I have what I think it's a simple question.
I have a file named like this: 'prec/CHIRPS/P_CHIRPS.v2.0_mm-day-1_daily_2020.01.01.tif' and you can see it has a date within.
I've used successfully the package datefinder to extract the date from that string, but now what I want to do it's actually get the format from which datefinder read that date. That means that I want an output to be '%Y.%m%.d%' so I can use it to write a file with that same date format.
This is for example to be able to use whichever format of date and whichever file name I have, extract both the date and its format, and finally rewrite something like 'this is just an example of the file name with the date 2020.01.01'.
Thanks!!
Related
I'm trying to get DAYID as string in format YYYYMMDD, however its not working correctly.
I have a timestamp field, I take first 10 characters and convert it into date (working correctly)
toDate(substring(EventTimestamp,1,10))
-- 2021-03-24
However when I try to convert to string using below expression, I;m getting wrong answer. I;m getting the Day as 83.
toString(toDate(substring(EventTimestamp,1,10)),'YYYYMMDD')
--20210383
Date format characters are case-sensitive as per this answer here, so use yyyyMMdd instead.
An example using formatDateTime:
#formatDateTime(utcnow(), 'yyyyMMdd')
I have a .csv or .txt file which contains a date/timestamp field.
It looks like 'DD/MM/YYYY HH:MM:SS' in the CSV file. When I load this file is from a txt instead of .csv I can see there is trailing fractional seconds that .csv file isn't displaying.
I want the field to be read in as a date/time field 'DD/MM/YYYY HH:MM:SS' (two spaces between date & time) but cant find the correct format to used.
I'm trying to format this field into a usable format and have tried multiple format types, such as DATETIME19., ANYDTM etc, and I have also tried the picture format < https://communities.sas.com/t5/SAS-Data-Management/Timestamp-format-of-YYYY-MM-DD-HH-MM-SS/m-p/314667#M8994>
I currently have the field read in as a character but cant slice the data. Data below is to shown as an example, I'm reading this is from a text file currently.
DATA = '2020-08-24 10:49:17.8653230'
DATA ENTITY;
INFILE ENT
DELIMITER='09'x
DSD
FIRSTOBS=2
TRUNCOVER;
FORMAT CreatedOn $19.;
INPUT CreatedOn $;
RUN;
OUTPUT = '2020-08-24 10:49:17'
I've looked through a lot of online resources and must be missing something as I cant make anything I've tried to work.
I want the fields to be recognized as a date&time field with the DD/MM/YYYY HH:MM:SS format instead of a character field.
I'm running base SAS 9.4.2
Thanks in advance!
Imports fine for me using anydtdtm.
data demo;
example_date = '2020-08-24 10:49:17.8653230';
want = input(example_date, anydtdtm.);
format want datetime22.;
run;
proc print;run;
I'm trying to convert, in a RPG program, a date from a file (it's from the DSPJRN command, so the field si 6 numeric, in JOB format).
I want to use it as a date in my program, but I can't achieve it correctly.
I have tried to describe a field with type "D": date, keyword datfmt(*job) to convert the value from the file, but datfmt(*job) is incorrect (error RNF0612)
I have tried to retrieve the job Date format from a CLP program with RTVJOBA DATFMT(&FMT), and use the variable in RPG to convert the date like this
eval ztJODATE = %date(JODATE:FMT)
but it doesn't compile : error RNF0606 . I think that I can't use a variable for the format in the %date built-in function.
Is this a way to do what I want, or am I forced to transform the date value in SQL before using its value in RPG?
PS: I don't want to hardcode the format in my RPG program!
You can specify *JOBRUN for %DATE.
eval ztJODATE = %date(JODATE:*JOBRUN)
Note that RPG retrieves the job date format during initialization of the module, so if you change the job date format while the program is running, RPG will not understand the date.
Rather than using DSPJRN to an outfile, the recommended way to retrieve and process journal entries would be to use one of the programatic interfaces provided by IBM i.
Retrieve Journal Entries (QjoRetrieveJournalEntries) API
QSYS2.DISPLAY_JOURNAL() stored procedure
You could also use a *TYPE3 or higher format for the output file. Rather than the separate job formatted data & time fields, there's a single char(26) system timestamp field.
Having said that, there is a Convert Date and Time Format (QWCCVTDT) API that accepts '*JOB' as an input format specifier..
At the moment I am using xlsread to open a set of data that I have in excel with given timestamps. But when these values are placed in matlab it changes the formatting of the timestamp.
In excel it is:
dd/mm/yyyy HH:MM
but when it puts it into matlab it changes it to
mm/dd/yyyy HH:MM
which ruins my other code. I have tried using formatIn and specifying it, but then it returns an error if no value for midnight is given.
Any help would be appreciated.
You can use datenum and datestr to convert the format to what you want. In the following example I'm assuming your timestamps are contained in a cell array of strings, but it also works if it's a char matrix:
>> timestamps = {'08/25/2014 13:14'; '08/26/2014 14:15'} %// mm/dd/yyyy HH:MM
>> result = datestr(datenum(timestamps, 'mm/dd/yyyy HH:MM'), 'dd/mm/yyyy HH:MM')
result =
25/08/2014 13:14
26/08/2014 14:15
What Luis recommended should help you to get any format that you like. However there is something important to realize here:
Excel does not 'have' the date in your format. It has the date stored as a number like 123546.123 and presents it to you in a certain way.
If you want to get the date in exactly the way that excel presents it, the trick is to avoid importing the relevant column as a date, but just import it as text instead.
How to do this depends on your import method, but it should not be very hard.
I'm outputting to CSV and I'd like my dates in ISO8601 format, such as 2014-04-02T19:21:36.292Z, but I keep getting dates like Mar 27 2014 17:56:33 in my csv.
I'm fine to create a second intermediate string variable to do the formatting, but it yields the same result.
I see that there's a "sprintf" function in Logstash, but it seems you can do EITHER variable references OR date formats (which I assume will get the current system date time), but I don't think you can do both. I other words, I don't think it lets you apply a date format to an existing date variable, or if it does I'm not sure what the syntax would be.
Plenty of false hits on Google and stack, but all are about parsing.
Ironically stdout happens to output in the format I want, using stdout { debug => true codec => "rubydebug"}. Maybe that could somehow help in my case, not sure? Although other folks might want some other arbitrary format.
Try this one. Add a new "date" field then output to csv.
filter {
ruby {
code => '
require "time"
event["date"] = Time.parse(event["#timestamp"].to_s).iso8601;
'
}
}