Lets say I have a line #SYM
I need to replace it with all lines from file1.txt
Is it possible to do that with sed?
I have tried sed 's/#SYM/file1.txt/' updater
But that doesn't work, because I need to load file1.txt as string, and I do not know how to do that.
EDIT: I believe that there could be a way to do it in a shell script somehow.
EDIT2: I also just tried this:
#!/bin/bash
value=$(<tools/symlink)
sed -i 's/#SYM/$value/' META-INF/com/google/android/updater-script
Use r command:
sed -e '/#SYM/ {r tools/symlink' -e 'd}' META-INF/com/google/android/updater-script
/#SYM/ {r tools/symlink if a line contains #SYM, append the contents of tools/symlink
d} then delete the matching line
the two commands are separated using -e option because everything after r is considered as part of filename
Add the -i option once you are satisifed that it is working
Related
How can I add ",1" at the end of each of the lines using sed?
The file I am using is like this;
A
B
C
I tried this;
sed 's/$/,1/' alphabets.txt > alphabets1.txt
and got this;
A
,1
B
,1
C
,1
but what I want is this;
A,1
B,1
C,1
When I tried the best answer from "https://stackoverflow.com/questions/15978504/add-text-at-the-end-of-each-line", I got a blank page.
sed -n 's/$/,1/' alphabets.txt > alphabets2.txt
I found out that there's ^M at the end using cat -vt file. How can I delete it and change it to ",1"?
Mac sed is BSD sed. You may try this command on a file optionally ending with \r to remove \r and append 1 in the end:
sed -E $'s/\\\r?$/,1/'
A,1
B,1
C,1
Make sure you shell is bash while running this.
You may also use:
sed -E 's/'$'\r''?$/,1/' file
$'\r' is a BASH string to match \r and ? after this makes it optional.
Please note that this sed command will also run fine on gnu sed.
On a Unix system I am trying to add a new line in a file using sed or perl but it seems I am missing something.
Supposing my file has multiple lines of texts, always ending like this {TNG:}}${1:F01.
I am trying to find a to way to add a new line after the }$, in this way {1 should always start on a new line.
I tried it by escaping $ sign using this:
perl -e '$/ = "\${"; while (<>) { s/\$}\{$/}\n{/; print; }' but it does not work.
Any ideas will be appreciated.
give this a try:
sed 's/{TNG:}}\$/&\n/' file > newfile
The sed will by default use BRE, that is, the {}s are literal characters. But we must escape the $.
kent$ cat f
{TNG:}}${1:F01.
kent$ sed 's/{TNG:}}\$/&\n/' f
{TNG:}}$
{1:F01.
With perl:
$ cat input.txt
line 1 {TNG:}}${1:F01
line 2 {TNG:}}${1:F01
$ perl -pe 's/TNG:\}\}\$\K/\n/' input.txt
line 1 {TNG:}}$
{1:F01
line 2 {TNG:}}$
{1:F01
(Read up on the -p and -n options in perlrun and use them instead of trying to do what they do in a one-liner yourself)
I want to get the first line of a file that is not commented out with an hash, then append a line of text just after that line just before that line.
I managed to get the number of the line:
sed -n '/^\s*#/!{=;q}' file // prints 2
and also to insert text (specifying the line manually):
sed '2 a extralinecontent' file
I can't get them working together as a one liner or in a batch.
I tried command substitution (with $(command) and also with backticks) but I get an error from bash:
sed '$(sed -n '/^\s*#/!{=;q}' file) a extralinecontent' file
-bash: !{=: event not found
and also tried many other combinations, but no luck.
I'm using gnu-sed (via brew) on macOS.
This might work for you (GNU sed):
sed -e '/^\s*#/b;a extra line content' -e ':a;n;ba' file
Bail out of any lines beginning with a comment at the beginning of the file, append an extra line following the first line that is not a comment and keep fetching/printing all the remaining lines of the file.
