One regex to capture words separated by one space-character in combination with the opposite capture occurrences more than one space-character - regex-group

Question

I would like to have just one regex to capture words separated by one space-character in combination with the opposite capture occurrences more than one space-character
I would like to have the following example covered:
This line with sometimes more than 1 space needs to be captured in 3 matches with 2 groups.
I expect the following groups:
([This line with][ ])([sometimes more than][ ])([1][ ])space needs to be captured in 3 matches with 2 groups.
To capture one of the two is no problem.
i.e.
to capture more than one space-char:
([\s]{2,})
and to capture words separated by only one space-char(see https://stackoverflow.com/a/60288115/3710053):
\S+(?:\s\S+)*

Answer 1

You might use an alternation to match either a word followed by a repeating pattern of a single space and a word OR match 2 or more spaces
\S+(?: \S+)*| {2,}
Explanation
\S+ Match 1+ non whitespace chars
(?: \S+)* Repeat 0+ times matching a space and 1+ non whitespace chars
| Or
{2,} Repeat 2 or more times matching a space
Regex demo
If you want to match whitespace chars instead, you could replace the space with \s but note that it could also possibly match newlines.
Edit
For the updated question, you could use 2 capturing groups:
(\S+(?: \S+)*)( {2,})
Explanation
( Capture group 1
\S+ Match 1+ non whitespace chars
(?: \S+)* Repeat 0+ times matching a space and 1+ non whitespace chars
) Close group 1
( Capture group 2
{2,} Match 2 or more spaces
) Close group 2
Regex demo