Needed Solve: Need to skip if column value coming as NULL from data source so that it won't overwrite the existing values.
Scenario : I'm processing CDC of a master table and referenced table. To get CDC changes from both tables based on master table doing a left join between master & reference CDC data.
In scenario where there is change happened in master table only, then in left join the reference data will come as nulls for all columns. In mapping dataflow the reference column values in target getting overridden as NULLS.
any suggestions how to skip the columns with null values in dataflow ?
The reason for left join is that, there is very high chance changes will happen only in table1 but not table 2.
Related
I have two KSQL Tables each having the same key. I am running the following query on them
CREATE TABLE TEMP1 AS SELECT
b.MFG_DATE,
b.rowtime as bd_rowtime,
s.rowtime as sd_rowtime,
b.EXPIRY_DATE as EXP_DATE,
b.BATCH_NO as BATCH_NO,
s.rowkey as SD_ID
FROM GR_SD4 s
INNER JOIN GR_BD4 b ON b.rowkey = s.rowkey;
PARTITION BY s.rowkey;
The resulting table does not get populated with data but when I run the select query separately it populates the data. I am confused on what could be the reason for the table not being populated with data.
The issue may be related to the PARTITION BY clause in your query. Since you are joining two tables, the resulting table will have a composite primary key (rowkey, s.rowkey). The PARTITION BY clause should be updated to reflect this, i.e. PARTITION BY rowkey, s.rowkey. This should ensure that the data is correctly partitioned and can be inserted into the table.
Any one knows best way for loading delta or CDC with using any tools
I got big table with billions of records and want to update or insert like Merge in Sql server or Oracle but in Amazon Redshift S3
Also we have loads of columns as can't compare all columns as well
e.g
TableA
Col1 Col2 Col3 ...
It has say already records
SO when inserting new records need to check that particular record is already existing if so no insert if not insert and if changed update record like that
I do have key id and date columns but as its got 200+ columns not easy to check all columns and taking much time
Many thanks in advance
There are set of values to update. Example: table t1 has column c1 which has to be updated from 1 to x. There are around 300 such sets available in a file and around 15 such tables with over 100k of records.
What is the optimal way of doing this?
Approaches I can think of are:
individual update statement for old with new value in all tables
programmatically read the file and create dynamic update statement
using merge into table syntax
In one of the tables the column is primary key with tables referencing them as foreign key
I have a schema with one table with the majority of data, customer, and three other tables with foreign key references to customer.entry_id which is a BIGSERIAL field. The three other tables are called location, devices and urls where we store various data related to a specific entry in the customer table.
I want to partition the customer table into monthly child tables, and have that part worked out; customer will stay as-is, each month will have a table customer_YYYY_MM that inherits from the master table with the right CHECK constraint and indexes will be created on each individual child table. Data will be moved to the correct child tables while the master table stays empty.
My question is about the other three tables, as I want to partition them as well. However, they have no date information (at all), only the reference to the primary key from the master table. How can I setup the constraints on these tables? Is it even meaningful or possible without date information?
My application logic knows where to insert all the data (it's fairly trivial), but I expect to be able to do simple SELECT queries without specifying which child tables to get it from. So this should work as you would expect from non-partitioned tables:
SELECT l.*
FROM customer c
JOIN location l USING entry_id
WHERE c.date_field > '2015-01-01'
I would partition them by the reference key. The foreign key is used in join conditions and is not usually subject to change so it fulfills the following important points:
Partition by the information that is used mostly in the WHERE clauses of the queries or other parts where partitioning can be used to filter out tables that don't need to be scanned. As one guide puts it:
The objective when defining partitions should be to allow as many queries as possible to fetch data from as few partitions as possible - ideally one.
Partition by information that is not going to be changed so that rows don't constantly need to be thrown from one subtable to another
This all depends of the size of the tables too of course. If the sizes stay small then there is no need to partition.
Read more about partitioning here.
Use views:
create view customer as
select * from customer_jan_15 union all
select * from customer_feb_15 union all
select * from customer_mar_15;
create view location as
select * from location_jan_15 union all
select * from location_feb_15 union all
select * from location_mar_15;
I know how partitioning in DB2 works but I am unaware about where this partition values exactly get stored. After writing a create partition query, for example:
CREATE TABLE orders(id INT, shipdate DATE, …)
PARTITION BY RANGE(shipdate)
(
STARTING '1/1/2006' ENDING '12/31/2006'
EVERY 3 MONTHS
)
after running the above query we know that partitions are created on order for every 3 month but when we run a select query the query engine refers this partitions. I am curious to know where this actually get stored, whether in the same table or DB2 has a different table where partition value for every table get stored.
Thanks,
table partitions in DB2 are stored in tablespaces.
For regular tables (if table partitioning is not used) table data is stored in a single tablespace (not considering LOBs).
For partitioned tables multiple tablespaces can used for its partitions.
This is achieved by the "" clause of the CREATE TABLE statement.
CREATE TABLE parttab
...
in TBSP1, TBSP2, TBSP3
In this example the first partition will be stored in TBSP1, the second in TBSP2, The third in TBSP3, the fourth in TBSP1 and so on.
Table partitions are named in DB2 - by default PART1 ..PARTn - and all these details can be looked up in the system catalog view SYSCAT.DATAPARTITIONS including the specified partition ranges.
See also http://www-01.ibm.com/support/knowledgecenter/SSEPGG_10.5.0/com.ibm.db2.luw.sql.ref.doc/doc/r0021353.html?cp=SSEPGG_10.5.0%2F2-12-8-27&lang=en
The column used as partitioning key can be looked up in syscat.datapartitionexpression.
There is also a long syntax for creating partitioned tables where partition names can be explizitly specified as well as the tablespace where the partitions will get stored.
For applications partitioned tables look like a single normal table.
Partitions can be detached from a partitioned table. In this case a partition is "disconnected" from the partitioned table and converted to a table without moving the data (or vice versa).
best regards
Michael
After a bit of research I finally figure it out and want to share this information with others, I hope it may come useful to others.
How to see this key values ? => For LUW (Linux/Unix/Windows) you can see the keys in the Table Object Editor or the Object Viewer Script tab. For z/OS there is an Object Viewer tab called "Limit Keys". I've opened issue TDB-885 to create an Object Viewer tab for LUW tables.
A simple query to check this values:
SELECT * FROM SYSCAT.DATAPARTITIONS
WHERE TABSCHEMA = ? AND TABNAME = ?
ORDER BY SEQNO
reference: http://www-01.ibm.com/support/knowledgecenter/SSEPGG_9.5.0/com.ibm.db2.luw.sql.ref.doc/doc/r0021353.html?lang=en
DB2 will create separate Physical Locations for each partition. So each partition will have its own Table-space. When you SELECT on this partitioned Table your SQL may directly go to a single partition or it may span across many depending on how your SQL is. Also, this may allow your SQL to run in parallel i.e. many TS can be accessed concurrently to speed up the SELECT.