Compare three enums in swift [duplicate] - swift

Question

Does anybody know of a shortcut to test whether three numbers are the same? I know this works:
if number1 == number2 && number2 == number3 {
}
But I would like something cleaner, such as;
if number1 == number2 == number3 {
}
It's quite important as I'm comparing a lot of different values.

Answer 1

You could use a set
if Set([number1, number2, number3]).count == 1 {
...
though I'd argue it isn't as transparent as multiple if clauses

Answer 2

You can use the power of tuples and the Transitive Property of Equality.
if (number1, number2) == (number2, number3) {
}
The clause of this IF is true only when number1 is equals to number2 AND number2 is equals to number3. It means that the 3 values must be equals.

Answer 3

You can add them in an array and use sets:
var someSet = NSSet(array: [2,2,2])
if someSet.count == 1 {
print("Same values")
}

Answer 4

Don't know of anything other than a Set, I'd suggest wrapping it in a function to make your intent clear. Something along these lines:
func allItemsEqual<T>(items:[T]) -> Bool {
guard items.count > 1 else { fatalError("Must have at least two objects to check for equality") }
return Set(items).count == 1
}
func allItemsEqual(items:T...) -> Bool {
return equal(items)
}
if allItemsEqual(2,3,2) {
// false
}
if allItemsEqual(2, 2, 2) {
// true
}
Beyond that, maybe you could get fancy with operator overloading?

Answer 5

Try this:
func areEqual<T: NumericType>(numbers: T...) -> Bool {
let num = numbers[0]
for number in numbers {
if number != num {
return false
}
}
return true
}
Where NumericType is defined in this post: What protocol should be adopted by a Type for a generic function to take any number type as an argument in Swift?
This will allow you to use the function for all number types
You just pass any number of numbers like:
//returns true
if areEqual(1, 1, 1) {
print("equal")
}