So im trying to return a report that will list each user and each group they are in using -Filter "name-like 'BLAH'"
the user may be apart multiple "BLAH" groups but no more than 3. How can i get an output like?
Member | Group1 | Group2 | Group3
I tried the below but not quite what i need
$adgroups = Get-ADGroup -Filter "name -like '*BLAH*'" | sort name
$data = foreach ($adgroup in $adgroups) {
$members = $adgroup | get-adgroupmember |select name| sort name
foreach ($member in $members) {
[PSCustomObject]#{
Members = $member
Group = $adgroup.name
}
}
}
This is what i get when using #Adam Luniewski solution
Try this:
$adgroups = Get-ADGroup -Filter "name -like '*BLAH*'" | Sort-Object Name
$data = ForEach ($adgroup in $adgroups){
$adgroup | get-adgroupmember | Select-Object #{n='Members';e={$_}},#{n='Group';e={(Get-ADUser $_.SamAccountName -Properties MemberOf).MemberOf}}
}
Here Get-ADUser is used to retrieve user group memberships (first said #Olaf) then I used calculated properties to format the output.
This should work. Just watch out if you have StrictMode set in your script, it might throw an error if $usrgrp count is less than 3, then you'd have to modify this part.
# get a list of all users and groups in two columns
$dat = #(Get-ADGroup -Filter "name -like '*BLAH*'" -PipelineVariable group | Get-ADGroupMember | select #{n='UserName';e={$_.name}},#{n='GroupName';e={$group.name}})
# for each user in a list add group fields
$dat | select UserName -Unique | ForEach-Object {
$usrgrp = #($dat | where username -eq $_.UserName | sort GroupName);
[pscustomobject]#{
UserName=$_.Username;
Group1=$usrgrp[0].GroupName;
Group2=$usrgrp[1].GroupName;
Group3=$usrgrp[2].GroupName;
};
}
Related
I am beginner in powershell and trying to create a script.
I have list of users, for them I need to know in which DLs they are added.
The problem I am facing is, it shows the list of DLs only, is there any way I can get DLs under the usernames? or a better way to accomplish this.
Note: we name all our DLs in capital letter thats why I have used "\b[A-Z0-9_]+\b" in where-object.
$users = import-csv C:\Test\users.csv | ForEach-Object {$_.users = $_.users.Trim(); $_} | Select-Object -ExpandProperty users
foreach ( $user in $users)
{get-ADPrincipalGroupMembership $user | select name |
Where-Object { $_.name -cmatch "\b[A-Z0-9_]+\b"} | Export-CSV "C:\test\output_file.csv" -NoTypeInformation -Append
}
Now I get the following outcome:
Group1
Group2
Group3
Group2
Group3
Group4
My ideal out put would be something along the lines of:
User MemberOf
---- --------
Bob Group1, Group2, Group3....
Jim Group2, Group3, Group4....
Thanks alot.
Assuming you're looking for Distribution Lists, you can tell if a group is a Security Group or a Distribution List by looking at the GroupCategory property of an ADGroup object.
Instead of looking at the user's memberOf attribute and finding out which ones are Distribution you can search for ADGroups that are GroupCategory -eq 'Distribution' where each user is a member:
$users = (Import-CSV C:\Test\users.csv | ForEach-Object {
$_.users.Trim()
}).users
$result = foreach ($user in $users)
{
$userDN = (Get-ADUser $user).DistinguishedName
$groups = Get-ADGroup -Filter "member -eq '$userDN' -and groupCategory -eq 'Distribution'"
[pscustomobject]#{
User = $user
MemberOf = $groups.Name -join ', '
}
}
$result | Export-CSV "C:\test\output_file.csv" -NoTypeInformation
If you want to use the code you already have, with this minor update you should be getting the result you are looking for:
$users = (Import-CSV C:\Test\users.csv | ForEach-Object {
$_.users.Trim()
}).users
$result = foreach ($user in $users)
{
$membership = Get-ADPrincipalGroupMembership $user |
Where-Object {
$_.name -cmatch "\b[A-Z0-9_]+\b"
}
[pscustomobject]#{
User = $user
MemberOf = $membership.Name -join ', '
}
}
$result | Export-CSV "C:\test\output_file.csv" -NoTypeInformation
I need to get specific users from specific Groups in Active Directory.
