Break down a String in SWIFT - swift

Question

How can I break down a string by spaces? I’m used to taking data before/after a word or special character or a space. However I’m working on a decoder app where my string would look like:
This is a downloaded code that would be set to a string: “09627189762”
let str = downloadedCode
print(str) //09627189762
And I need it to format it here so that it can print as seen below:
let strA = //breakdown first 2 characters
let strB = //breakdown 3rd character etc
let strC = //do something
let strD = //do something
let strE = //do something
let strF = //do something
print(strA) //prints 09
print(strB) //prints 6
print(strC) //prints 27
print(strD) //prints 189
print(strE) //prints 7
print(strF) //prints 62
These numbers all have a different meaning that need coding, so I have to break the string down based on characters count ?

Answer 1

You can use a regular expression to split your input string into constant-length parts. In the example below, each (\\d{X}) part of the pattern means "match a sequence of X digits".
func splitString(_ str: String) -> [String] {
let regex = try! NSRegularExpression(pattern:
"(\\d{2})(\\d{1})(\\d{2})(\\d{3})(\\d{1})(\\d{2})")
var parts = [String]()
if let match = regex.firstMatch(in: str, range: NSMakeRange(0, str.count)) {
let nsstr = str as NSString
for i in 1 ..< match.numberOfRanges {
let part = nsstr.substring(with: match.range(at: i))
parts.append(part)
}
}
return parts
}
print(splitString("09627189762")) // ["09", "6", "27", "189", "7", "62"]