
db.collection.aggregate([{
$group: {
_id: { os_name: "$os_name", os_version: "$os_version" },
"login": { $sum: "$events.login" }, 'events': { $last: '$events' },
count: { $sum: NumberInt(1) }
}
}, { $addFields: { 'events.login': '$login' } }, { $project: { login: 0 } }])
Test : MongoDB-Playground
Related
I have an issue that need to insert index number when get data. First i have this data for example:
[
{
_id : 616efd7e56c9530018e318ac
student : {
name: "Alpha"
email: null
nisn: "0408210001"
gender : "female"
}
},
{
_id : 616efd7e56c9530018e318af
student : {
name: "Beta"
email: null
nisn: "0408210001"
gender : "male"
}
}
]
and then i need the output like this one:
[
{
no:1,
id:616efd7e56c9530018e318ac,
name: "Alpha",
nisn: "0408210001"
},
{
no:2,
id:616efd7e56c9530018e318ac,
name: "Beta",
nisn: "0408210002"
}
]
i have tried this code but almost get what i expected.
{
'$project': {
'_id': 0,
'id': '$_id',
'name': '$student.name',
'nisn': '$student.nisn'
}
}
but still confuse how to add the number of index. Is it available to do it in $project or i have to do it other way? Thank you for the effort to answer.
You can use $unwind which can return an index, like this:
db.collection.aggregate([
{
$group: {
_id: 0,
data: {
$push: {
_id: "$_id",
student: "$student"
}
}
}
},
{
$unwind: {path: "$data", includeArrayIndex: "no"}
},
{
"$project": {
"_id": 0,
"id": "$data._id",
"name": "$data.student.name",
"nisn": "$data.student.nisn",
"no": {"$add": ["$no", 1] }
}
}
])
You can see it works here .
I strongly suggest to use a $match step before these steps, otherwise you will group your entire collection into one document.
You need to run a pipeline with a $setWindowFields stage that allows you to add a new field which returns the position of a document (known as the document number) within a partition. The position number creation is made possible by the $documentNumber operator only available in the $setWindowFields stage.
The partition could be an extra field (which is constant) that can act as the window partition.
The final stage in the pipeline is the $replaceWith step which will promote the student embedded document to the top-level as well as replacing all input documents with the specified document.
Running the following aggregation will yield the desired results:
db.collection.aggregate([
{ $addFields: { _partition: 'students' }},
{ $setWindowFields: {
partitionBy: '$_partition',
sortBy: { _id: -1 },
output: { no: { $documentNumber: {} } }
} },
{ $replaceWith: {
$mergeObjects: [
{ id: '$_id', no: '$no' },
'$student'
]
} }
])
I got a question that I would expect to be pretty simple, but I cannot figure it out. What I want to do is this:
Find all documents in a collection and:
sort the documents by a certain date field
apply distinct on one of its other fields, but return the whole document
Best shown in an example.
This is a mock input:
[
{
"commandName" : "migration_a",
"executionDate" : ISODate("1998-11-04T18:46:14.000Z")
},
{
"commandName" : "migration_a",
"executionDate" : ISODate("1970-05-09T20:16:37.000Z")
},
{
"commandName" : "migration_a",
"executionDate" : ISODate("2005-11-08T11:58:52.000Z")
},
{
"commandName" : "migration_b",
"executionDate" : ISODate("2016-06-02T19:48:34.000Z")
}
]
The expected output is:
[
{
"commandName" : "migration_a",
"executionDate" : ISODate("2005-11-08T11:58:52.000Z")
},
{
"commandName" : "migration_b",
"executionDate" : ISODate("2016-06-02T19:48:34.000Z")
}
]
Or, in other words:
Group the input data by the commandName field
Inside each group sort the documents
Return the newest document from each group
My attempts to write this query have failed:
The distinct() function will only return the value of the field I am distinct-ing on, not the whole document. That makes it unsuitable for my case.
Tried writing an aggregate query, but ran into an issue of how to sort-and-select a single document from inside of each group? The sort aggreation stage will sort the groups among one other, which is not what I want.
I am not too well-versed in Mongo and this is where I hit a wall. Any ideas on how to continue?
