rename batch files in folder using a textfile - sed

I have a folder of files that start with specific strings and would like to replace part of their strings using the corresponding column from textfile
Folder with files
ABC_S1_002.txt
ABC_S1_003.html
ABC_S1_007.png
NMC_D1_002.png
NMC_D2_003.html
And I have a text file that has the strings to be replaced as:
ABC ABC_newfiles
NMC NMC_extra
So the folder after renaming will be
ABC_newfiles_S1_002.txt
ABC_newfiles_S1_003.html
ABC_newfiles_S1_007.png
NMC_extra_D1_002.png
NMC_extra_D2_003.html
I tried file by file using mv
for f in ABC*; do mv "$f" "${f/ABC/ABC_newfiles}"; done
How can I read in the textfile that has the old strings in first column and replace that with new strings from second column? I tried
IFS=$'\n'; for i in $(cat file_rename);do oldName=$(echo $i | cut -d $'\t' -f1); newName=$(echo $i | cut -d $'\t' -f2); for f in oldName*; do mv "$f" "${f/oldName/newName}"; done ; done
Did not work though.

This might work for you (GNU parallel and rename):
parallel --colsep ' ' rename -n 's/{1}/{2}/' {1}* :::: textFile
This will list out the rename commands for each line in textFile.
Once the output has been checked, remove the -n option and run for real.
For a sed solution, try:
sed -E 's#(.*) (.*)#ls \1*| sed "h;s/\1/\2/;H;g;s/\\n/ /;s/^/echo mv /e"#e' testFile
Again, this will echo the mv commands out, once checked, remove echo and run for real.

Review the result of
sed -r 's#([^ ]*) (.*)#for f in \1*; do mv "$f" "${f/\1/\2}"; done#' textfile
When that looks well, you can copy paste the result or wrap it in source:
source <(sed -r 's#([^ ]*) (.*)#for f in \1*; do mv "$f" "${f/\1/\2}"; done#' textfile)

Related

Removing a specific line in bash with an exact string

I'm having trouble in getting sed to remove just the specific line I want. Let's say I have a file that looks like this:
testfile
testfile.txt
testfile2
Currently I'm using this to remove the line I want:
sed -i "/$1/d" file
The issue is that with this if I were to give testfile as input it would delete all three lines but I want it to only remove the first line. How do I do this?
With grep
grep -x -F -v -- "$1" file
# or
grep -xFv -- "$1" file
-F is for "fixed strings" -- turns off regex engine.
-x is to match entire line.
-v is for "everything but" the matched line(s).
-- to signal the end of options, in case $1 starts with a hyphen.
To save the file
grep -xFv -- "$1" file | sponge file # `moreutils` package
# or
tmp=$(mktemp)
grep -xFv -- "$1" file > "$tmp" && mv "$tmp" file
So match the whole line.
var=testfile
sed -i '/^'"$var"'$/d' file
# or with " quoting
sed -i "/^$var\$/d" file
You can learn regex with fun online with regex crosswords.

