I know that in the latest version of dart we can use if else statements inside the build method. Does anyone know if we can use also if else statement when we setting class parameters? I know I can do inline statement there but inline is a bit hard to read when there are multiple conditions
const int i = 0;
class Person {
// NewClass n = NewClass(a: i == 0 ? 'a' : 'b'); //<- inline statement working
NewClass n = NewClass(a: if(i == 0) 'a' else 'b'); //<- if statement doesn't
}
class NewClass {
final String a;
const NewClass({this.a});
}
Edit:
Basically in my case I've got an TextField widget where I set its's type parameter from enum (Type.text, Type.numeric...) According to this parameter I want to set The textField parameters (textCapitalization, maxLength and so on)
As per your comment, you are already creating an enum for specifying the type of the fields.
enum Type {text, numeric}
Now for specifying the properties of that particular type, you can add an extension on this enum, as shown below:
extension TextFieldProperties on Type {
int get maxLength {
if (this == Type.text) {
return 10;
}
return 12;
}
}
So in your field class you already have a type defined, you can use that type variable to get the properties of that particular type of field.
Type type = Type.text;
print(type.maxLength); // Will print 10
type = Type.numeric;
print(type.maxLength); // Will print 12
Note: It will work only in Dart 2.7 and above
You want the conditional expression (?:), not the conditional statement or literal entry (if), as you have already discovered.
The reason if doesn't work is that if only works as a statement or as a collection literal entry. It doesn't work in arbitrary expressions.
The reason for the distinction is that the if syntax allows you to omit the else branch. That only makes sense in places where "nothing" is a valid alternative. For a statement, "doing nothing" is fine. For a collection, "adding nothing" is also fine.
In an expression context, you must evaluate to a value or throw. There is no reasonable default that we can use instead of "nothing", so an if is not allowed instead of an expression.
Doesn't work because this syntax doesn't exist in Dart. The only way to do what you would like to do is to use the ternary operator.
If you try it in the DartPad you will get an error.
I suggest you to use a function to return the right value.
Related
I have a problem understanding, and living with, the excessive use of bang operators in dart/flutter.
Consider this example:
if(model != null && model!.someValue != null) {
print(model!.someValue!);
}
The first condition check is verifying that the model is not null. In the second condition I have to put in a bang operator after model, else the compiler gives me an The property 'someValue' can't be unconditionally accessed because the receiver can be 'null' error. But why is this necessary? I´ve just checked the variable! And same goes for the print(model!.someValue!); line.
Another example where I have these classes:
class GeoPosition {
double lat = 0;
}
class Wrapper {
GeoPosition? position;
}
...
Wrapper wrapper = Wrapper();
wrapper.position = GeoPosition();
wrapper.position!.lat = 1;
Now why do I need to put this bang operator (or ? operator) after position? I´ve just created a new instance of GeoPosition in the Wrapper instance - position cannot be null.
My best guess is that the compiler cannot see or understand the current context of the class. But in Typescript the linter is smart enough to know when these operators are not necessary.
I know that I can create local variables from the properties that I am trying to access, but this would be just as ugly ;)
So why are ! and ? necessary in these (and many other) situations? And is there anything I can do about it?
This is what happens with nullable properties (hence the message you get). It is explained here: Understanding null safety: Working with nullable fields.
You should be able to work around this issue by declaring the field as late, as in
class Wrapper {
late GeoPosition position;
}
Wrapper wrapper = Wrapper();
wrapper.position = GeoPosition();
wrapper.position.lat = 1;
This will remove the need to add a bang to every access to position The compiler will add a non-null check at appropriate places. Of course, the program will fail if you don't assign a non-null value before accessing the field.
If explained in Late variables
Nullable properties of a class can still be null between two access.
For your first example you can extract the variable then check it:
var someValue = model?.someValue;
if(someValue != null) {
print(someValue); // not null
}
For your second example an elegant way will be the .. operator :
Wrapper wrapper = Wrapper();
wrapper. Position = GeoPosition()..lat = 1;
If you want the GeoPosition to be not null you have to make it not nullable:
class Wrapper {
GeoPosition position;
Wrapper(this.position);
}
You can set the position field final to be immutable.
Be careful with the late keyword, if you forget to init the field you've got a crash like the ! operator.
I want to feed Two to the function. When function receives Two as the data, it should print success to the console. But seems like it's not the correct way.
Error: Conditions must have a static type of 'bool'. Try changing the condition.
List
enum ButtonList {One, Two, Three}
Calling function
testFunc(ButtonList.Two)),
Function
testFunc( ButtonList type) {
if (type = ButtonList.Two ){print('sucess ')};
}
It should be:
testFunc(ButtonList type) {
if (type == ButtonList.Two) {
print('sucess ')
};
}
There's a big difference between = (assigning a value to a variable) and == (equality comparison). if expects a condition (==), not the assigning operation (=).
