This is my single document of a collection. I want to convert this format data to
{
"_id" : ObjectId("5e311e8bb94999f1be0d5ead"),
"dealer_code" : "123",
"mappinginfo" : [
{
"territory" : "MORADABAD",
"area" : "UPH",
"zone" : "N"
}
],
"active" : NumberInt(1),
}
like this data
{
"_id" : ObjectId("5e311e8bb94999f1be0d5ead"),
"dealer_code" : "123",
"territory" : "MORADABAD",
"area" : "UPH",
"zone" : "N"
"active" : NumberInt(1),
}
Here is the Query.
db.collection.aggregate([
{
$unwind: "$mappinginfo"
},
{
$project: {
_id: 1,
active: 1,
dealer_code: 1,
territory: "$mappinginfo.territory",
area: "$mappinginfo.area",
zone: "$mappinginfo.zone",
}
},
])
db.collection.aggregate([
{ $unwind: "$mappinginfo" },
{
$project:
{
_id: 1,
dealer_code: 1,
active: 1,
territory: "$mappinginfo.territory",
area: "$mappinginfo.area",
zone: "$mappinginfo.zone"
}
},
{ $out: "existing_collection_name" }
])
Make use of aggregation pipeline.
Solution -
db.test.aggregate([
{ $unwind: "$mappinginfo" },
{ $project: {
dealer_code: 1,
territory: "$mappinginfo.territory",
area: "$mappinginfo.area",
zone: "$mappinginfo.zone",
active: 1
}}
]);
Explanation
Aggregation pipeline as the name is, works on data in pipeline. A pipeline has an input, an operator and an output. For the example above -
First stage is an unwind stage which will be fed with an entire collection. The unwind operator will iterate on individual documents and for each document it will create as many copies as are elements in mappinginfo field. For your case it will only create just one copy. After the unwind stage the resulting document would look like this -
[{
"_id" : ObjectId("5e311e8bb94999f1be0d5ead"),
"dealer_code" : "123",
"mappinginfo": {
"territory" : "MORADABAD",
"area" : "UPH",
"zone" : "N"
}
"active" : NumberInt(1),
}]
Notice that the mappinginfo is no more a list.
Next stage is a projection stage. $project operator will simply take the above list of documents as input and for each document either it will simply project the field as it is or will change the value of the field based on what is available in the current document. { "active": 1 } implies projecting the value as it is. { "zone": "$mappinginfo.zone" } implies projecting the value of zone inside mappinginfo field under the name zone at the root level.
More info on both operators -
- $unwind
- $project
Related
This is an example of a data document
{
"_id" : ObjectId("5f437e7846103b2ad0fc5d7d"),
"order_no" : "O-200824-AGFJDQW",
"shipment_no" : "S-200824-AGWCRRM",
"member_id" : 2200140,
"ponta_id" : "9990010100280214",
"plu" : 14723,
"product_name" : "AQUA Air Mineral Botol Air Pet 600ml",
"qty" : 2,
"store_id" : "TD46",
"stock_on_hand" : 0,
"transaction_date" : ISODate("2020-08-24T08:28:29.931Z"),
"created_date" : ISODate("2020-08-24T08:46:48.441Z")
}
this is the data query that I run
var bulan = 12 //month is written with number. example: August = 8
db.log_stock_oos.aggregate([
{
$project: {
month: {
$month: '$transaction_date'
}
}
},
{
$match: {month: bulan}
}
]);
but the result is like this after I run the query
{
"_id" : ObjectId("5f44689607fe453fbfba433e"),
"month" : 12
}
how to make the output exactly like the document display that I attached above??
this is my reference
When you use the projection, its kind of if your value 1 then include the field, if your value 0 then exclude the field from the whole documents. Projection
You can do two things
Use the projection
db.collection.aggregate([
{
$project: {
month: {
$month: "$transaction_date"
},
order_no: 1,
shipment_no: 1,
member_id: 1,
//other fields like above with the value 1
}
},
// match stages
])
Use $addFields
use $addFields incited of $project in your code. If will create a filed if not exists in your document, else it will overwrite the field
I am trying to find the average sell of each console xbox, ps4, and wii. I am working with nested documents, and I try to access type to filter "sell" using db.console.find({"market.type":"sell"}); but I end up getting "online" type values as well.