How to Find & Replace a String Within Files with Find / Grep / Sed

I have a folder of 500 *.INI files that I need to manually edit. Within each INI file, I have the line Source =. I would like that line to become Source = C:\software\{filename}.
For instance, a dx4.ini file would need to be fixed to become: Source = C:\software\dx4
Is there a quick way to do this with Find, Grep, or Sed functions?
You can try with sed
For example
Input file contents:
file.txt
Source =
some lines..
script:
newstring='Source = C:\software\dx4'
oldstring='Source ='
echo `sed "s/$oldstring/$newstring/g" file.txt` > file.txt
After running the above commands
output:
Source = C:\software\dx4
some lines..
If you want to edit a file in a script, I think ed is the way to go. Combined with a shell for loop:
for file in *.INI; do
base=$(basename "$file" .INI)
ed -s "$file" <<EOF
/^Source =/s/=/= C:\\\\software\\\\$base/
w
EOF
done
(This does assume that filenames will not have newlines or ampersands in their names)
With GNU awk for the 3rd arg to match(), gensub(), and "inplace" editing:
awk -i inplace '
match($0,/(.*Source = C:\\software\\){filename}(.*)/,a) {
fname = gensub(/\..*/,"",1,FILENAME)
$0 = a[1] fname a[2]
}
1' *.INI
The above assumes you're running in a UNIX environment though your use of the term folder instead of directory and that path starting with C: and containing backslashes makes me suspicious. If you're on Windows then save the part between the 2 's (exclusive) in a file named foo.awk and execute it as awk -i inplace foo.awk *.INI or however it is you normally execute commands like this in Windows.
find *.ini -type -f > stack
while read line
do
sed -i s"#Source =#Source = C:\\software\\dx4#" "${line}"
done < stack
Assuming that a} You have sed with "-i" (the insert flag, which AFAIK is not always portable) and b} sed doesn't crap itself about a double escape sequence, I think that will work.

Shell scripting Sed option

I need a help in the shell scripting processing the file. The script should read each file in the path and replace the string in each row.
It should read each line and replace the 7th column with XXXX mentioned in the sample output. Any help in appreciated.
Input file data
"2013-04-30"|"X"|"0000628"|"15000231"|"1999-12-05"|"ST"|"2455525445552000"|"1111-11-11"|75.00|"XXE11111"|"224425"
"2013-04-30"|"Y"|"0000928"|"95000232"|"1999-12-05"|"VT"|"2455525445552000"|"1111-11-11"|95.00|"VVE11111"|"224425"
output file
"2013-04-30"|"X"|"0000628"|"15000231"|"1999-12-05"|"ST"|"24555XXXXXXXXXX"|"1111-11-11"|75.00|"XXE11111"|"224425"
"2013-04-30"|"Y"|"0000928"|"95000232"|"1999-12-05"|"VT"|"24555XXXXXXXXXX"|"1111-11-11"|95.00|"VVE11111"|"224425"
Script I used to run but it is not editing the input file
FILES=/home/auto/*.txt
for f in $FILES
do
echo "Processing $f file..."
cat $f | awk 'BEGIN {FS="|"; OFS="|"} {$7=substr($7, 1, 6)"XXXXXXXXXX\"";print}'
done
but I can't edit the exiting file in the directory. I need to use the sed -i option but it's not working.
I tried using the script in below server but I am getting the following error.
SunOS 5.10 Generic January 2005
echo "hello"
FILES=/export/home/*.txt
for f in $FILES
do
echo "Processing $f file..."
sed -i -r 's/"([^"]{6})[^"]*"/"\1XXXXXXXXXX"/6' "$f"
done
I get
sed: illegal option -- i
Using GNU sed with -i optoin
sed -i -r 's/"([^"]{5})[^"]*"/"\1XXXXXXXXXX"/5' file
"2013-04-30"|"X"|"0000628"|"15000231"|"1999-12-05"|"ST"|"24555XXXXXXXXXX"|"1111-11-11"|75.00|"XXE11111"|"224425"
"2013-04-30"|"Y"|"0000928"|"95000232"|"1999-12-05"|"VT"|"24555XXXXXXXXXX"|"1111-11-11"|95.00|"VVE11111"|"224425"
if your awk is gnu awk 4.1.0, there is in-place option, read man/info page.
otherwise, you could do:
awk '..code..' inputfile > tmpfile && mv tmpfile inputfile
note, the cat is not necessary, could (should) be removed.
A little ugly but you can try something like this with sed
sed -i 's/\(\([^|]*|\)\{6\}\)\(.\{6\}\).\{11\}\(.*\)/\1\3XXXXXXXXXXX\4/' file
So with your existing script, it will be -
FILES=/home/auto/*.txt
for f in $FILES
do
echo "Processing $f file..."
sed -i 's/\(\([^|]*|\)\{6\}\)\(.\{6\}\).\{11\}\(.*\)/\1\3XXXXXXXXXXX\4/' "$f"
done