Formatting is important to read and understand the code. Please read Dart best code style practices: https://dart.dev/guides/language/effective-dart/style
You are trying to assign with =, use == instead
Is there a construct that communicates to the type checker a function's post-condition?
For example, in typescript it is possible to say
function assertIsNumber(value: any): asserts value is number {
if (typeof value !== 'number') {
throw new TypeError();
}
}
I would like to be able to do something like the following in dart:
class SomeClass {
int? value;
_checkPreconditions() {
if(value == null) {
throw MyPreconditionError()
}
// ...
}
somefunc() {
_checkPreconditions();
// here we know `value` is a non-null int.
final sum = value + 5;
}
}
I understand I could coerce the value to non-null sum = value! + 5, but I would prefer to allow the function to inform the type checker if possible.
It looks like the type system of Dart is not so powerful. The only thing that looks (from first glance) possible is to create a custom code analyzer package (or search for one that already exists).
Dart annotations don't actually do anything. They provide hints to tools such as the Dart analyzer (usually so that it can generate additional warnings), but they cannot change program behavior. Even if you could convince the analyzer to treat some variables as different types, you still wouldn't be able to compile and run your code.
Annotations can be used by code generation tools, so one possibility might be to generate a statement such as final value = this.value!; automatically. However, that would be a lot of trouble to go through (and would mean that code then would need to use this.value = 42; for assignments and would prevent your code from being analyzed directly).
Im learning about protobuf and am playing with alexeyxo/protobuf-swift.
Is there a way to cast protobuf Messages into the type they extend?
proto file:
message Command_Login {
extend SessionCommand {
optional Command_Login ext = 1001;
}
optional string user_name = 1;
optional string password = 2;
}
Here is the swiftcode:
let commandContainerBuilder = CommandContainer.Builder()
commandContainerBuilder.sessionCommand.append(commandLogin)
// sessionCommand is an array of SessionCommand (of which Command_Login extends)
Error:
Cannot convert value of type CommandLogin? to expected argument type SessionCommand
Sorry, you've misinterpreted extensions. I say "sorry" because this is probably my fault -- I designed the "extensions" feature, and unfortunately by using the word "extend" I confused a lot of people.
You see, extensions have nothing to do with inheritance. In your example, you are not declaring that Command_Login is any kind of subclass of SessionCommand. This is easier to understand if we shift the declarations around a bit:
message Command_Login {
optional string user_name = 1;
optional string password = 2;
}
extend SessionCommand {
optional Command_Login ext = 1001;
}
The above is completely valid and exactly equivalent to your code except for one difference: In your version, the extension's name is Command_Login.ext (because you declared it nested inside Command_Login), but in my version the name is just ext (in the global scope). Other than namespacing, they function the same.
What the extend clause actually does is declare a new field on SessionContext, where the type of that field is Command_Login. If you happen to place an extend clause inside of a message block, this only matters for namespacing purposes, much like declaring static members of a class in C++ or Java.
I'm trying to write a class for a scala project and I get this error in multiple places with keywords such as class, def, while.
It happens in places like this:
var continue = true
while (continue) {
[..]
}
And I'm sure the error is not there since when I isolate that code in another class it doesn't give me any error.
Could you please give me a rule of thumb for such errors? Where should I find them? are there some common syntactic errors elsewhere when this happens?
It sounds like you're using reserved keywords as variable names. "Continue", for instance, is a Java keyword.
You probably don't have parentheses or braces matched somewhere, and the compiler can't tell until it hits a structure that looks like the one you showed.
The other possibility is that Scala sometimes has trouble distinguishing between the end of a statement with a new one on the next line, and a multi-line statement. In that case, just drop the ; at the end of the first line and see if the compiler's happy. (This doesn't seem like it fits your case, as Scala should be able to tell that nothing should come after true, and that you're done assigning a variable.)
Can you let us know what this code is inside? Scala expects "expressions" i.e. things that resolve to a particular value/type. In the case of "var continue = true", this does not evaluate to a value, so it cannot be at the end of an expression (i.e. inside an if-expression or match-expression or function block).
i.e.
def foo() = {
var continue = true
while (continue) {
[..]
}
}
This is a problem, as the function block is an expression and needs to have an (ignored?) return value, i.e.
def foo() = {
var continue = true
while (continue) {
[..]
}
()
}
() => a value representing the "Unit" type.
I get this error when I forget to put an = sign after a function definition:
def function(val: String):Boolean {
// Some stuff
}