I've an Entity "Invoice" and this one has a many-to-one relationship to Customer-Entity. This Customer-Entity is also used from other Entities for Hibernate Search and so there are many Hibernate Search annotations. For Invoice HS-Index I just want to have the Customer.id in the Invoice index and no other property of Customer.
How is this possible, because in the documentation I've found nothing specific about it.
In recent versions of Hibernate Search, you would simply use #IndexedEmbedded(includePaths = "id").
Hibernate Search 3.4 is very old, though (9 years old), and is missing many features. I'd recommend you upgrade since you're very likely to hit bugs that will never be solved in this version.
If you really have to stick with 3.4, I believe your only solution will be writing a custom bridge:
public class CustomerIdBridge implements StringBridge {
public String objectToString(Object object) {
Customer customer = (Customer) object;
if ( customer == null ) {
return null;
}
Object id = customer.getId();
return id == null ? null : id.toString();
}
}
Then apply the bridge like this:
#ManyToOne(...)
#Field(bridge = #FieldBridge(impl = CustomerIdBridge.class))
private Customer customer;
The resulting field will simply be named "customer" (same name as your property).
See here for more information about bridges in Hibernate Search 3.4.2.
Related
I'm using GORM for MongoDB in my Grails 3 web-app to manage read/writes from DB.
I have the following 2 domain classes:
class Company {
String id
}
class Team {
String id
Company company
}
For teams, their company is saved on DB as String, and with GORM I can simply use team.company to get an instance of Company domain class.
However, I need to override the getter for company, and I need the raw value for company id (as stored on DB), without GORM getting in the way and performing its magic.
Is there a way to get the raw String value?
Any help is welcome! Thanks in advance
Update (May 27)
Investigating #TaiwaneseDavidCheng suggestion, I updated my code to
class Company {
String id
}
class Team {
String id
Company company
String companyId
static mapping = {
company attr: "company" // optional
companyId attr: "company", insertable: false, updateable: false
}
}
Please note that I'm using GORM for MongoDB, which (citing the manual) tries to be as compatible as possible with GORM for Hibernate, but requires a slightly different implementation.
However I found out (by trial&error) that GORM for MongoDB doesn't support a similar solution, as it seems only one property at a time can be mapped to a MongoDB document property.
In particular the last property in alphabetical order wins, e.g. companyId in my example.
I figured out a way to make the whole thing work, I'm posting my own answer below.
given a non-insertable non-updateable column "companyId" in domain class
class Company {
String id
}
class Team {
String id
Company company
Long companyId
static mapping = {
company column:"companyId"
companyId column:"companyId",insertable: false,updateable: false
}
}
(Follows the edit to my question above)
I defined a custom mapping, and made use of Grails transients by also defining custom getter and setter for team's company.
class Company {
String id
}
class Team {
String id
Company company
String companyId
static mapping = {
companyId attr: "company" // match against MongoDB property
}
static transients = [ 'company' ] // non-persistent property
Company getCompany() {
return Company.get(companyId)
}
void setCompany(Company company) {
companyId = company.id
}
}
I'm trying to implement a rest api using RepositoryRestResource and RestTemplate
It all works rather well, except for loading #DBRef's
Consider this data model:
public class Order
{
#Id
String id;
#DBRef
Customer customer;
... other stuff
}
public class Customer
{
#Id
String id;
String name;
...
}
And the following repository (similar one for customer)
#RepositoryRestResource(excerptProjection = OrderSummary.class)
public interface OrderRestRepository extends MongoRepositor<Order,String>{}
The rest api returns the following JSON:
{
"id" : 4,
**other stuff**,
"_links" : {
"self" : {
"href" : "http://localhost:12345/api/orders/4"
},
"customer" : {
"href" : "http://localhost:12345/api/orders/4/customer"
}
}
}
Which if loaded correctly by the resttemplate will create a new Order instance with customer = null
Is it possible to eagerly resolve the customer on the repository end and embed the JSON?
Eagerly resolving dependent entities in this case will raise most probably N+1 database access problem.
I don't think there is a way to do that using default Spring Data REST/Mongo repositories implementation.
Here are some alternatives:
Construct an own custom #RestController method that would access the database and construct desired output
Use Projections to populate fields from related collection, e.g.
#Projection(name = "main", types = Order.class)
public interface OrderProjection {
...
// either
#Value("#{customerRepository.findById(target.customerId)}")
Customer getCustomer();
// or
#Value("#{customerService.getById(target.customerId)}")
Customer getCustomer();
// or
CustomerProjection getCustomer();
}
#Projection(name = "main", types = Customer.class)
public interface CustomerProjection {
...