For reference, this is the work-in-progress aggregation query I am trying to expand on:
db.getCollection('some_collection').aggregate([
{ $group: { '_id': '$commandName', 'docs': {$addToSet: '$$ROOT'} } },
{ $sort: {'_id.docs.???': 1}}
])
Post-resolved edit
Thank you for the answers. I got what I needed. For future reference, this is the full query that will do what was requested and also return a list of the filtered documents, not groups.
db.getCollection('some_collection').aggregate([
{ $sort: {'executionDate': 1}},
{ $group: { '_id': '$commandName', 'result': { $last: '$$ROOT'} } },
{ $replaceRoot: {newRoot: '$result'} }
])
The query result without the $replaceRoot stage would be:
[
{
"_id": "migration_a",
"result": {
"commandName" : "migration_a",
"executionDate" : ISODate("2005-11-08T11:58:52.000Z")
}
},
{
"_id": "migration_b",
"result": {
"commandName" : "migration_b",
"executionDate" : ISODate("2016-06-02T19:48:34.000Z")
}
}
]
The outer _id and _result are just "group-wrappers" around the actual document I want, which is nested under the result key. Moving the nested document to the root of the result is done using the $replaceRoot stage. The query result when using that stage is:
[
{
"commandName" : "migration_a",
"executionDate" : ISODate("2005-11-08T11:58:52.000Z")
},
{
"commandName" : "migration_b",
"executionDate" : ISODate("2016-06-02T19:48:34.000Z")
}
]
Try this:
db.getCollection('some_collection').aggregate([
{ $sort: {'executionDate': -1}},
{ $group: { '_id': '$commandName', 'doc': {$first: '$$ROOT'} } }
])
I believe this will result in what you're looking for:
db.collection.aggregate([
{
$group: {
"_id": "$commandName",
"executionDate": {
"$last": "$executionDate"
}
}
}
])
You can check it out here
Of course, if you want to match your expected output exactly, you can add a sort (this may not be necessary since your goal is to simply return the newest document from each group):
{
$sort: {
"executionDate": 1
}
}
You can check this version out here.
The use-case the question presents is nearly covered in the $last aggregation operator documentation.
Which summarises:
the $group stage should follow a $sort stage to have the input
documents in a defined order. Since $last simply picks the last
document from a group.
Query: Link
db.collection.aggregate([
{
$sort: {
executionDate: 1
}
},
{
$group: {
_id: "$commandName",
executionDate: {
$last: "$executionDate"
}
}
}
]);
I tried searching on here but couldn't really find what I need. I have documents like this:
{
appletype:Granny,
color:Green,
datePicked:2015-01-26,
dateRipe:2015-01-24,
numPicked:3
},
{
appletype:Granny,
color:Green,
datePicked:2015-01-01,
dateRipe:2014-12-28,
numPicked:6
}
I would like to return only those apples picked latest, will all fields. I want my query to return me the first document only essentially. When I try to do:
db.collection.aggregate([
{ $match : { "appletype" : "Granny" } },
{ $sort : { "datePicked" : 1 } },
{ $group : { "_id" : { "appletype" : "$appletype" },
"datePicked" : { $max : "$datePicked" } },
])
It does return me all the apples picked latest, however with only appletype:Granny and datePicked:2015-01-26. I need the remaining fields. I tries using $project and adding all the fields, but it didn't get me what I needed. Also, when I added the other fields to the group, since datePicked is unique, it returned both records.
How can I go about returning all fields, for only the latest datePicked?
Thanks!
From your description, it sounds like you want one document for each of the types of apple in your collection and showing the document with the most recent datePicked value.
Here is an aggregate query for that:
db.collection.aggregate([
{ $sort: { "datePicked": -1 },
{ $group: { _id: "$appletype", color: { $first: "$color" }, datePicked: { $first: "$datePicked" }, dateRipe: { $first: "$dateRipe" }, numPicked: { $first: "$numPicked" } } },
{ $project: { _id: 0, color: 1, datePicked: 1, dateRipe: 1, numPicked: 1, appletype: "$_id" } }
])
But then based on the aggregate query you've written, it looks like you're trying to get this:
db.collection.find({appletype: "Granny"}).sort({datePicked: -1}).limit(1);
I would to like to know whether the group by is possible for a particular substring of a field in mongodb rather than grouping it by the whole field itself.
Eg:
I have a field PostId containing values abcde:123,abcde:456, abcde:789.....field name is PostId.
Can i group by just the string abcde rather the whole field that is (abcde:123).
I tried the below query, its grouping it by the whole postid field. But i require it to just group by the part of string in postId.
db.noundata.aggregate({
$match: {
EntityId: 334,
SubProductId: 1,
AdjScore: {
$gt: 0.0
},
NounWord: 'foot'
}
}, {
$group: {
_id: {
PostId: "$PostId"
},
NounWeightage: {
$sum: 1
}
}
}, {
$sort: {
AdjScore: -1
}
}, {
$limit: 10
})
What i require is, is there a possible way to group by on regex rather than the whole field
thanx
You can use $substr in aggregation framework within a $project to extract the needed part of the string. After you can use it to group.
