PerformSegue from long press on a a custom UiTableViewCell - swift

Question

maybe the question has been asked several times, but can't find it.
I'm a newbie.
I have a UITableView with a custom UITableViewCell.
in the cell there are 3 different labels.
I added the gesture recognizer on the custom cell, so that if long press is done on a label :
- label 1 should show another UiViewController
- label 2 should do a call
- label 3 should create a mail
for labels 2 and 3 i had no problem
but how to perform the segue to open the view controller ?
This is the storyboard
This is the custom tableviewcell
import UIKit
import MessageUI
class OfficeCell: UITableViewCell, MFMailComposeViewControllerDelegate {
#IBOutlet weak var lbOffice: UILabel!
#IBOutlet weak var lbAddress: UILabel!
#IBOutlet weak var lbPhone: UILabel!
#IBOutlet weak var lbMail: UILabel!
override func awakeFromNib() {
super.awakeFromNib()
// Initialization code
}
override func setSelected(_ selected: Bool, animated: Bool) {
super.setSelected(selected, animated: animated)
self.setupLabelTap()
// Configure the view for the selected state
}
func setupLabelTap() {
let lbAddressTap = UILongPressGestureRecognizer(target: self, action: #selector(self.longPressReconizer(_:)))
self.lbAddress.isUserInteractionEnabled = true
self.lbAddress.addGestureRecognizer(lbAddressTap)
let lbAddressTap2 = UILongPressGestureRecognizer(target: self, action: #selector(self.longPressReconizer(_:)))
self.lbMail.isUserInteractionEnabled = true
self.lbMail.addGestureRecognizer(lbAddressTap2)
let lbAddressTap3 = UILongPressGestureRecognizer(target: self, action: #selector(self.longPressReconizer(_:)))
self.lbPhone.isUserInteractionEnabled = true
self.lbPhone.addGestureRecognizer(lbAddressTap3)
}
#objc func longPressReconizer(_ sender: UITapGestureRecognizer) {
print("labelTapped")
let etichetta :UILabel = sender.view as! UILabel
print (etichetta.text!)
switch etichetta.tag {
case 0:
self.performSegue(withIdentifier: "moveToMaps", sender: self)
case 1:
let telNumber = etichetta.text!.replacingOccurrences(of: " ", with: "")
if let phoneCallURL = URL(string: "telprompt://\(telNumber)") {
let application:UIApplication = UIApplication.shared
if (application.canOpenURL(phoneCallURL)) {
application.open(phoneCallURL, options: [:], completionHandler: nil)
}
}
case 2:
if MFMailComposeViewController.canSendMail() {
let mail = MFMailComposeViewController()
mail.mailComposeDelegate = self
mail.setToRecipients([etichetta.text!])
mail.setSubject("Informazioni")
self.window?.rootViewController?.present(mail, animated: true)
} else {
// show failure alert
}
default:
print("default")
}
}
func mailComposeController(_ controller:MFMailComposeViewController, didFinishWith result: MFMailComposeResult, error: Error?) {
controller.dismiss(animated: true)
}
}
but Xcode give me this error
Value of type 'OfficeCell' has no member 'performSegue'
on
self.performSegue(withIdentifier: "moveToMaps", sender: self)
how to achieve what i need ?
Thanks in advance
Fabrizio

Answer 1

you need to implement delegate and perform segue from main class because cell class can't perform segue ... in storyBoard attach "moveToMaps" segue from main controller
protocol CellDelegate {
func didTapAddressButton()
}
class OfficeCell: UITableViewCell, MFMailComposeViewControllerDelegate {
var delegate: CellDelegate?
}
In your main View controller class
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "OfficeCell", for: indexPath) as! OfficeCell
cell.delegate = self
return cell
}
extension MainController: CellDelegate {
func didTapAddressButton(){
self.performSegue(withIdentifier: "moveToMaps", sender: self)
}
}