Document 1:
_id:("111111111111111111111111")
market:Array
0:Object
type:"sell"
console:"Xbox"
amount:399
1:Object
type:"online"
console:"PS4"
amount:359
2:Object
type:"sell"
console:"xbox"
amount:349
Since you need to filter the sub-documents from a documents so simply find will not work to filter the sub-documents.
You have to use aggregation pipeline as below:
> db.st9.aggregate([
{
$unwind:"$market"
},
{
$match: {"market.type":"sell"}
},
{
$group: {_id:"$market.console", "avg": {$avg:"$market.amount"}, "count": {$sum:1}, "totalSum": {$sum: "$market.amount"} }
}
])
Output:
{ "_id" : "PS4", "avg" : 300, "count" : 1, "totalSum" : 300 }
{ "_id" : "Xbox", "avg" : 359, "count" : 3, "totalSum" : 1077 }
>
For more reference on aggregation pipeline check below official mongo db documentations:
$unwind
$match
$group
It's one of my data as JSON format:
{
"_id" : ObjectId("5bfdb412a80939b6ed682090"),
"accounts" : [
{
"_id" : ObjectId("5bf106eee639bd0df4bd8e05"),
"accountType" : "DDA",
"productName" : "DDA1"
},
{
"_id" : ObjectId("5bf106eee639bd0df4bd8df8"),
"accountType" : "VSA",
"productName" : "VSA1"
},
{
"_id" : ObjectId("5bf106eee639bd0df4bd8df9"),
"accountType" : "VSA",
"productName" : "VSA2"
}
]
}
I want to make a query to get all productName(no duplicate) of accountType = VSA.
I write a mongo query:
db.Collection.distinct("accounts.productName", {"accounts.accountType": "VSA" })
I expect: ['VSA1', 'VSA2']
I get: ['DDA','VSA1', 'VSA2']
Anybody knows why the query doesn't work in distinct?
Second parameter of distinct method represents:
A query that specifies the documents from which to retrieve the distinct values.
But the thing is that you showed only one document with nested array of elements so whole document will be returned for your condition "accounts.accountType": "VSA".
To fix that you have to use Aggregation Framework and $unwind nested array before you apply the filtering and then you can use $group with $addToSet to get unique values. Try:
db.col.aggregate([
{
$unwind: "$accounts"
},
{
$match: {
"accounts.accountType": "VSA"
}
},
{
$group: {
_id: null,
uniqueProductNames: { $addToSet: "$accounts.productName" }
}
}
])
which prints:
{ "_id" : null, "uniqueProductNames" : [ "VSA2", "VSA1" ] }
Lets say I have a collection called phone_audit with document entries of the following form - _id which is the phone number, and value containing items that always contains 2 entries (id, and a date).
Please see below:
{
"_id" : {
"phone_number" : "+012345678"
},
"value" : {
"items" : [
{
"_id" : "c14b4ac1db691680a3fb65320fba7261",
"updated_at" : ISODate("2016-03-14T12:35:06.533Z")
},
{
"_id" : "986b58e55f8606270f8a43cd7f32392b",
"updated_at" : ISODate("2016-07-23T11:17:53.552Z")
}
]
}
},
......
I need to get a list of _id values for every entry in that collection representing the older of the two items in each document.
So in the above - result would be [c14b4ac1db691680a3fb65320fba7261,...]
Any pointers at the type of query to execute would be v.helpful even if the exact syntax is not correct.
