mongoose Look for an exact word in a phrase - mongodb

As of now when I search for a text, it is searching through each character using this code:
model.find( { title: { $regex: /word/i } } )
but the result comes like 'word', 'word123' or '333word3' and I want only the titles that contain 'word' word in it. eg: 'this is a word'

Simply put \b allows you to perform a “whole words only” search using a regular expression in the form of \bword\b
Model.find({
title: {
$regex: "\\bword\\b"
}
})
//or
Model.find({
title: /\bword\b/
})
If you want ignore such cases: foo-word, bar:word, word-buz use this:
Model.find({
title: {
$regex: "\\b(^|\\s|[^\\W])word(\\s|[^\\W]|$)\\b"
}
})

You're regex expression dosen't exclude those options you said
You need to either:
Change up the regex to something like / word /i if you want to force a space around the word, mind you if combinations like word-word2 are relevant you'll have to account for those as well in the regex you form.
Use Mongo's $text option, for that you'll have to build a text index on that field. Keep in mind that Mongo stems words when it indexes the text field meaning a word like cars would become car meaning this might not be the best option for you if an exact match is a requirement.

Related

mongodb $regex not working with $options x

I have models collection of documents in mongodb atlas. This is how document looks.
{
name: "Iphone 11 Pro Max",
description: "",
}
I have a value like "Iphone11ProMax", that I retrieved from the URL params. Now I want to query the above document with this value. But wasn't able to because the value I have doesn't have spaces and I can not manually insert spaces since params changes. so I tried using $regex operator like this
const {name} = req.params;
const pattern = new RegExp(name);
Model.findOne({name: {$regex: pattern, $options: 'x'}});
Since 'x' option ignores the any whitespaces, I thought it might work but it did not. Any suggestions on this?
The "$regex" "$options" "x" only ignores whitespace in the regex pattern, not the target string.
There are several options to query your collection with the value retrieved from the URL. One option is to programmatically place /s* between each character in this value to use as your "$regex" pattern. After transforming this value, the query could be like this.
N.B.: You may or may not need to "escape" \ in the "$regex".
db.collection.find({
"name": {
// put "\\s*" between every character in regex
"$regex": "I\\s*p\\s*h\\s*o\\s*n\\s*e\\s*1\\s*1\\s*P\\s*r\\s*o\\s*M\\s*a\\s*x"
}
})
Try it on mongoplayground.net.

MongoDB and NextJS: Find a certain data matches regardless if uppercase or lowercase

The goal of this code is to display the current numbers of death, recoveries and critical for covid 19 around the world.
The search function codes are as follows:
const search = (e) => {
e.preventDefault() //to avoid page redirection
const countryMatch = countryCollection.find(country => country.country_name === targetCountry)
if (!countryMatch || countryMatch === null|| countryMatch === 'undefined') {
alert("Country Does Not Exist, use another name.")
setName("")
setTargetCountry("")
} else {
setName(countryMatch.country_name)
setDeathCount(toNum(countryMatch.deaths))
setCriticalCount(toNum(countryMatch.serious_critical))
setRecoveryCount(toNum(countryMatch.total_recovered))
}
}
Our task is to find a country regardless if its in upper or lower case. Eg: Malaysia vs malaysia.
REGULAR EXPRESSION
What you need is regular expression or RegExp. MongoDb supports regular expression for your searches.
In Your case it can be something like
countryCollections.find({'country':new RegExp(countryName,flag)},callback)
flag determines how you want to search
for case insensitive search use 'i'
More about RegExp can be found on mongoDB docs https://docs.mongodb.com/manual/reference/operator/query/regex/
According to your usage of MongoDB, I would say, that this case is an excellent case to using text indexes.
Here is an example for you:
Schema.index(
// making field available for $text search and $meta sorting
{
'field': 'text',
'embedDoc.field': 'text',
},
{
//options of index
weights: // weight for each field
{
'field': 2,
'embedDoc.field': 1,
},
name: 'Countries', // Index Name for Mongo Compass and .explain debug
})
I guess you should try that. It will solve all your potential problems with text search. Like ' or diacritic symbols in searching, lower-uppercase and so on. But please, check the documentation of text indexes, before implementing them, it's quite sensitive and flexible for any cases. But there is no universal silver bullet.

