Here is the string I am trying to extract from:
'cn=xyxyxyxyxyx ousy,ou=information services,ou=domain users,dc=corp,dc=xyxyxx,dc=com'
I am trying to extract the string between the first 'ou=' and the second comma. In this case that is
'information services'
Here is what I have so far:
SUBSTR(F_DN, locate('ou=', F_DN)+3, locate(',', F_DN, locate(',', F_DN)+1)+1 ) as role
And this is the result:
'information services,ou=domain users,dc=co'
It seems to locate to the first character just fine but I cannot get the length correct.
Try this:
select regexp_substr(str, 'ou=([^,]+)', 1, 1, '', 1)
from (values 'cn=xyxyxyxyxyx ousy,ou=information services,ou=domain users,dc=corp,dc=xyxyxx,dc=com') t (str);
Related
I have a string data like 'wordword (2018)', want to extract those data with pattern (yyyy). have tried with '%/([0-9][0-9][0-9][0-9]/)%' but doesn't work
Building on HABO's comment, you can use something like:
DECLARE #Pattern VARCHAR(50) = '%([0-9][0-9][0-9][0-9])%'
SELECT A.value, yyyy = SUBSTRING(A.value, NULLIF(PATINDEX(#pattern, A.Value), 0) + 1, 4)
FROM (
VALUES
('wordword (2018)'),
('Nothing here'),
('this (2010) and that (2020)')
) A(value)
SQL Server has a very limited pattern matching support, so I converted your regex to the closest thing that SQL Server supports. The NULLIF() in the above converts a not-found index of zero to a null, which propagates to the result.
Did you try CHARINDEX?
SUBSTRING(#str,
CHARINDEX(‘[0-9][0-9][0-9][0-9]’,#str),4)
I have a column with Names, and I am trying to split the column into First and Last Name using Text functions such as LEFT/SUBSTRING/CHARINDEX.
Data in the column:
Name
Yang, Jon
Huang, Eugene
Torres, Ruben
Zhu, Christy
Johnson, Elizabeth
Everything works fine as long as I use this code:
SELECT
[Name]
--,LEFT([Name], CHARINDEX(' ', [Name])) AS FirstName
,SUBSTRING([Name], 1, CHARINDEX(' ', [Name] )) AS FirstName
FROM
DataModeling.Customer
But the problem arises when I try to subtract 1 from CHARINDEX to exclude the Comma from the result and it throws this error:
I have done this operation many times in Excel so trying to replicate it with TSQL. Any suggestion on what I am doing wrong is helpful.
You get that error when CHARINDEX(' ', [Name] ) return 0. So minus 1 will make it negative and it is invalid value for substring()
You can use CASE expression to check the return value from CHARINDEX() and return the correct value to substring()
Or, you can "cheat" by using
CHARINDEX( ' ', [Name] + ' ' )
So CHARINDEX() will always return a value that is more than 0
I am currently working on DB data which contains whitespaces and hyphens. I searched over the net and found this Remove/replace special characters in column values? . I tried to follow the answer but I am still getting hyphens. I tried playing around with it, I can only remove the whitespace
conn_p = p.connect("dbname='p_test' user='postgres' password='postgres' host='localhost'")
conn_t = p.connect("dbname='t_mig1' user='postgres' password='postgres' host='localhost'")
cur_p = conn_p.cursor()
cur_t = conn_t.cursor()
cur_t.execute("SELECT CAST(REGEXP_REPLACE(studentnumber, ' ', '') as integer), firstname, middlename, lastname FROM sprofile")
rows = cur_t.fetchall()
for row in rows:
print "Inserting ", row[0], row[1], row[2], row[3]
cur_p.execute(""" INSERT INTO "a_recipient" (id, first_name, middle_name, last_name) VALUES ('%s', '%s', '%s', '%s') """ % (row[0], row[1], row[2], row[3]))
cur_p.commit()
cur_pl.close()
cur_t.close()
What I would like to achieve is if I got a studentnumber of 001-2012-1456, it will be displayed as 000120121456.
To wipe out all characters in a set efficiently use translate. It takes a set of characters to translate into another set of characters. If the other set is empty it deletes them.
test=> select translate('001-2012-145 6', '- ', '');
translate
-------------
00120121456
While translate is simpler and faster for this particular job, it's important to know how to use regexes for others. To do it with regexp_replace there's two changes you need to make.
First, you have to match the set of - and as [- ].
Then, you have to specify to replace all occurrences, otherwise it will stop after the first one. That's done with the g flag.
test=> select regexp_replace('001-2012-145 6', '[- ]', '', 'g');
regexp_replace
----------------
00120121456
Here's a tutorial on POSIX regular expressions and character sets.
Its very simple to use inbuilt translate function.
Example:
select translate('001-2012-145 6', '- ', '');
Output of above command :
00120121456
I am making a report and I need to split a coma separated string into three columns of a table.
string = 'some text, some text, some text'
But the sting doesn't always have two coma's i.e.
string = 'some text, some text'
so when i try to get the value for the third column
=Split(Fields!GLDescription.Value, ", ").GetValue(2)
This code can result in a "#Error" message in the column. I tried to solve this by checking the length like so
=IIF(Split(Fields!GLDescription.Value, ", ").Length >= 3, Split(Fields!GLDescription.Value, ", ").GetValue(2), "")
But it still resulted in the same error. Is there anyway to check if an array key exists?
The issue, as you've seen, is that SSRS IIf expressions aren't good at short circuiting. I can think of a workaround that will work for 2 and 3 column fields.
Try an expression like:
=IIf(
Split(Fields!GLDescription.Value, ", ").Length = 3
, Mid(
Fields!GLDescription.Value
, InStrRev(Fields!GLDescription.Value, ", ") + 2
, Len(Fields!GLDescription.Value) - InStrRev(Fields!GLDescription.Value, ", ") + 2
)
, "No val 3"
)
With dataset:
Gives result:
It's not bulletproof for all possible situations, but might be enough for your data.
I have a field named rspec in a table trace.
So for now the field is like "Vol3/data/20070204_191426_FXBS.v3a".
All I need is a query to change it to the format "Vol3/data/20070204_191426_FXBS.V3A".
Assuming the current version:
select left(rspec, - 3)||upper(right(rspec, 3))
from trace
For older versions:
select substr(rspec, 1, length(rspec) - 3)||upper(substring(rspec from '...$'))
from trace
Or, to cover all possibilities like
file extensions of variable length: abc123.jpeg
no file extension at all: abc123
dot as last character: abc123.
multiple dots: abc.123.jpg
SELECT CASE WHEN rspec ~~ '%.%'
THEN substring(rspec, E'^.*\\.')
|| upper(substring(rspec , E'([^.]*)$'))
ELSE rspec
END AS rspec
FROM (VALUES
('abc123.jpeg')
, ('abc123')
, ('abc123.')
, ('abc.123.jpg')
) ASx(rspec); -- testcases
Explain:
If the string has no dot, use the string.
Else, take everything up to and including the last dot in the string.
Append everything after the last dot in upper case.