MongoDB Query Aggregation - mongodb

Question

I need a query that takes multiple 'companyID's' and return the count for each company.
Currently this query only does this for one companyID and it does not return the id but just 'null' like show below.
I understand that I can use the 'in' operator for multiple companyID's but not sure how I would go about having the query return the count for multiple companyID's
db.getCollection('reg').aggregate([ {
'$match' : {
'$and' : [
{
'companyID' : 11
},
{
'created' : {
'$gte' : 1556726597
}
},
{
'created' : {
$lt : 1580572997
}
}
]
}
},
{
'$project' : {
'testID' : 1,
}
},
{
'$group' : {
'_id' : '$testID',
'registrationsCount' : {'$sum' : 1},
},
},
{
$group: {
_id: null,
count: { $sum: 1 }
}
}
])
The result below
{
"_id" : null,
"count" : 10.0
}
Schema below
{
"_id" : NumberLong(1),
"appUserID" : NumberLong(4294967295),
"companyID" : NumberLong(5),
"created" : NumberLong(1372625588),
"testID" : NumberLong(11),
"isCheckIn" : true,
"lastModified" : NumberLong(1372625588),
"source" : "upload",
"timeArrived" : NumberLong(1343062512),
}

Answer 1

I think you need to do 2 things
first
'$match' : {
'$or': [
'$and' : [
{
'companyID' : 11
},
{
'created' : {
'$gte' : 1556726597
}
},
{
'created' : {
$lt : 1580572997
}
}
]
// ... add the other ids you need
]
}
And second
{
'$group' : {
'_id' : '$testID',
'registrationsCount' : {'$sum' : 1},
},
},
{
$group: {
_id: '$testID', // or '$_id' not sure
count: { $sum: 1 }
}
}
Hope this helps!