How to execute sql file with Slick 3.0.0 - scala

Question

I have a structure like this
src
└── main
├── resources
│ └── inserts.sql
└── my.package
└── Main.scala
In Main.scala I want to take the file inserts.sql and use Slick 3.0.0 to execute it on my db.

Answer 1

A SQL string can be executed directly by using the SQLActionBuilder class.
Also, since the BufferedSource object we get from Source.fromResource is Closable, we should wrap it with a Using block.
import slick.jdbc.SetParameter.SetUnit
import slick.jdbc.SQLActionBuilder
import scala.io.Source
import scala.util.Using
// ...
Using(Source.fromResource("inserts.sql")) { insertsSqlSource =>
val sqlActionBuilder = SQLActionBuilder(insertsSqlSource.mkString, SetUnit)
database.run(sqlActionBuilder.asUpdate)
}

Answer 2

You can read file content:
val query = scala.io.Source.fromResource("inserts.sql").mkString
and then create query using sql or sqlu interpolators:
//https://scala-slick.org/doc/3.0.0/sql.html
sql"$query".as[ExpectedType]
and run it as always :)
PS: Not tested. Don't have prepared env now.

Answer 3

Looks like there is no way to execute a sql file with Slick other then loading it into memory as a String and executing it with sql, sqlu or tsql.
Beware that in this case the $ interpolation is meant to insert bind variables into the query. To splice literal values into the query you must use #$ instead. Since in this case the variable is the whole query, we have to do
val inserts_sql = Source.fromResource("inserts.sql").mkString
db.run(sqlu"#$query")