}
The customerService.getById can employ caching (e.g. using Spring #Cachable annotation) to mitigate the performance penalty of accessing the database additionally for each result set record.
Add redundancy to your data model and store copies of the Customer object fields in the Order collection on creation/update.
This kind of problem arises, in my opinion, because MongoDB doesn't support joining different document collections very well (its "$lookup" operator has significant limitations in comparison to the common SQL JOINs).
MongoDB docs also do not recommend using #DBRef fields unless joining collections hosted in distinct servers:
Unless you have a compelling reason to use DBRefs, use manual references instead.
Here's also a similar question.
I have a REST interface for a datamodel that has several one-to-many and many-to-many relationships between entities. While many-to-many relationships seem easy to manage statelessly, I'm having trouble with one-to-many. Consider the following one-to-many relationship:
Employee:
#ManyToOne
#JoinColumn(name = "Company_id")
private Company company;
Company:
#OneToMany(mappedBy = "company", cascade = CascadeType.ALL, orphanRemoval=true)
public Set<Employee> employees = new HashSet<Employee>();
When a company is updated, its employee collection may have been updated as well (employees removed or added) but since the REST interface only allows updating the company as a whole, I cannot explicitly delete or add employees.
Simply replacing the collection does not work, but I found that this seems to work:
public void setEmployees(Set<Employee> employee) {
this.employees.clear(); // magic happens here?
this.employees.addAll(employees);
for (Iterator<Employee> iterator = employees.iterator(); iterator.hasNext();) {
Employee employee = (Employee) iterator.next();
employee.setCompany(this);
}
}
Is this the way it should be done, or is there a better way?
EDIT: In fact the above does not work! It appears to work at first, but then it will break with:
Exception in thread "main" java.lang.IllegalStateException: An entity copy was already assigned to a different entity.
I assume this happens because the db already contains a set of employees and if any of the "old" employees are also part of the replacement set, they collide with the ones in the database.
So what is the right way to replace the set?
First make sure equals is implemented properly. As per hibernate spec: http://docs.jboss.org/hibernate/orm/4.1/manual/en-US/html/ch04.html#persistent-classes-equalshashcode
I had a similar problem doing a merge. Essentially I had to fetch the existing employees associated with the company. I had to merge any changes to existing employees, and then add any new employees.
Query query = em.createQuery("select e from Employee e where e.company = '" + company.getId() + "'");
Collection<Employee> existingEmployees = new LinkedList<Employee>();
try{
Iterables.addAll(existingEmployees, (Collection<Employee>) query.getResultList());
}
catch(NoResultException nre){
//No results
}
for(Employee existingEmployee : existingEmployees){
for(Employee employee : company.getEmployees()){
if(existingEmployee.name().equals(employee.name())){
employee.setId(existingEmployee.getId());
}
employee.setCompany(company);
}
}
i think you have no better choice then to replace the existing collection and simply set the new one provided by the REST response.
I am using JPA in my application. In one of the table, I have not used primary key (I know its a bad design).
Now the generated entity is as mentioned below :
#Entity
#Table(name="INTI_SCHEME_TOKEN")
public class IntiSchemeToken implements Serializable {
private static final long serialVersionUID = 1L;
#Column(name="CREATED_BY")
private String createdBy;
#Temporal( TemporalType.DATE)
#Column(name="CREATED_ON")
private Date createdOn;
#Column(name="SCH_ID")
private BigDecimal schId;
#Column(name="TOKEN_ID")
private BigDecimal tokenId;
public IntiSchemeToken() {
}
public String getCreatedBy() {
return this.createdBy;
}
public void setCreatedBy(String createdBy) {
this.createdBy = createdBy;
}
public Date getCreatedOn() {
return this.createdOn;
}
public void setCreatedOn(Date createdOn) {
this.createdOn = createdOn;
}
public BigDecimal getSchId() {
return this.schId;
}
public void setSchId(BigDecimal schId) {
this.schId = schId;
}
public BigDecimal getTokenId() {
return this.tokenId;
}
public void setTokenId(BigDecimal tokenId) {
this.tokenId = tokenId;
}
}
Here In my project, eclipse IDE shows ERROR mark(RED colored cross) on this class and the error is "The entity has no primary key attribute defined".
Can anyone tell me, How to create an entity without primary key ?
Thanks.
You can't. An entity MUST have a unique, immutable ID. It doesn't have to be defined as a primary key in the database, but the field or set of fields must uniquely identify the row, and its value may not change.