With aggregate(), you can $unwind value.items, $sort by update_at, then use $first to get the oldest:
[
{
"$unwind": "$value.items"
},
{
"$sort": { "value.items.updated_at": 1 }
},
{
"$group":{
_id: "$_id.phone_number",
oldest:{$first:"$value.items"}
}
},
{
"$project":{
value_id: "$oldest._id"
}
}
]
I am new in mongodb and i want to remove the some element in array.
my document as below
{
"_id" : ObjectId("4d525ab2924f0000000022ad"),
"name" : "hello",
"time" : [
{
"stamp" : "2010-07-01T12:01:03.75+02:00",
"reason" : "new"
},
{
"stamp" : "2010-07-02T16:03:48.187+03:00",
"reason" : "update"
},
{
"stamp" : "2010-07-02T16:03:48.187+04:00",
"reason" : "update"
},
{
"stamp" : "2010-07-02T16:03:48.187+05:00",
"reason" : "update"
},
{
"stamp" : "2010-07-02T16:03:48.187+06:00",
"reason" : "update"
}
]
}
in document, i want to remove first element(reason:new) and last element(06:00) .
and i want to do it using mongoquery, i am not using any java/php driver.
If I'm understanding you correctly, you want to remove the first and last elements of the array if the size of the array is greater than 3. You can do this by using the findAndModify query. In mongo shell you would be using this command:
db.collection.findAndModify({
query: { $where: "this.time.length > 3" },
update: { $pop: {time: 1}, $pop: {time: -1} },
new: true
});
This would find the document in your collection which matches the $where clause.
The $where field allows you to specify any valid javascript method. Please note that it applies the update only to the first matched document.
You might want to look at the following docs also:
http://www.mongodb.org/display/DOCS/Advanced+Queries#AdvancedQueries-JavascriptExpressionsand%7B%7B%24where%7D%7D for more on the $where clause.
http://www.mongodb.org/display/DOCS/Updating#Updating-%24pop for
more on $pop.
http://www.mongodb.org/display/DOCS/findAndModify+Command for more
on findAndModify.
You could update it with { $pop: { time: 1 } } to remove the last one, and { $pop: { time : -1 } } to remove the first one. There is probably a better way to handle it though.
#javaamtho you cannot test for a size greater than 3 but only if it is exactly 3, for size greater than x number you should use the $inc operator and have a field you either 1 or -1 to in order to keep track when you remove or add items (use a separate field outside the array as below, time_count)
{
"_id" : ObjectId("4d525ab2924f0000000022ad"),
"name" : "hello",
"time_count" : 5,
"time" : [
{
"stamp" : "2010-07-01T12:01:03.75+02:00",
"reason" : "new"
},
{
"stamp" : "2010-07-02T16:03:48.187+03:00",
"reason" : "update"
},
{
"stamp" : "2010-07-02T16:03:48.187+04:00",
"reason" : "update"
},
{
"stamp" : "2010-07-02T16:03:48.187+05:00",
"reason" : "update"
},
{
"stamp" : "2010-07-02T16:03:48.187+06:00",
"reason" : "update"
}
]
}
If you would like to leave these time elements, you can use aggregate command from mongo 2.2+ to retrieve min and max time elements, unset all time elements, and push min and max versions (with some modifications it could do your job):
smax=db.collection.aggregate([{$unwind: "$time"},
{$project: {tstamp:"$time.stamp",treason:"$time.reason"}},
{$group: {_id:"$_id",max:{$max: "$tstamp"}}},
{$sort: {max:1}}])
smin=db.collection.aggregate([{$unwind: "$time"},
{$project: {tstamp:"$time.stamp",treason:"$time.reason"}},
{$group: {_id:"$_id",min:{$min: "$tstamp"}}},
{$sort: {min:1}}])
db.students.update({},{$unset: {"scores": 1}},false,true)
smax.result.forEach(function(o)
{db.collection.update({_id:o._id},{$push:
{"time": {stamp: o.max ,reason: "new"}}},false,true)})
smin.result.forEach(function(o)
{db.collection.update({_id:o._id},{$push:
{"time": {stamp: o.min ,reason: "update"}}},false,true)})
db.collection.findAndModify({
query: {$where: "this.time.length > 3"},
update: {$pop: {time: 1}, $pop{time: -1}},
new: true });
convert to PHP