So far I have this:
$Groupnames = get-adgroup -Filter "name -like '$Groupfilter'" -Properties * -SearchBase $Grouppath |
Select-Object Name, #{
Name='Username';
Expression={
Get-ADGroupMember -identity $($_.Name) -Recursive |
Get-ADUser -Property SamAccountName |
Select -ExpandProperty SamAccountName
}
}
This works to get the Groups with their names. Now I want to get all users from these groups. what works but the formating is completly off. I want this:
Name Username
---- --------
Group1 user1adm
Group2 {user1adm, user1, user2, user2adm...}
Group3 {user1adm, user3, user2adm, user6...}
But I get this:
{user1adm, user1, user2, user2adm...}
With that formatting I can't see all users.
My goal at the end is also to exclude users who end with adm, but I don't know how to do that.
Can you help me?
Get-ADGroupMember can return objects of type 'user', 'group' or 'computer', so piping the returned objects straight through to Get-ADUser could get you into trouble if one of the objects is not a user.
Having said that, the objects returned from Get-ADGroupMember already contain the SamAccountName property you are after, so you can eliminate Get-ADUser from the code.
$Groupnames = Get-ADGroup -Filter "name -like '$Groupfilter'" -SearchBase $Grouppath |
Select-Object Name,
#{Name = 'Username'; Expression = {
($_ | Get-ADGroupMember -Recursive |
Select-Object -ExpandProperty SamAccountName |
Where-Object { $_ -notmatch 'adm$' }
) -join ', '
}
}
# output the result on screen
$Groupnames | Format-Table -AutoSize
# output to CSV file
$Groupnames | Export-Csv -Path 'Path\To\The\GroupMembers.csv' -NoTypeInformation
I want 1 list with all users there are member of 2 (both) identity.
I have used this, but it returns first all users in the first identity and then the next identity.
$groups = "SMSxxx", "Personalxxxx"
$results = foreach ($group in $groups) {
Get-ADGroupMember $group | select samaccountname, name, #{n='GroupName';e={$group}}, #{n='Description';e={(Get-ADGroup $group -Properties description).description}}
}
$results
$results | Export-csv C:\Temp\GroupMemberShip.txt -NoTypeInformation
Best regards,
Peter
You can continue with your current logic and use Group-Object to find users that exist in all groups.
$groups = "SMSxxx", "Personalxxxx"
$results = foreach ($group in $groups) {
$description = (Get-ADGroup $group -Properties description).description
Get-ADGroupMember $group | select SamAccountName,Name,#{n='GroupName';e={$group}}, #{n='Description';e={$description}}
}
$results | Group-Object SamAccountName |
Where Count -eq $groups.Count | Select -Expand Group |
Export-csv C:\Temp\GroupMemberShip.csv -NoTypeInformation
How could I get a List of Members on multible AD Groups with more than 5000 Users
Example:
Group1 = includes 6000 Members and Group2
Group2 = includes 7000 Members
the result of the get-adgroupmember of Group1 should 13000
how can I do that? Here I have the Problem, that it will not look in sub groups recursive will not work with get-adgroup
$group = "group1"
$ADInfo = Get-ADGroup -Identity $Group -Properties Members
$outputfile = $group
$ADInfo.Members | get-aduser | Select name, enabled, UserPrincipalName, SamAccountName
#$ADInfo.Members | get-aduser | Select name, enabled, UserPrincipalName, SamAccountName | Export-Csv c:\temp\$outputfile-member.csv -Delimiter "," -NoTypeInformation
# to show output
$members = #()
$members = $ADInfo.members
$members.count
With groups that large, it will be slow, but this should do what you want:
$groups = 'group1', 'group2' # array of group names
foreach ($group in $groups) {
Write-Host "Working on group '$group'"
$result = Get-ADGroupMember -Identity $group -Recursive | Where-Object { $_.objectClass -eq 'user' } | ForEach-Object {
Get-ADUser -Identity $_.distinguishedName | Select-Object Name, Enabled, UserPrincipalName, SamAccountName
}
# show result on screen
$result | Format-Table -AutoSize
# write to export file
$result | Export-Csv -Path "c:\temp\$group-members.csv" -NoTypeInformation
}
Hope that helps
The easiest solution would be to adjust the MaxGroupOrMemberEntries parameter in ADWS on the DC you are targeting. You can see information on ADWS defaults here.