MongoDB text search: find both words in one document [duplicate]

I have an index on an array "keys" that I am using to provide full text functionality to my applicaiton.
With the release of 2.4.3, I'd like to utilize the "text" index type. I insured a "text" index type on my array "keys" and it seems to work SUPER fast (faster than my old keywords full text method).
The problem is, my app assumes that fields are inclusive (AND). By default, the text search ORs my parameters.
Does anyone know of a way to run a text search inclusively?
For example:
db.supplies.runCommand("text", {search:"printer ink"})
should return results with both printer and ink, instead of all results with either printer or ink.
Give a try to:
db.supplies.runCommand("text", {search:"\"printer\" \"ink\""})
Also, here's a quote from docs:
If the search string includes phrases, the search performs an AND with
any other terms in the search string; e.g. search for ""twinkle
twinkle" little star" searches for "twinkle twinkle" and ("little" or
"star").
You can wrap each word in double-quotes:
let keywords = ctx.params.query.split(/\s+/).map(kw => `"${kw}"`).join(' ');
match.$text = { $search: keywords, $caseSensitive: false };
There is a downside if the user inputs a quoted string this will not work. You'd have to parse out quoted strings first.
As #alecxe pointed out earlier, to do AND search on text index column you need to double quote each search word.
Below is a quick one-liner for your requirement.
db.supplies.runCommand("text", {search: "printer ink".split(" ").map(str => "\""+str+"\"").join(' ')})
Here is a simple function I made to search using subwords in node. Hope it helps someone
Let's suppose a user search for pri nks so it should satisfy printer and inks but $text search doesn't allow for this so here is my simple function:
var makeTextFilter = (text) => {
var wordSplited = text.split(/\s+/);
/** Regex generation for words */
var regToMatch = new RegExp(wordSplited.join("|"), 'gi');
let filter = [];
searchFieldArray.map((item,i) => {
filter.push({});
filter[i][item] = {
$regex: regToMatch,
$options: 'i'
}
})
return filter;
}
and use it in your query like this
let query = {...query, $or: makeTextFilter(textInputFromUser)}
tableName.find(query, function (err, cargo_list)

Case Insensitive Search in MongoDB - no Regex and no toLower(), toUpper() [duplicate]

