Read a file, count delimiters and output line number with mismatched delimiter - powershell

Question

I have a file named: test_file.txt. The second line has 4 pipe delimiters and all other lines except 2nd line has 3 pipe delimiters.
I just want to output line 2 since it has one more delimiter than other lines.
$colCnt = "C:\test.txt"
[int]$LastSplitCount = $Null
Get-Content $colCnt | ?{$_} | Select -Skip 1 | %{if($LastSplitCount -and !
($_.split("|").Count -eq $LastSplitCount))
{"Process stopped at line number $($_.psobject.Properties.value[5]) for column count mis-match.";break}
elseif(!$LastSplitCount){$LastSplitCount = $_.split("|").Count}}

Answer 1

If your text file looks anything like this:
blah|using|three|delimiters
blah|using|four |delimiter |characters
blah|using|three|delimiters
blah|using|four |delimiter |characters
blah|using two |delimiters
The the following code should output the lines with more (or less) than 3 | delimiters:
$line = 0
switch -Regex -File "C:\test.txt" {
'^(?:[^|]*\|){3}[^|]*$' { $line++ } # this line is OK, just increase the line counter
default { "Bad delimiter count in line {0}: '{1}'" -f ++$line, $_ }
}
Output:
Bad delimiter count in line 2: 'blah|using|four |delimiter |characters'
Bad delimiter count in line 4: 'blah|using|four |delimiter |characters'
Bad delimiter count in line 5: 'blah|using two |delimiters'
Regex details:
^ Assert position at the beginning of the string
(?: Match the regular expression below
[^|] Match any character that is NOT a “|”
* Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
\| Match the character “|” literally
){3} Exactly 3 times
[^|] Match any character that is NOT a “|”
* Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
$ Assert position at the end of the string (or before the line break at the end of the string, if any)