You could do something like the following, which is potentially convoluted:
function Get-ADGroupMembers
{
param ($groupname)
Get-ADGroupMember $groupname | where ObjectClass -eq 'Group' | ForEach-Object {
$_.Name
Get-ADGroupMembers $_.Name
}
}
$maingroup = 'group1'
$subgroups = Get-ADGroupMembers $maingroup
$allGroups = #($maingroup)+#($subgroups)
$regexEscapes = $allGroups |% { [regex]::Escape($_) }
$filter = "CN=({0})" -f ($regexEscapes -join "|")
$output = foreach ($group in $allGroups) {
Get-AdGroup $group -Properties Members | Select #{n='Members';e={$_.Members -notmatch $filter}}
}
$output.Members
Explanation:
The function will list the Name property value for each recursively discovered member group.
Since the -notmatch regex operator is used in filtering, a regex match string needs to be constructed. There could be multiple groups so the | (regex OR) character needs to be used.
The [regex]::Escape method escapes all backslashes and other special regex characters that may appear in the name strings.
$output is an array of PSCustomObjects that contain the Members property. The Members property contains the DN of all members that are users.
Non-PowerShell commands may be better suited for this particular case if the ADWS default limits are not modified.
I need to return all members of multiple security groups using PowerShell. Handily, all of the groups start with the same letters.
I can return a list of all the relevant security groups using the following code:
Get-ADGroup -filter 'Name -like"ABC*"' | Select-Object Name
And I know I can return the membership list of a specific security group using the following code:
Get-ADGroupMember "Security Group Name" -recursive | Select-Object Name
However, I can't seem to put them together, although I think what I'm after should look something like this (please feel free to correct me, that's why I'm here!):
$Groups = Get-ADGroup -filter 'Name -like"ABC*"' | Select-Object Name
ForEach ($Group in $Groups) {Get-ADGroupMember -$Group -recursive | Select-Object Name
Any ideas on how to properly structure that would be appreciated!
Thanks,
Chris
This is cleaner and will put in a csv.
Import-Module ActiveDirectory
$Groups = (Get-AdGroup -filter * | Where {$_.name -like "**"} | select name -expandproperty name)
$Table = #()
$Record = [ordered]#{
"Group Name" = ""
"Name" = ""
"Username" = ""
}
Foreach ($Group in $Groups)
{
$Arrayofmembers = Get-ADGroupMember -identity $Group | select name,samaccountname
foreach ($Member in $Arrayofmembers)
{
$Record."Group Name" = $Group
$Record."Name" = $Member.name
$Record."UserName" = $Member.samaccountname
$objRecord = New-Object PSObject -property $Record
$Table += $objrecord
}
}
$Table | export-csv "C:\temp\SecurityGroups.csv" -NoTypeInformation
If you don't care what groups the users were in, and just want a big ol' list of users - this does the job:
$Groups = Get-ADGroup -Filter {Name -like "AB*"}
$rtn = #(); ForEach ($Group in $Groups) {
$rtn += (Get-ADGroupMember -Identity "$($Group.Name)" -Recursive)
}
Then the results:
$rtn | ft -autosize
Get-ADGroupMember "Group1" -recursive | Select-Object Name | Export-Csv c:\path\Groups.csv
I got this to work for me... I would assume that you could put "Group1, Group2, etc." or try a wildcard.
I did pre-load AD into PowerShell before hand:
Get-Module -ListAvailable | Import-Module
This will give you a list of a single group, and the members of each group.
param
(
[Parameter(Mandatory=$true,position=0)]
[String]$GroupName
)
import-module activedirectory
# optional, add a wild card..
# $groups = $groups + "*"
$Groups = Get-ADGroup -filter {Name -like $GroupName} | Select-Object Name
ForEach ($Group in $Groups)
{write-host " "
write-host "$($group.name)"
write-host "----------------------------"
Get-ADGroupMember -identity $($groupname) -recursive | Select-Object samaccountname
}
write-host "Export Complete"
If you want the friendly name, or other details, add them to the end of the select-object query.