Example:
> db.stuff.save({"foo":"bar"});
> db.stuff.find({"foo":"bar"}).count();
1
> db.stuff.find({"foo":"BAR"}).count();
0
You could use a regex.
In your example that would be:
db.stuff.find( { foo: /^bar$/i } );
I must say, though, maybe you could just downcase (or upcase) the value on the way in rather than incurring the extra cost every time you find it. Obviously this wont work for people's names and such, but maybe use-cases like tags.
UPDATE:
The original answer is now obsolete. Mongodb now supports advanced full text searching, with many features.
ORIGINAL ANSWER:
It should be noted that searching with regex's case insensitive /i means that mongodb cannot search by index, so queries against large datasets can take a long time.
Even with small datasets, it's not very efficient. You take a far bigger cpu hit than your query warrants, which could become an issue if you are trying to achieve scale.
As an alternative, you can store an uppercase copy and search against that. For instance, I have a User table that has a username which is mixed case, but the id is an uppercase copy of the username. This ensures case-sensitive duplication is impossible (having both "Foo" and "foo" will not be allowed), and I can search by id = username.toUpperCase() to get a case-insensitive search for username.
If your field is large, such as a message body, duplicating data is probably not a good option. I believe using an extraneous indexer like Apache Lucene is the best option in that case.
Starting with MongoDB 3.4, the recommended way to perform fast case-insensitive searches is to use a Case Insensitive Index.
I personally emailed one of the founders to please get this working, and he made it happen! It was an issue on JIRA since 2009, and many have requested the feature. Here's how it works:
A case-insensitive index is made by specifying a collation with a strength of either 1 or 2. You can create a case-insensitive index like this:
db.cities.createIndex(
{ city: 1 },
{
collation: {
locale: 'en',
strength: 2
}
}
);
You can also specify a default collation per collection when you create them:
db.createCollection('cities', { collation: { locale: 'en', strength: 2 } } );
In either case, in order to use the case-insensitive index, you need to specify the same collation in the find operation that was used when creating the index or the collection:
db.cities.find(
{ city: 'new york' }
).collation(
{ locale: 'en', strength: 2 }
);
This will return "New York", "new york", "New york" etc.
Other notes
The answers suggesting to use full-text search are wrong in this case (and potentially dangerous). The question was about making a case-insensitive query, e.g. username: 'bill' matching BILL or Bill, not a full-text search query, which would also match stemmed words of bill, such as Bills, billed etc.
The answers suggesting to use regular expressions are slow, because even with indexes, the documentation states:
"Case insensitive regular expression queries generally cannot use indexes effectively. The $regex implementation is not collation-aware and is unable to utilize case-insensitive indexes."
$regex answers also run the risk of user input injection.
If you need to create the regexp from a variable, this is a much better way to do it: https://stackoverflow.com/a/10728069/309514
You can then do something like:
var string = "SomeStringToFind";
var regex = new RegExp(["^", string, "$"].join(""), "i");
// Creates a regex of: /^SomeStringToFind$/i
db.stuff.find( { foo: regex } );
This has the benefit be being more programmatic or you can get a performance boost by compiling it ahead of time if you're reusing it a lot.
Keep in mind that the previous example:
db.stuff.find( { foo: /bar/i } );
will cause every entries containing bar to match the query ( bar1, barxyz, openbar ), it could be very dangerous for a username search on a auth function ...
You may need to make it match only the search term by using the appropriate regexp syntax as:
db.stuff.find( { foo: /^bar$/i } );
See http://www.regular-expressions.info/ for syntax help on regular expressions
db.company_profile.find({ "companyName" : { "$regex" : "Nilesh" , "$options" : "i"}});
db.zipcodes.find({city : "NEW YORK"}); // Case-sensitive
db.zipcodes.find({city : /NEW york/i}); // Note the 'i' flag for case-insensitivity
TL;DR
Correct way to do this in mongo
Do not Use RegExp
Go natural And use mongodb's inbuilt indexing , search
Step 1 :
db.articles.insert(
[
{ _id: 1, subject: "coffee", author: "xyz", views: 50 },
{ _id: 2, subject: "Coffee Shopping", author: "efg", views: 5 },
{ _id: 3, subject: "Baking a cake", author: "abc", views: 90 },
{ _id: 4, subject: "baking", author: "xyz", views: 100 },
{ _id: 5, subject: "Café Con Leche", author: "abc", views: 200 },
{ _id: 6, subject: "Сырники", author: "jkl", views: 80 },
{ _id: 7, subject: "coffee and cream", author: "efg", views: 10 },
{ _id: 8, subject: "Cafe con Leche", author: "xyz", views: 10 }
]
)
Step 2 :
Need to create index on whichever TEXT field you want to search , without indexing query will be extremely slow
db.articles.createIndex( { subject: "text" } )
step 3 :
db.articles.find( { $text: { $search: "coffee",$caseSensitive :true } } ) //FOR SENSITIVITY
db.articles.find( { $text: { $search: "coffee",$caseSensitive :false } } ) //FOR INSENSITIVITY
One very important thing to keep in mind when using a Regex based query - When you are doing this for a login system, escape every single character you are searching for, and don't forget the ^ and $ operators. Lodash has a nice function for this, should you be using it already:
db.stuff.find({$regex: new RegExp(_.escapeRegExp(bar), $options: 'i'})
Why? Imagine a user entering .* as his username. That would match all usernames, enabling a login by just guessing any user's password.
Suppose you want to search "column" in "Table" and you want case insensitive search. The best and efficient way is:
//create empty JSON Object
mycolumn = {};
//check if column has valid value
if(column) {
mycolumn.column = {$regex: new RegExp(column), $options: "i"};
}
Table.find(mycolumn);
It just adds your search value as RegEx and searches in with insensitive criteria set with "i" as option.
Mongo (current version 2.0.0) doesn't allow case-insensitive searches against indexed fields - see their documentation. For non-indexed fields, the regexes listed in the other answers should be fine.
For searching a variable and escaping it:
const escapeStringRegexp = require('escape-string-regexp')
const name = 'foo'