how to remove trailing line from every file with our renaming the fuel

Hi I use the following code to remove the trailing lines from a file. But is there anyway I can run this on 2000 files inside a folder with out renaming them ? thanx in advance
sed -e :a -e '/^\n*$/{$d;N;};/\n$/ba'
sed -i "" -e :a -e '/^\n*$/{$d;N;};/\n$/ba' YourFile
if it is in same folder with a pattern to select id like *.txt, replace YourFile by the shell pattern, if other selection pass each file name via a pre selection like find or a while read from a stream/file input
You can use find to list the files that you need, and then run sed on each on them. This version uses the -i option to modify the files in place:
find . -name "*.txt" | xargs -I % sed -i -e :a -e '/^\n*$/{$d;N;};/\n$/ba' %

unix sed, replace field at a specific row and column in the same file

I have a text file with 4 columns delimited by comma.
As I am reading each record in a loop, I want to add a value to the 5th column depending on a condition.
So if I know the row number and column number, how can I use awk/sed commands to replace/set value at that particular field without using temporary files?
I want to update the file (directly) that I am reading from
inp.txt
a,b,c,d
e,f,g,h
i,j,k,l
Thanks,
-sri
I can't speak for sed, but the purpose of awk isn't to edit files in place but to write to stdout.
But anyway, here's a solution you don't need a loop for, pretending the condition is that the entry in column 4 is an h.
awk -F ',' '{ if ($4 == "h") print $0",z"; else print $0","}' inp.txt > out.txt
output:
a,b,c,d,
e,f,g,h,z
i,j,k,l,
You cannot directly edit the file with either awk or sed. Some versions of sed have an option (-i) that works with a temporary file and overwrites the original file, but it does not actually edit the file in place. This is not a big deal. Just do:
$ awk 'NR==5{ $(NF+1) = "new value"}1' OFS=, FS=, input-file > tmp.$$
$ mv tmp.$$ input-file
To add a new column to row 5 of input-file. If you wish, you can use ed to edit the file, but it makes more sense to use a temporary file. If you want to pretend that you aren't using a temporary file, and your sed supports -i, you can do the same thing with:
sed -i '5s/$/,new value/' input-file
Even though most utilitites do not allow in-place modification of the file, it is simple to use one of the following sh functions to emulate that behavior using temporary files:
edit() { local f=$1; shift; "$#" < $f > $f.$$ && mv $f.$$ $f; } # Break hard links
edit() { local f=$1; shift; "$#" < $f > $f.$$ && cat $f.$$ > $f && rm $f.$$; }
With either of these, you could use awk to give the appearance of editing files in-place using edit filename awk awk-cmds. The first version breaks hard links, but uses slightly less IO.
perl -i -F, -lane 'if($.==<row number>){$F[<column_number>-1]+=<add your stuff here>}print join(",",#F)' your_file
tested below:
>cat temp
b,c,d,g
r,g,d,s
execute for changing the 3rd column in second row:
>perl -i -F, -lane 'if($.==2){$F[2]=10}print join(",",#F)' temp
> cat temp
b,c,d,g
r,g,10,s
You mean like this?
this is the version don't using any temporary files.
[a#b ~]$ cat tmp | sed 's_^\(.*\),\(.*\),\(.*\),\(.*\)_\1,\2,\3,\4_g'
inp.txt
a,b,c,d
e,f,g,h
i,j,k,l
[a#b ~]$ cat tmp | sed 's_^\(.*\),\(.*\),\(.*\),\(.*\)_\1,sth,\3,\4_g'
inp.txt
a,sth,c,d
e,sth,g,h
i,sth,k,l
[a#b ~]$ sed -ie 's_^\(.*\),\(.*\),\(.*\),\(.*\)_\1,sth,\3,\4_g' tmp
[a#b ~]$ cat tmp
inp.txt
a,sth,c,d
e,sth,g,h
i,sth,k,l
Cheers,