One example:
> db.collection.aggregate({$project:{a_whole:'$a',a_substr:{$substr:['$a',2,3]}}})
{
"result" : [
{
"a_whole" : "abc:123",
"a_substr" : "c:1"
},
{
"a_whole" : "ab:123",
"a_substr" : ":12"
},
{
"a_whole" : "abcd:123",
"a_substr" : "cd:"
}
],
"ok" : 1
}
I have the following issue:
this query return 1 result which is what I want:
> db.items.aggregate([ {$group: { "_id": "$id", version: { $max: "$version" } } }])
{
"result" : [
{
"_id" : "b91e51e9-6317-4030-a9a6-e7f71d0f2161",
"version" : 1.2000000000000002
}
],
"ok" : 1
}
this query ( I just added projection so I can later query for the entire document) return multiple results. What am I doing wrong?
> db.items.aggregate([ {$group: { "_id": "$id", version: { $max: "$version" } }, $project: { _id : 1 } }])
{
"result" : [
{
"_id" : ObjectId("5139310a3899d457ee000003")
},
{
"_id" : ObjectId("513931053899d457ee000002")
},
{
"_id" : ObjectId("513930fd3899d457ee000001")
}
],
"ok" : 1
}
found the answer
1. first I need to get all the _ids
db.items.aggregate( [
{ '$match': { 'owner.id': '9e748c81-0f71-4eda-a710-576314ef3fa' } },
{ '$group': { _id: '$item.id', dbid: { $max: "$_id" } } }
]);
2. then i need to query the documents
db.items.find({ _id: { '$in': "IDs returned from aggregate" } });
which will look like this:
db.items.find({ _id: { '$in': [ '1', '2', '3' ] } });
( I know its late but still answering it so that other people don't have to go search for the right answer somewhere else )
See to the answer of Deka, this will do your job.
Not all accumulators are available in $project stage. We need to consider what we can do in project with respect to accumulators and what we can do in group. Let's take a look at this:
db.companies.aggregate([{
$match: {
funding_rounds: {
$ne: []
}
}
}, {
$unwind: "$funding_rounds"
}, {
$sort: {
"funding_rounds.funded_year": 1,
"funding_rounds.funded_month": 1,
"funding_rounds.funded_day": 1
}
}, {
$group: {
_id: {
company: "$name"
},
funding: {
$push: {
amount: "$funding_rounds.raised_amount",
year: "$funding_rounds.funded_year"
}
}
}
}, ]).pretty()
Where we're checking if any of the funding_rounds is not empty. Then it's unwind-ed to $sort and to later stages. We'll see one document for each element of the funding_rounds array for every company. So, the first thing we're going to do here is to $sort based on:
funding_rounds.funded_year
funding_rounds.funded_month
funding_rounds.funded_day
In the group stage by company name, the array is getting built using $push. $push is supposed to be part of a document specified as the value for a field we name in a group stage. We can push on any valid expression. In this case, we're pushing on documents to this array and for every document that we push it's being added to the end of the array that we're accumulating. In this case, we're pushing on documents that are built from the raised_amount and funded_year. So, the $group stage is a stream of documents that have an _id where we're specifying the company name.
Notice that $push is available in $group stages but not in $project stage. This is because $group stages are designed to take a sequence of documents and accumulate values based on that stream of documents.
$project on the other hand, works with one document at a time. So, we can calculate an average on an array within an individual document inside a project stage. But doing something like this where one at a time, we're seeing documents and for every document, it passes through the group stage pushing on a new value, well that's something that the $project stage is just not designed to do. For that type of operation we want to use $group.
Let's take a look at another example:
db.companies.aggregate([{
$match: {
funding_rounds: {
$exists: true,
$ne: []
}
}
}, {
$unwind: "$funding_rounds"
}, {
$sort: {
"funding_rounds.funded_year": 1,
"funding_rounds.funded_month": 1,
"funding_rounds.funded_day": 1
}
}, {
$group: {
_id: {
company: "$name"
},
first_round: {
$first: "$funding_rounds"
},
last_round: {
$last: "$funding_rounds"
},
num_rounds: {
$sum: 1
},
total_raised: {
$sum: "$funding_rounds.raised_amount"
}
}
}, {
$project: {
_id: 0,
company: "$_id.company",
first_round: {
amount: "$first_round.raised_amount",
article: "$first_round.source_url",
year: "$first_round.funded_year"
},
last_round: {
amount: "$last_round.raised_amount",
article: "$last_round.source_url",
year: "$last_round.funded_year"
},
num_rounds: 1,
total_raised: 1,
}
}, {
$sort: {
total_raised: -1
}
}]).pretty()
In the $group stage, we're using $first and $last accumulators. Right, again we can see that as with $push - we can't use $first and $last in project stages. Because again, project stages are not designed to accumulate values based on multiple documents. Rather they're designed to reshape documents one at a time. Total number of rounds is calculated using the $sum operator. The value 1 simply counts the number of documents passed through that group together with each document that matches or is grouped under a given _id value. The project may seem complex, but it's just making the output pretty. It's just that it's including num_rounds and total_raised from the previous document.