db.stuff.find({name: new RegExp('^' + escapeStringRegexp(name) + '$', 'i')})
Escaping the variable protects the query against attacks with '.*' or other regex.
escape-string-regexp
The best method is in your language of choice, when creating a model wrapper for your objects, have your save() method iterate through a set of fields that you will be searching on that are also indexed; those set of fields should have lowercase counterparts that are then used for searching.
Every time the object is saved again, the lowercase properties are then checked and updated with any changes to the main properties. This will make it so you can search efficiently, but hide the extra work needed to update the lc fields each time.
The lower case fields could be a key:value object store or just the field name with a prefixed lc_. I use the second one to simplify querying (deep object querying can be confusing at times).
Note: you want to index the lc_ fields, not the main fields they are based off of.
Using Mongoose this worked for me:
var find = function(username, next){
User.find({'username': {$regex: new RegExp('^' + username, 'i')}}, function(err, res){
if(err) throw err;
next(null, res);
});
}
If you're using MongoDB Compass:
Go to the collection, in the filter type -> {Fieldname: /string/i}
For Node.js using Mongoose:
Model.find({FieldName: {$regex: "stringToSearch", $options: "i"}})
The aggregation framework was introduced in mongodb 2.2 . You can use the string operator "$strcasecmp" to make a case-insensitive comparison between strings. It's more recommended and easier than using regex.
Here's the official document on the aggregation command operator: https://docs.mongodb.com/manual/reference/operator/aggregation/strcasecmp/#exp._S_strcasecmp .
You can use Case Insensitive Indexes:
The following example creates a collection with no default collation, then adds an index on the name field with a case insensitive collation. International Components for Unicode
/* strength: CollationStrength.Secondary
* Secondary level of comparison. Collation performs comparisons up to secondary * differences, such as diacritics. That is, collation performs comparisons of
* base characters (primary differences) and diacritics (secondary differences). * Differences between base characters takes precedence over secondary
* differences.
*/
db.users.createIndex( { name: 1 }, collation: { locale: 'tr', strength: 2 } } )
To use the index, queries must specify the same collation.
db.users.insert( [ { name: "Oğuz" },
{ name: "oğuz" },
{ name: "OĞUZ" } ] )
// does not use index, finds one result
db.users.find( { name: "oğuz" } )
// uses the index, finds three results
db.users.find( { name: "oğuz" } ).collation( { locale: 'tr', strength: 2 } )
// does not use the index, finds three results (different strength)
db.users.find( { name: "oğuz" } ).collation( { locale: 'tr', strength: 1 } )
or you can create a collection with default collation:
db.createCollection("users", { collation: { locale: 'tr', strength: 2 } } )
db.users.createIndex( { name : 1 } ) // inherits the default collation
I'm surprised nobody has warned about the risk of regex injection by using /^bar$/i if bar is a password or an account id search. (I.e. bar => .*#myhackeddomain.com e.g., so here comes my bet: use \Q \E regex special chars! provided in PERL
db.stuff.find( { foo: /^\Qbar\E$/i } );
You should escape bar variable \ chars with \\ to avoid \E exploit again when e.g. bar = '\E.*#myhackeddomain.com\Q'
Another option is to use a regex escape char strategy like the one described here Javascript equivalent of Perl's \Q ... \E or quotemeta()
Use RegExp,
In case if any other options do not work for you, RegExp is a good option. It makes the string case insensitive.
var username = new RegExp("^" + "John" + "$", "i");;
use username in queries, and then its done.
I hope it will work for you too. All the Best.
If there are some special characters in the query, regex simple will not work. You will need to escape those special characters.
The following helper function can help without installing any third-party library:
const escapeSpecialChars = (str) => {
return str.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, "\\$&");
}
And your query will be like this:
db.collection.find({ field: { $regex: escapeSpecialChars(query), $options: "i" }})
Hope it will help!
Using a filter works for me in C#.
string s = "searchTerm";
var filter = Builders<Model>.Filter.Where(p => p.Title.ToLower().Contains(s.ToLower()));
var listSorted = collection.Find(filter).ToList();
var list = collection.Find(filter).ToList();
It may even use the index because I believe the methods are called after the return happens but I haven't tested this out yet.
This also avoids a problem of
var filter = Builders<Model>.Filter.Eq(p => p.Title.ToLower(), s.ToLower());
that mongodb will think p.Title.ToLower() is a property and won't map properly.
I had faced a similar issue and this is what worked for me:
const flavorExists = await Flavors.findOne({
'flavor.name': { $regex: flavorName, $options: 'i' },
});
Yes it is possible
You can use the $expr like that:
$expr: {
$eq: [
{ $toLower: '$STRUNG_KEY' },
{ $toLower: 'VALUE' }
]
}
Please do not use the regex because it may make a lot of problems especially if you use a string coming from the end user.
I've created a simple Func for the case insensitive regex, which I use in my filter.
private Func<string, BsonRegularExpression> CaseInsensitiveCompare = (field) =>
BsonRegularExpression.Create(new Regex(field, RegexOptions.IgnoreCase));
Then you simply filter on a field as follows.
db.stuff.find({"foo": CaseInsensitiveCompare("bar")}).count();
These have been tested for string searches
{'_id': /.*CM.*/} ||find _id where _id contains ->CM
{'_id': /^CM/} ||find _id where _id starts ->CM
{'_id': /CM$/} ||find _id where _id ends ->CM
{'_id': /.*UcM075237.*/i} ||find _id where _id contains ->UcM075237, ignore upper/lower case
{'_id': /^UcM075237/i} ||find _id where _id starts ->UcM075237, ignore upper/lower case
{'_id': /UcM075237$/i} ||find _id where _id ends ->UcM075237, ignore upper/lower case
For any one using Golang and wishes to have case sensitive full text search with mongodb and the mgo godoc globalsign library.
collation := &mgo.Collation{
Locale: "en",
Strength: 2,
}
err := collection.Find(query).Collation(collation)
As you can see in mongo docs - since version 3.2 $text index is case-insensitive by default: https://docs.mongodb.com/manual/core/index-text/#text-index-case-insensitivity
Create a text index and use $text operator in your query.