Here's a way to do it with GNU sed without reading the file twice
$ cat ip.txt
#comment
foo baz good
123 456 7889
$ sed -e '0,/^\s*[^#[:space:]]/ {// a XYZ' -e '}' ip.txt
#comment
foo baz good
XYZ
123 456 7889
GNU sed allows first address to be 0 if the other address is regex, that way this will work even if first line matches the condition
/^\s*[^#[:space:]]/ as sed doesn't support possessive quantifier, need to ensure that the first character being matched by the character class isn't either a # or a whitespace character
// is a handy shortcut to repeat the last regex
a XYZ your required line to be appended (note that your question mentiones insert, so if you want that, use i instead of a)
I am having issues of editing huge C++ file where I am using sed to convert List(something) to List<something> why I am doing this because our List has been converted to template.
Command I have written in small shell file is like this
sed -i '/List/s/(/</g' $1
sed -i '/List/s/)/>/g' $1
But this command is converting the whole line associated with List to angular braces like,
some_Fun(List(something)) to some_Fun<List<something>>
I don't want sed to change some_Fun<> , sed should keep some_Fun() and change only List() to List<>.
You can use this sed:
sed 's/\(List\)(\([^)]*\))/\1<\2>/g' file
(OR)
sed 's/List(\([^)]*\))/List<\1>/g' file
I'm on Linux command line and I have file with
127.0.0.1
128.0.0.0
121.121.33.111
I want
127.0.0.1:80
128.0.0.0:80
121.121.33.111:80
I remember my colleagues were using sed for that, but after reading sed manual still not clear how to do it on command line?
You could try using something like:
sed -n 's/$/:80/' ips.txt > new-ips.txt
Provided that your file format is just as you have described in your question.
The s/// substitution command matches (finds) the end of each line in your file (using the $ character) and then appends (replaces) the :80 to the end of each line. The ips.txt file is your input file... and new-ips.txt is your newly-created file (the final result of your changes.)
Also, if you have a list of IP numbers that happen to have port numbers attached already, (as noted by Vlad and as given by aragaer,) you could try using something like:
sed '/:[0-9]*$/ ! s/$/:80/' ips.txt > new-ips.txt
So, for example, if your input file looked something like this (note the :80):
127.0.0.1
128.0.0.0:80
121.121.33.111
The final result would look something like this:
127.0.0.1:80
128.0.0.0:80
121.121.33.111:80
Concise version of the sed command:
sed -i s/$/:80/ file.txt
Explanation:
sed stream editor
-i in-place (edit file in place)
s substitution command
/replacement_from_reg_exp/replacement_to_text/ statement
$ matches the end of line (replacement_from_reg_exp)
:80 text you want to add at the end of every line (replacement_to_text)
file.txt the file name
How can this be achieved without modifying the original file?
If you want to leave the original file unchanged and have the results in another file, then give up -i option and add the redirection (>) to another file:
sed s/$/:80/ file.txt > another_file.txt
sed 's/.*/&:80/' abcd.txt >abcde.txt
If you'd like to add text at the end of each line in-place (in the same file), you can use -i parameter, for example:
sed -i'.bak' 's/$/:80/' foo.txt
However -i option is non-standard Unix extension and may not be available on all operating systems.
So you can consider using ex (which is equivalent to vi -e/vim -e):
ex +"%s/$/:80/g" -cwq foo.txt
which will add :80 to each line, but sometimes it can append it to blank lines.
So better method is to check if the line actually contain any number, and then append it, for example:
ex +"g/[0-9]/s/$/:80/g" -cwq foo.txt
If the file has more complex format, consider using proper regex, instead of [0-9].
You can also achieve this using the backreference technique
sed -i.bak 's/\(.*\)/\1:80/' foo.txt
You can also use with awk like this
awk '{print $0":80"}' foo.txt > tmp && mv tmp foo.txt
Using a text editor, check for ^M (control-M, or carriage return) at the end of each line. You will need to remove them first, then append the additional text at the end of the line.
sed -i 's|^M||g' ips.txt
sed -i 's|$|:80|g' ips.txt
sed -i 's/$/,/g' foo.txt
I do this quite often to add a comma to the end of an output so I can just easily copy and paste it into a Python(or your fav lang) array