My question will seem quite simple, but I'm having a hard time understanding how certain queries work with ObjectBox and Flutter.
I have a List object. I would like to retrieve them all, but display only the first 5, sorted by ascending name.
I find many examples with filter queries in the documentation, but the getAll() does not allow to easily integrate the limit and I find very few examples. I think I'm doing it wrong. What is the best way to do this query ?
final boxListCoins = objectBoxDatabase.store.box<CoinsList>();
// final query = boxListCoins.getAll(); ?
final query = (boxListCoins.query()..order(CoinsList_.coinId, flags: Order.descending)).build();
query.limit = 5;
final coinsList = query.find();
I see that you want to get all your results but you want to display the first 5. So what I would do in your case is:
(1) get all your results(based on your query)
(2) then set another property equal to the top 5:)
** now you have a list of all your entries and you have your top 5 that you can display.
heres how I would code it up!
final boxListCoins = objectBoxDatabase.store.box<CoinsList>();
// final query = boxListCoins.getAll(); ?
final query = (boxListCoins.query()..order(CoinsList_.coinId, flags: Order.descending)).build();
// this is your list of all of the coins!
final coinsList = query.find();
// This is you list of the Top 5
var topFive = [];
if (coinsList.length >= 5) {
// take your top5 here :) also feel free to turn this iterable into what ever you want I just choose to keep it a list :)
topFive = coinsList.take(5).toList();
} else {
// if you length is not greater than 5 then you have your top automatically.
topFive = coinsList;
}
Hope this helps:)
Happy Coding, also I'm a developer #Pieces and if you need a place to store helpful code snippets, like this one, check it out here https://code.pieces.app/
I have this JSON
{
"components": [
"component1",
"component2",
"component3"
],
"validFrom": "someDate"
}
I would like to calculate the Range for VSCode so that I can report Diagnostics in my extension.
How can I calculate the Range, i.e. for "component1"? Some utility function should return something like (startLine: 3, startCharacter: 5, endLine: 3, endCharacter: 5 + component1.length).
With the jsonc-parser, which is also used by VS Code itself to parse JSON content btw., you can parse the document and get the range of an element.
This sample demonstrates how to get the range of "component1":
import { findNodeAtLocation, parseTree } from "jsonc-parser";
...
//Parse JSON of a TextDocument
const rootNode = parseTree(textDocument.getText());
// Find first element of the "components" array
const firstComponent = findNodeAtLocation(rootNode, ["components", 0]);
const start = textDocument.positionAt(firstComponent.offset);
const end = textDocument.positionAt(firstComponent.offset + firstComponent.length)
const range = new Range(start, end);
(Please note: I skipped any check for undefined)
Positioning information is usually provided by a parser. It determines the individual tokens in the input and their location. This can then be used to generate Monaco ranges for various purposes (code completion, error diagnostics, edit actions etc.).
I am new to protractor and want to assert whether a newly added row contains the text which i have added.
Also i want to assert whether the particular text belongs to the header section.
I have tried to some extent but my code is failing.
Below is my code
var row=element.all(by.repeater('dataRow in displayedCollection'));
var col=row.all(by.tagName('td'));
col.each(function(item)
{
item.getText().then(function(text)
{
})
})
})
Below is the HTML code
Below is UI
Sergey is correct, this would be much easier using async/await but using your example here is how I would do it.
Assuming that the newly added row is always the last row in the table you can probably do it something like this:
const rows = element.all(by.repeater('dataRow in displayedCollection'));
const relevantRow = rows.last();
relevantRow.getText().then(test => {
expect(text).toContain(mySampletext);
});
If the new row is not always the last one, then the way to find it would be different. For example, if every time you added a row the table was sorted alphabetically, then you would need to filter the list of rows to find the one you are looking for, and then check that the text matches what you expect it to be.
You don't really need to get each td element unless you want to verify that the text in each column is correct. In that case you would probably do it similar to this:
const expectedText = ['someText', 'in order', 'by', 'columns'];
const rows = element.all(by.repeater('dataRow in displayedCollection'));
const relevantRow = rows.last();
const columns = relevantRow.$$('td');
let coumnTextMatches = true;
columns.each((col, index) => {
col.getText().then(text => {
columntextMatches = expectedText[index] === text;
});
});
expect(columntextMatches).toEqual(true);
This may or may not be completely accurate. I just did it off the top of my head without testing it out but it should be pretty close to something like that.
For the headers it would be similar.
get all the header elements
iterate over each one and check that the text matches what you expect
I have an api that in the past developments would receive comma separated strings as valid input and used the following as the validator:
Joi.string()
But now I want to implement the same variable using array of strings as mentioned here https://github.com/glennjones/hapi-swagger/issues/119. So the new check would be:
Joi.array().items(Joi.string())
But I do not want to break the backward compatibility of the code. Is there a way to check both conditions for the variable?
I am a newbie to Joi, so any help or guidance would be appreciated. Thanks in advance.
Take a look at .alternatives().try() which supports multiple schemas for a single field.
For example:
Joi.alternatives().try(Joi.array().items(Joi.string()), Joi.string())
This will validate both arrays of strings and plain strings, however as I'm sure you know, you'll still need server side logic to check which format the value is so you can process it properly.
You can use alternatives.try or shorthand [schema1, schema2]
const Joi = require('joi');
const schema1 = {
param: Joi.alternatives().try(Joi.array().items(Joi.string()), Joi.string())
};
const result1 = Joi.validate({param: 'str1,str2'}, schema1);
console.log(result1.error); // null
const result2 = Joi.validate({param: ['str1', 'str2']}, schema1);
console.log(result2.error); // null
const schema2 = {
param: [Joi.array().items(Joi.string()), Joi.string()]
};
const result3 = Joi.validate({param: 'str1,str2'}, schema2);
console.log(result3.error); // null
const result4 = Joi.validate({param: ['str1', 'str2']}, schema2);
console.log(result4.error); // null
I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.