I am trying to convert a double value to int and use it in the number of agents per arrival. I have a distribution but want it to round to the nearest integer. I looked up the anylogic math functions but the only one that makes sense is rint but that still returns a double.
you can do this:
(int) rint(yourVariable)
Another way is to use (int)floor(myDouble)) and (int)ceil(myDouble)) .
With these, you can decide if you want to round up or down (if the default rounding rules aren't to your liking)
Related
PureScript contains a method in the Integer library fromNumber.
Here is an example of how it might be used:
myInteger = fromMaybe 0 (fromNumber myNumber)
However the docs provide this puzzling explanation:
Creates an Int from a Number value. The number must already be an integer and fall within the valid range of values for the Int type otherwise Nothing is returned.
Basically, your number must already be an Integer to convert it to an integer.
Assuming your number is not already an integer, a reasonable use case, how would you convert it to a number?
If it's not already an integer, there is no one true way of converting it to an integer. You could round to the nearest integer, round up, round down, do banker's rounding, or some sort of crazy conversion scheme of your own.
The Data.Int module offers several functions for different conversion strategies, such as floor, ceil, and round.
I am trying to write a program in C to get the percent of even numbers in an array. I am thinking of writing it using int datatype. But some one mentioned to me using double will be easier. I don't understand that. Can anyone guide me with it?
What does double datatype return?
Can the return statement be given as return (double)? What will that give?
Can double convert a real number to a percent? Eg: 0.5 to 50.0
The int datatype is, as the name would suggest, integers (or whole numbers). So you cannot represent a decimal like 0.5. A double is decimal number. So you can hold numbers like 0.5. Common practice is to store your percentage as a simple decimal number like 0.5 (using the double type). Then when you need to display nicely as 50.0%, just multiply by 100 before displaying.
Here's a useful link on C's basic datatypes: http://www.tutorialspoint.com/ansi_c/c_basic_datatypes.htm
I want to use xor for my double numbers in matlab,but bitxor is only working for int numbers. Is there a function that could convert double to int in Matlab?
The functions You are looking for might be: int8(number), int16(number), uint32(number) Any of them will convert Double to an Integer, but You must pick the best one for the result You want to achieve. Remember that You cannot cast from Double to Integer without rounding the number.
If I understood You correcly, You could create a function that would simply remove the "comma" from the Double number by multiplying your starting value by 2^n and then casting it to Integer using any of the functions mentioned earlier, performing whatever you want and then returning comma to its original position by dividing the number by 2^n
Multiplying the starting value by 2^n is a hack that will decrease the rounding error.
The perfect value for n would be the number of digits after the comma if this number is relatively small.
Please also specify, why are You trying to do this? This doesn't seem to be the optimal solution.
You can just cast to an integer:
a = 1.003
int8(a)
ans =
1
That gives you an 8 bit signed integer, you can also get other size i.e. int16 or else unsigned i.e. uint8 depending on what you want to do
I need a variable a = 6700000^2 * (a - b) (2 + sinf(a)+ s inf(b)), where a and b are floats between -7 to 7. I need all the precision that floats can give me.
Which data type should a be? Is the sinf the proper function to get the best precision out of a and b? And should a and b be in radians or degrees?
Well I Made a mistake when I posted the expression, the correct expression is c=67000000^2*(a-b)(2+sinf(a)+sinf(b)) and my problem is with c ."a" and "b" are floats and they are passed to me as floats, they really are coordinates (latitude and longitude) so thats not my concern... My concern is when using sinf on them do I lose any precision? And which type should c be so I don't lose precision cause I'm using a long double variable d to store a sum of multiple different c variables and d is returned to me as being zero and it shouldn't (sould be about 1 or 2 )so I was gessing I was losing some precision when calculating the c parcels...I was using c as being a double...can it be that I am losing some precision when calculating c?
Thank you very much for your help.
I can't tell you whether float is good enough for your application. If you need more precision, use double, and then use sin() instead of sinf().
The standard trig functions take angles in radians, as you'll discover if you read the relevant documentation.
Instead of using float, you should use a double if you want no worries in regards to memory. Remember to then change sinf() to sin() and use radians.
If you want the best precision without rolling your own types, you should use double rather than float. In that case, you can just use sin(3). According to the man page, you should pass the argument in radians.
I have an issue with rounding the result of a calculation to two decimal places.
It is a financial calculation and when the result involves half a penny I would expect the number to be rounded up but it is in fact being rounded down.
To replicate the issue:
float raw = 16.695;
NSLog(#"All DP: %f",raw);
NSLog(#"2 DP: %.2f",raw);
Returns:
All DP: 16.695000
2 DP: 16.69
Whereas I would expect to see:
All DP: 16.695000
2 DP: 16.70
Can anyone advise if this is by design or if (most likely) I am missing something and if there is anything I can do to get around it. It is vital that it rounds up in this scenario.
Thanks in advance,
Oli
Don't use floats for financial calculations!
There are values that floats cannot represent exactly. 16.695 is one of them. When you try to store that value in a float, you actually get the closest representable value. When you perform a series of operations on a float, you can lose precision, and then you lose accuracy. This leads to losing money.
Use an actual currency type, use NSDecimalNumber, or do all your calculations with ints that count the smallest unit you care about (i.e., 1050 is $10.50 in whole cents, or $1.050 if you want fractions of pennies).
As far as I am aware the NSLog() function only takes formatting arguments and makes no attempt to round.
You may be use to using a printf() style function that does support rounding.
I suggest using one of the many functions in math.h to round your value before output and only rely on NSLog() for formatting.
After seeing the comments
Use the C standard function family round(). roundf() for float, round() for double, and roundl() for long double. You can then cast the result to the integer type of your choice
you could try this:
- (void)testNSlogMethod {
float value = 16.695; //--16.70
value = value *100;
int mulitpler = round(value);
NSLog(#"%.2f",mulitpler/100.0f);
}