Win-PS2EXE - Respect the location of the resulting executable - powershell

Question

Take these settings for the program Win-PS2EXE:
This is so that the console will show when the exe file is clicked on.
And this code:
$inf_file = "$PSScriptRoot\setup-files\install.inf"
write-host """$inf_file"""
timeout 10
Let us say that the path of the new executable is W:\Apps\Install Scheme.exe
Which means the $inf_file is here W:\Apps\setup-files\install.inf
When I click the converted exe file I get this.
Is there any way to get the correct path of W:\Apps\setup-files\install.inf so that the executable recognises the location of itself when clicked.
I thought that $PSScriptRoot would work.
I'm lost as to how to get around this as the exe file will eventually depend on knowing its location.

Answer 1

Here's the code that can accomplish that.
Function Get-PSScriptPath {
<#
.SYNOPSIS
Returns the current filepath of the .ps1 or compiled .exe with Win-PS2EXE.
.DESCRIPTION
This will return the path of the file. This will work when the .ps1 file is
converted with Win-PS2EXE
.NOTES
Author: Ste
Date Created: 2021.05.03
Tested with PowerShell 5.1 and 7.1.
Posted here: https://stackoverflow.com/q/60121313/8262102
.PARAMETER None
NA
.INPUTS
None. You cannot pipe objects to Get-PSScriptPath.
.OUTPUTS
Returns the current filepath of the .ps1 or compiled .exe with Win-PS2EXE.
.EXAMPLE (When run from a .ps1 file)
PS> Get-PSScriptPath
PS> C:\Users\Desktop\temp.ps1
.EXAMPLE (When run from a compiled .exe file with Win-PS2EXE.
PS> Get-PSScriptPath
PS> C:\Users\Desktop\temp.exe
#>
if ([System.IO.Path]::GetExtension($PSCommandPath) -eq '.ps1') {
$psScriptPath = $PSCommandPath
} else {
# This enables the script to be compiles and get the directory of it.
$psScriptPath = [System.Diagnostics.Process]::GetCurrentProcess().MainModule.FileName
}
return $psScriptPath
}
Get-PSScriptPath

Answer 2

To offer a pragmatic, concise alternative (PSv3+) that always reports the script path as a full path:
One-liner:
$scriptDir = if (-not $PSScriptRoot) { Split-Path -Parent (Convert-Path ([environment]::GetCommandLineArgs()[0])) } else { $PSScriptRoot }
Annotated form:
$scriptDir = if (-not $PSScriptRoot) { # $PSScriptRoot not defined?
# Get the path of the executable *as invoked*, via
# [environment]::GetCommandLineArgs()[0],
# resolve it to a full path with Convert-Path, then get its directory path
Split-Path -Parent (Convert-Path ([environment]::GetCommandLineArgs()[0]))
}
else {
# Use the automatic variable.
$PSScriptRoot
}