So, if one field in your entity, or one set of fields in your entity, satisfies these criteria, make it (or them) the ID of the entity. For example, if there is no way that a user can create two instances in the same day, you could make [createdOn, createdBy] the ID of the entity.
Of course this is a bad solution, and you should really change your schema and add an autogenerated, single-column ID in the entity.
If your Primary Key(PK) is a managed super class which is inherited in an entity class then you will have to include the mapped super class name in the persistence.xml file.
Look at the bug report:
https://bugs.eclipse.org/bugs/show_bug.cgi?id=361042
If you need to define a class without primary key, then you should mark that class as an Embeddable class. Otherwise you should give the primary key for all entities you are defining.
You can turn off (change) validation that was added.
Go to workspace preferences 'Java Persistence->JPA->Errors/Warnings' next 'Type' and change 'Entity has no primary key' to 'Warnning'.
In addition to http://en.wikibooks.org/wiki/Java_Persistence/Identity_and_Sequencing#No_Primary_Key you can use some build-in columns like ROWID in Oracle:
Oracle legacy table without good PK: How to Hibernate?
but with care:
http://www.orafaq.com/wiki/ROWID
Entity frameworks doesn't work for all kind of data (like statistical data which was used for analysis not for querying).
Another solution without Hibernate
If
- you don't have PK on the table
- there is a logical combination of columns that could be PK (not necessary if you can use some kind of rowid)
-- but some of the columns are NULLable so you really can't create PK because of DB limitation
- and you can't modify the table structure (would break insert/select statements with no explicitly listed columns at legacy code)
then you can try the following trick
- create view at database with virtual column that has value of concatenated logical key columns ('A='||a||'B='||'C='c..) or rowid
- create your JPA entity class by this view
- mark the virtual column with #Id annotation
That's it. Update/delete data operations are also possible (not insert) but I wouldn't use them if the virtual key column is not made of rowid (to avoid full scan searches by the DB table)
P.S. The same idea is partly described at the linked question.
You need to create primary key ,If not found any eligible field then create auto increment Id.
CREATE TABLE fin_home_loan (
ID int NOT NULL AUTO_INCREMENT,
PRIMARY KEY (ID));
Just add fake id field.
In Postgres:
#Id
#Column(name="ctid")
String id;
In Oracle:
#Id
#Column(name="ROWID")
String rowid;
I am trying to achieve the following using Entity framework 4.0 and self-tracking entities:
1) The client application request a book form the server by providing an ISBN number
2) The server performs a query on its database to see if the book is already present
3a) If the book is in the database, it returns it.
3b) If the book is not in the database, it will query Amazon for info, extract the required attributes, create a new book, store it in the database, and return it to the client
Now, 3b) is where the problems are... I can't find any information on how I can create an entity object (a book) on the server side, add it to the context and store it in the database. I have tried all sorts of things:
public class BookBrowserService : IBookBrowserService {
public Book GetBook(string ISBN) {
using (var ctx = new BookBrowserModelContainer()) {
Book book = ctx.Books.Where(b => b.ISBN == ISBN).SingleOrDefault();
if (book == null) {
book = new Book();
book.ISBN = ISBN; // This is the key
book.Title = "This title would be retrieved from Amazon";
Author author = new Author();
author.Name = "The author's name would be retrieved from Amazon";
book.Authors.Add(author);
ctx.Books.AddObject(book);
ctx.SaveChanges(); // This one always throws an exception...
}
return book;
}
}
}
Could anyone tell me what I am doing wrong?
It looks like the problem is related to the EDMX model.
I have a Book entity and an Author entity, with a many-to-many relationship.
The Book entity's Key is ISBN, which is a string of Max length 13.
StoreGeneratedPattern is set to None.
The Author entity's Key is Id, which is a Guid.
StoreGeneratedPattern is Identity.
The exception message is:
"Cannot insert the value NULL into column 'Id', table 'BookBrowser.dbo.Authors'; column does not allow nulls. INSERT fails. The statement has been terminated. "
But since StoreGeneratedPattern is set to Identity, shouldn't an Id value be created automatically?
Thanks,
Peter
It looks that the problem was that I used a Guid as Key in combination with StoreGeneratedPattern = Identity.
When I set StoreGeneratedPattern to None and create my own Guid using Id = Guid.NewGuid(), the problem is gone.
Apparently, the SQL server cannot generate Guids...
you can use StoreGeneratedPattern=Identity, but generated sql script based on your edmx doesn`t contain newid() in describing primary key(GUID). you can do this manually in generated sql script. 'BookId uniqueidentifier NOT NULL
DEFAULT newid()'. So id value will create GUID automatically.