MongoDB Text Search AND multiple search words

I have an index on an array "keys" that I am using to provide full text functionality to my applicaiton.
With the release of 2.4.3, I'd like to utilize the "text" index type. I insured a "text" index type on my array "keys" and it seems to work SUPER fast (faster than my old keywords full text method).
The problem is, my app assumes that fields are inclusive (AND). By default, the text search ORs my parameters.
Does anyone know of a way to run a text search inclusively?
For example:
db.supplies.runCommand("text", {search:"printer ink"})
should return results with both printer and ink, instead of all results with either printer or ink.
Give a try to:
db.supplies.runCommand("text", {search:"\"printer\" \"ink\""})
Also, here's a quote from docs:
If the search string includes phrases, the search performs an AND with
any other terms in the search string; e.g. search for ""twinkle
twinkle" little star" searches for "twinkle twinkle" and ("little" or
"star").
You can wrap each word in double-quotes:
let keywords = ctx.params.query.split(/\s+/).map(kw => `"${kw}"`).join(' ');
match.$text = { $search: keywords, $caseSensitive: false };
There is a downside if the user inputs a quoted string this will not work. You'd have to parse out quoted strings first.
As #alecxe pointed out earlier, to do AND search on text index column you need to double quote each search word.
Below is a quick one-liner for your requirement.
db.supplies.runCommand("text", {search: "printer ink".split(" ").map(str => "\""+str+"\"").join(' ')})
Here is a simple function I made to search using subwords in node. Hope it helps someone
Let's suppose a user search for pri nks so it should satisfy printer and inks but $text search doesn't allow for this so here is my simple function:
var makeTextFilter = (text) => {
var wordSplited = text.split(/\s+/);
/** Regex generation for words */
var regToMatch = new RegExp(wordSplited.join("|"), 'gi');
let filter = [];
searchFieldArray.map((item,i) => {
filter.push({});
filter[i][item] = {
$regex: regToMatch,
$options: 'i'
}
})
return filter;
}
and use it in your query like this
let query = {...query, $or: makeTextFilter(textInputFromUser)}
tableName.find(query, function (err, cargo_list)