How to fetch value from inner object in mongo query result - mongodb

Question

I'm new to mongodb.
I have this object in my collection:
{
"_id" : ObjectId("5b549be38d9f1c00160117d3"),
"name" : "Name of object",
"a" : {
"b" : {
"c" : 100
}
}
}
What interests me is the 100 value, I want to fetch it from the object.
When I query the collection like this:
db.getCollection('myCollection').find({}, {'name':1, 'a.b.c':1})
I only get the same object with the inner objects.
Is there a way to query it so that I will get a result like this:
{"Name": "Name of object", "c":100}

Answer 1

By using Mongo aggregate query you can get the result. In $project stage of Mongo aggregate query you can add the conditions as per requirement.
Please try this query, might you will get the result:
db.myCollection.aggregate({
$project: {
"name": "$name",
"c": "$a.b.c",
_id: 0
}
})

Answer 2

As suggested by #Mayuri, You can achieve this by using .aggregate() but if you wanted to look at difference between $project in aggregation (Vs) projection in .find(), check out :
So one first thing with $project is it is much more powerful & can accept a lot more features that are helpful to transform the fields. But projection in .find() is pretty straight forward that can accept only few things : projection i.e; value to a field in projection can be one of these :
1 or true to include the field in the return documents.
0 or false to exclude the field.
Projection Operators : $, $elemMatch, $slice, $meta
Actual Issue :
In your query when you're doing 'a.b.c':1 in projection it means you're returning c field in the output, As field c is nested in b & a the output structure doesn't change & you'll be getting the c value under the same structure, but if you use aggregation { $project: { "c": "$a.b.c" } } it means you're assigning value of "$a.b.c" to a field named c. How ? : So when $ is used against a field in aggregation it will access field's value, which helps for assignment.