Returns a Future<Dynamic> instead of Bool - flutter

Question

I want to return a bool in this method but it return a Future
#override
Widget build(BuildContext context) {
return Scaffold(
body: Stack(
children: <Widget>[
Container(
padding: EdgeInsets.only(left: 0, right: 0, top: 110, bottom: 5),
child: SingleChildScrollView(
child: Column(
children: <Widget>[
QuestionCards(),
cla().then((value) => { //this can't be add like this
YoutubeViewer(
videoId: 'hVQUbKs6qN8', topic: 'topic1'),
}
)
],
).
),
],
),
);
}
Future<bool> cla() async {
bool d = false;
try {
final result = await InternetAddress.lookup('google.com');
if (result.isNotEmpty && result[0].rawAddress.isNotEmpty) {
print('connected');
return Future<bool>.value(true);
}
} on SocketException catch (_) {
print('not connected');
return Future<bool>.value(false);
}
}
If someone can tell me that what need to be changed in this
It would be really helpful
Thank you

Answer 1

Return bool using Future object
return Future<bool>.value(true);
and modify method like
Future<bool> cla() async{
Use like:
cla().then((value) {
// value will provide you true or false
});

Answer 2

Future<bool> cla() async {
bool d=false;
try {
final result = await InternetAddress.lookup('google.com');
if (result.isNotEmpty && result[0].rawAddress.isNotEmpty) {
print('connected');
d= true;
}
} on SocketException catch (_) {
print('not connected');
d= false;
}
return d;
}
#override
void initState() {
super.initState();
// calling cla function
setState(() async {
var value = await getWeather();
if(value){
...
}
});
}
The observation you found is expected. Since the operation inside cla() function is async and the method is marked as async to return the future result. So you. will get future and to get the result form future you have to call await on it as shown above.

Answer 3

Future<bool> cla() async{
// function body goes here..
}
you can explicitly define return type of the method.